如何将JavaScript对象转换为字符串?
例子:
var o = {a:1, b:2}
console.log(o)
console.log('Item: ' + o)
输出:
对象{a=1, b=2} //非常好的可读输出:) Item: [object object] //不知道里面有什么:(
当前回答
循环引用
通过使用下面的替换器，我们可以产生更少冗余的JSON -如果源对象包含对某个对象的多次引用，或者包含循环引用-那么我们通过特殊的路径字符串(类似于JSONPath)引用它-我们如下所示
let s = JSON.stringify(obj, refReplacer());
function refReplacer() { let m = new Map(), v= new Map(), init = null; return function(field, value) { let p= m.get(this) + (Array.isArray(this) ? `[${field}]` : '.' + field); let isComplex= value===Object(value) if (isComplex) m.set(value, p); let pp = v.get(value)||''; let path = p.replace(/undefined\.\.?/,''); let val = pp ? `#REF:${pp[0]=='[' ? '$':'$.'}${pp}` : value; !init ? (init=value) : (val===init ? val="#REF:$" : 0); if(!pp && isComplex) v.set(value, path); return val; } } // --------------- // TEST // --------------- // gen obj with duplicate references let a = { a1: 1, a2: 2 }; let b = { b1: 3, b2: "4" }; let obj = { o1: { o2: a }, b, a }; // duplicate reference a.a3 = [1,2,b]; // circular reference b.b3 = a; // circular reference let s = JSON.stringify(obj, refReplacer(), 4); console.log(s);
奖励:这里是这种序列化的逆函数
function parseRefJSON(json) { let objToPath = new Map(); let pathToObj = new Map(); let o = JSON.parse(json); let traverse = (parent, field) => { let obj = parent; let path = '#REF:$'; if (field !== undefined) { obj = parent[field]; path = objToPath.get(parent) + (Array.isArray(parent) ? `[${field}]` : `${field?'.'+field:''}`); } objToPath.set(obj, path); pathToObj.set(path, obj); let ref = pathToObj.get(obj); if (ref) parent[field] = ref; for (let f in obj) if (obj === Object(obj)) traverse(obj, f); } traverse(o); return o; } // ------------ // TEST // ------------ let s = `{ "o1": { "o2": { "a1": 1, "a2": 2, "a3": [ 1, 2, { "b1": 3, "b2": "4", "b3": "#REF:$.o1.o2" } ] } }, "b": "#REF:$.o1.o2.a3[2]", "a": "#REF:$.o1.o2" }`; console.log('Open Chrome console to see nested fields:'); let obj = parseRefJSON(s); console.log(obj);
其他回答
JSON方法远不如Gecko引擎的. tosource()原语。
有关比较测试，请参阅SO文章响应。
同样，上面的答案指的是http://forums.devshed.com/javascript-development-115/tosource-with-arrays-in-ie-386109.html，它像JSON一样(另一篇文章http://www.davidpirek.com/blog/object-to-string-how-to-deserialize-json通过“ExtJs JSON编码源代码”使用)不能处理循环引用，并且是不完整的。下面的代码显示了它的(欺骗的)限制(修正为处理无内容的数组和对象)。
(直接链接到//forums.devshed.com/中的代码…/ tosource - -数组在ie - 386109)
javascript:
Object.prototype.spoof=function(){
if (this instanceof String){
return '(new String("'+this.replace(/"/g, '\\"')+'"))';
}
var str=(this instanceof Array)
? '['
: (this instanceof Object)
? '{'
: '(';
for (var i in this){
if (this[i] != Object.prototype.spoof) {
if (this instanceof Array == false) {
str+=(i.match(/\W/))
? '"'+i.replace('"', '\\"')+'":'
: i+':';
}
if (typeof this[i] == 'string'){
str+='"'+this[i].replace('"', '\\"');
}
else if (this[i] instanceof Date){
str+='new Date("'+this[i].toGMTString()+'")';
}
else if (this[i] instanceof Array || this[i] instanceof Object){
str+=this[i].spoof();
}
else {
str+=this[i];
}
str+=', ';
}
};
str=/* fix */(str.length>2?str.substring(0, str.length-2):str)/* -ed */+(
(this instanceof Array)
? ']'
: (this instanceof Object)
? '}'
: ')'
);
return str;
};
for(i in objRA=[
