在MySQL中,你可以像这样插入多行:

INSERT INTO 'tablename' ('column1', 'column2') VALUES
    ('data1', 'data2'),
    ('data1', 'data2'),
    ('data1', 'data2'),
    ('data1', 'data2');

然而,当我尝试这样做时,我得到了一个错误。是否可以在SQLite数据库中一次插入多行?这样做的语法是什么?


当前回答

我有一个像下面这样的查询,但与ODBC驱动程序SQLite有一个错误“,”它说。 我运行vbscript在HTA (Html应用程序)。

    INSERT INTO evrak_ilac_iliskileri (evrak_id, ilac_id, 
baglayan_kullanici_id, tarih) VALUES (4150,762,1,datetime()),
(4150,9770,1,datetime()),(4150,6609,1,datetime()),(4150,3628,1,datetime()),
(4150,9422,1,datetime())

其他回答

你可以使用InsertHelper,它简单快捷

文档: http://developer.android.com/reference/android/database/DatabaseUtils.InsertHelper.html

教程: http://www.outofwhatbox.com/blog/2010/12/android-using-databaseutils-inserthelper-for-faster-insertions-into-sqlite-database/

编辑: 从API级别17开始,InsertHelper已弃用

我能够使查询动态。这是我的桌子:

创造可写的“tblPlanner”文本。

我得到所有的数据通过一个JSON,所以在得到一个NSArray内的所有东西后,我遵循这个:

    NSMutableString *query = [[NSMutableString alloc]init];
    for (int i = 0; i < arr.count; i++)
    {
        NSString *sqlQuery = nil;
        sqlQuery = [NSString stringWithFormat:@" ('%@', '%@', '%@', '%@', '%@', '%@', '%@', '%@'),",
                    [[arr objectAtIndex:i] objectForKey:@"plannerid"],
                    [[arr objectAtIndex:i] objectForKey:@"probid"],
                    [[arr objectAtIndex:i] objectForKey:@"userid"],
                    [[arr objectAtIndex:i] objectForKey:@"selectedtime"],
                    [[arr objectAtIndex:i] objectForKey:@"isLocal"],
                    [[arr objectAtIndex:i] objectForKey:@"subject"],
                    [[arr objectAtIndex:i] objectForKey:@"comment"],
                    [[NSUserDefaults standardUserDefaults] objectForKey:@"applicationid"]
                    ];
        [query appendString:sqlQuery];
    }
    // REMOVING LAST COMMA NOW
    [query deleteCharactersInRange:NSMakeRange([query length]-1, 1)];

    query = [NSString stringWithFormat:@"insert into tblPlanner (plannerid, probid, userid, selectedtime, isLocal, applicationid, subject, comment) values%@",query];

最后输出查询是这样的:

insert into tblPlanner (plannerid, probid, userid, selectedtime, isLocal, applicationid, subject, comment) values 
<append 1>
('pl1176428260', '', 'US32552', '2013-06-08 12:00:44 +0000', '0', 'subj', 'Hiss', 'ap19788'),
<append 2>
('pl2050411638', '', 'US32552', '2013-05-20 10:45:55 +0000', '0', 'TERI', 'Yahoooooooooo', 'ap19788'), 
<append 3>
('pl1828600651', '', 'US32552', '2013-05-21 11:33:33 +0000', '0', 'test', 'Yest', 'ap19788'),
<append 4>
('pl549085534', '', 'US32552', '2013-05-19 11:45:04 +0000', '0', 'subj', 'Comment', 'ap19788'), 
<append 5>
('pl665538927', '', 'US32552', '2013-05-29 11:45:41 +0000', '0', 'subj', '1234567890', 'ap19788'), 
<append 6>
('pl1969438050', '', 'US32552', '2013-06-01 12:00:18 +0000', '0', 'subj', 'Cmt', 'ap19788'),
<append 7>
('pl672204050', '', 'US55240280', '2013-05-23 12:15:58 +0000', '0', 'aassdd', 'Cmt', 'ap19788'), 
<append 8>
('pl1019026150', '', 'US32552', '2013-06-08 12:15:54 +0000', '0', 'exists', 'Cmt', 'ap19788'), 
<append 9>
('pl790670523', '', 'US55240280', '2013-05-26 12:30:21 +0000', '0', 'qwerty', 'Cmt', 'ap19788')

