使用javascript String()函数

 String(yourobject); //returns [object Object]

或stringify ()

JSON.stringify(yourobject)

setobjToString:function(obj){
        var me =this;
        obj=obj[0];
        var tabjson=[];
        for (var p in obj) {
            if (obj.hasOwnProperty(p)) {
                if (obj[p] instanceof Array){
                    tabjson.push('"'+p +'"'+ ':' + me.setobjToString(obj[p]));
                }else{
                    tabjson.push('"'+p +'"'+':"'+obj[p]+'"');
                }
            }
        }  tabjson.push()
        return '{'+tabjson.join(',')+'}';
    }

JSON方法远不如Gecko引擎的. tosource()原语。

有关比较测试，请参阅SO文章响应。

同样，上面的答案指的是http://forums.devshed.com/javascript-development-115/tosource-with-arrays-in-ie-386109.html，它像JSON一样(另一篇文章http://www.davidpirek.com/blog/object-to-string-how-to-deserialize-json通过“ExtJs JSON编码源代码”使用)不能处理循环引用，并且是不完整的。下面的代码显示了它的(欺骗的)限制(修正为处理无内容的数组和对象)。

(直接链接到//forums.devshed.com/中的代码…/ tosource - -数组在ie - 386109)

javascript:
Object.prototype.spoof=function(){
    if (this instanceof String){
      return '(new String("'+this.replace(/"/g, '\\"')+'"))';
    }
    var str=(this instanceof Array)
        ? '['
        : (this instanceof Object)
            ? '{'
            : '(';
    for (var i in this){
      if (this[i] != Object.prototype.spoof) {
        if (this instanceof Array == false) {
          str+=(i.match(/\W/))
              ? '"'+i.replace('"', '\\"')+'":'
              : i+':';
        }
        if (typeof this[i] == 'string'){
          str+='"'+this[i].replace('"', '\\"');
        }
        else if (this[i] instanceof Date){
          str+='new Date("'+this[i].toGMTString()+'")';
        }
        else if (this[i] instanceof Array || this[i] instanceof Object){
          str+=this[i].spoof();
        }
        else {
          str+=this[i];
        }
        str+=', ';
      }
    };
    str=/* fix */(str.length>2?str.substring(0, str.length-2):str)/* -ed */+(
        (this instanceof Array)
        ? ']'
        : (this instanceof Object)
            ? '}'
            : ')'
    );
    return str;
  };
for(i in objRA=[
    [   'Simple Raw Object source code:',
        '[new Array, new Object, new Boolean, new Number, ' +
            'new String, new RegExp, new Function, new Date]'   ] ,

    [   'Literal Instances source code:',
        '[ [], {}, true, 1, "", /./, function(){}, new Date() ]'    ] ,

    [   'some predefined entities:',
        '[JSON, Math, null, Infinity, NaN, ' +
            'void(0), Function, Array, Object, undefined]'      ]
    ])
alert([
    '\n\n\ntesting:',objRA[i][0],objRA[i][1],
    '\n.toSource()',(obj=eval(objRA[i][1])).toSource(),
    '\ntoSource() spoof:',obj.spoof()
].join('\n'));

显示:

testing:
Simple Raw Object source code:
[new Array, new Object, new Boolean, new Number, new String,
          new RegExp, new Function, new Date]

.toSource()
[[], {}, (new Boolean(false)), (new Number(0)), (new String("")),
          /(?:)/, (function anonymous() {}), (new Date(1303248037722))]

toSource() spoof:
[[], {}, {}, {}, (new String("")),
          {}, {}, new Date("Tue, 19 Apr 2011 21:20:37 GMT")]

and

testing:
Literal Instances source code:
[ [], {}, true, 1, "", /./, function(){}, new Date() ]

.toSource()
[[], {}, true, 1, "", /./, (function () {}), (new Date(1303248055778))]

toSource() spoof:
[[], {}, true, 1, ", {}, {}, new Date("Tue, 19 Apr 2011 21:20:55 GMT")]

and

testing:
some predefined entities:
[JSON, Math, null, Infinity, NaN, void(0), Function, Array, Object, undefined]

.toSource()
[JSON, Math, null, Infinity, NaN, (void 0),
       function Function() {[native code]}, function Array() {[native code]},
              function Object() {[native code]}, (void 0)]

toSource() spoof:
[{}, {}, null, Infinity, NaN, undefined, {}, {}, {}, undefined]

JSON似乎接受了第二个参数，可以帮助函数- replace，这以最优雅的方式解决了转换问题:

JSON.stringify(object, (key, val) => {
    if (typeof val === 'function') {
      return String(val);
    }
    return val;
  });

如果您正在使用Dojo javascript框架，那么已经有一个内置函数来完成此工作:Dojo . tojson()，它将像这样使用。

var obj = {
  name: 'myObj'
};
dojo.toJson(obj);

它将返回一个字符串。如果要将对象转换为json数据，则添加第二个参数true。

dojo.toJson(obj, true);

http://dojotoolkit.org/reference-guide/dojo/toJson.html#dojo-tojson

一个选项:

console.log('Item: ' + JSON.stringify(o));

另一个选项(正如soktinpk在评论中指出的那样)，更适合控制台调试IMO:

console.log('Item: '， o);