它在代码中也运行良好,我能够成功地在SQLite中保存所有内容。

在此之前,我使工会查询东西动态,但开始给一些语法错误。不管怎样,这对我来说很好。

Sqlite3不能在SQL中直接做到这一点,除非通过一个SELECT,虽然SELECT可以返回一个“行”表达式,但我知道没有办法让它返回一个假列。

但是,CLI可以做到:

.import FILE TABLE     Import data from FILE into TABLE
.separator STRING      Change separator used by output mode and .import

$ sqlite3 /tmp/test.db
SQLite version 3.5.9
Enter ".help" for instructions
sqlite> create table abc (a);
sqlite> .import /dev/tty abc
1
2
3
99
^D
sqlite> select * from abc;
1
2
3
99
sqlite> 

如果你在INSERT中使用了一个循环,而不是使用CLI .import命令,那么一定要遵循sqlite FAQ中的建议来提高INSERT速度:

By default, each INSERT statement is its own transaction. But if you surround multiple INSERT statements with BEGIN...COMMIT then all the inserts are grouped into a single transaction. The time needed to commit the transaction is amortized over all the enclosed insert statements and so the time per insert statement is greatly reduced. Another option is to run PRAGMA synchronous=OFF. This command will cause SQLite to not wait on data to reach the disk surface, which will make write operations appear to be much faster. But if you lose power in the middle of a transaction, your database file might go corrupt.

INSERT INTO TABLE_NAME 
            (DATA1, DATA2) 
VALUES      (VAL1, VAL2), 
            (VAL1, VAL2), 
            (VAL1, VAL2), 
            (VAL1, VAL2), 
            (VAL1, VAL2), 
            (VAL1, VAL2), 
            (VAL1, VAL2), 
            (VAL1, VAL2); 

如果你正在使用bash shell,你可以使用这个:

time bash -c $'
FILE=/dev/shm/test.db
sqlite3 $FILE "create table if not exists tab(id int);"
sqlite3 $FILE "insert into tab values (1),(2)"
for i in 1 2 3 4; do sqlite3 $FILE "INSERT INTO tab (id) select (a.id+b.id+c.id)*abs(random()%1e7) from tab a, tab b, tab c limit 5e5"; done; 
sqlite3 $FILE "select count(*) from tab;"'

或者如果你在sqlite CLI中,那么你需要这样做:

create table if not exists tab(id int);"
insert into tab values (1),(2);
INSERT INTO tab (id) select (a.id+b.id+c.id)*abs(random()%1e7) from tab a, tab b, tab c limit 5e5;
INSERT INTO tab (id) select (a.id+b.id+c.id)*abs(random()%1e7) from tab a, tab b, tab c limit 5e5;
INSERT INTO tab (id) select (a.id+b.id+c.id)*abs(random()%1e7) from tab a, tab b, tab c limit 5e5;
INSERT INTO tab (id) select (a.id+b.id+c.id)*abs(random()%1e7) from tab a, tab b, tab c limit 5e5;
select count(*) from tab;

它是如何工作的? 它使用if表选项卡:

id int
------
1
2

然后从TAB a中选择a.id, b.id, TAB b返回

a.id int | b.id int
------------------
    1    | 1
    2    | 1
    1    | 2
    2    | 2

等等。第一次执行后,插入2行,然后2^3=8。(三个,因为我们有TAB a TAB b TAB c)

在第二次执行之后,我们插入额外的(2+8)^3=1000行

第三次之后,我们插入大约max(1000^ 3,5e5)=500000行,依此类推……

这是我所知道的填充SQLite数据库的最快方法。