[ 'Simple Raw Object source code:',
'[new Array, new Object, new Boolean, new Number, ' +
'new String, new RegExp, new Function, new Date]' ] ,
[ 'Literal Instances source code:',
'[ [], {}, true, 1, "", /./, function(){}, new Date() ]' ] ,
[ 'some predefined entities:',
'[JSON, Math, null, Infinity, NaN, ' +
'void(0), Function, Array, Object, undefined]' ]
])
alert([
'\n\n\ntesting:',objRA[i][0],objRA[i][1],
'\n.toSource()',(obj=eval(objRA[i][1])).toSource(),
'\ntoSource() spoof:',obj.spoof()
].join('\n'));
显示:
testing:
Simple Raw Object source code:
[new Array, new Object, new Boolean, new Number, new String,
new RegExp, new Function, new Date]
.toSource()
[[], {}, (new Boolean(false)), (new Number(0)), (new String("")),
/(?:)/, (function anonymous() {}), (new Date(1303248037722))]
toSource() spoof:
[[], {}, {}, {}, (new String("")),
{}, {}, new Date("Tue, 19 Apr 2011 21:20:37 GMT")]
and
testing:
Literal Instances source code:
[ [], {}, true, 1, "", /./, function(){}, new Date() ]
.toSource()
[[], {}, true, 1, "", /./, (function () {}), (new Date(1303248055778))]
toSource() spoof:
[[], {}, true, 1, ", {}, {}, new Date("Tue, 19 Apr 2011 21:20:55 GMT")]
and
testing:
some predefined entities:
[JSON, Math, null, Infinity, NaN, void(0), Function, Array, Object, undefined]
.toSource()
[JSON, Math, null, Infinity, NaN, (void 0),
function Function() {[native code]}, function Array() {[native code]},
function Object() {[native code]}, (void 0)]
toSource() spoof:
[{}, {}, null, Infinity, NaN, undefined, {}, {}, {}, undefined]
我需要制作一个更可配置的JSON版本。stringify，因为我必须添加注释和知道JSON路径:
const someObj = { a: { nested: { value: 'apple', }, sibling: 'peanut' }, b: { languages: ['en', 'de', 'fr'], c: { nice: 'heh' } }, c: 'butter', d: function () {} }; function* objIter(obj, indent = ' ', depth = 0, path = '') { const t = indent.repeat(depth); const t1 = indent.repeat(depth + 1); const v = v => JSON.stringify(v); yield { type: Array.isArray(obj) ? 'OPEN_ARR' : 'OPEN_OBJ', indent, depth }; const keys = Object.keys(obj); for (let i = 0, l = keys.length; i < l; i++) { const key = keys[i]; const prop = obj[key]; const nextPath = !path && key || `${path}.${key}`; if (typeof prop !== 'object') { yield { type: isNaN(key) ? 'VAL' : 'ARR_VAL', key, prop, indent, depth, path: nextPath }; } else { yield { type: 'OBJ_KEY', key, indent, depth, path: nextPath }; yield* objIter(prop, indent, depth + 1, nextPath); } } yield { type: Array.isArray(obj) ? 'CLOSE_ARR' : 'CLOSE_OBJ', indent, depth }; } const iterMap = (it, mapFn) => { const arr = []; for (const x of it) { arr.push(mapFn(x)) } return arr; } const objToStr = obj => iterMap(objIter(obj), ({ type, key, prop, indent, depth, path }) => { const t = indent.repeat(depth); const t1 = indent.repeat(depth + 1); const v = v => JSON.stringify(v); switch (type) { case 'OPEN_ARR': return '[\n'; case 'OPEN_OBJ': return '{\n'; case 'VAL': return `${t1}// ${path}\n${t1}${v(key)}: ${v(prop)},\n`; case 'ARR_VAL': return `${t1}// ${path}\n${t1}${v(prop)},\n`; case 'OBJ_KEY': return `${t1}// ${path}\n${t1}${v(key)}: `; case 'CLOSE_ARR': case 'CLOSE_OBJ': return `${t}${type === 'CLOSE_ARR' ? ']' : '}'}${depth ? ',' : ';'}\n`; default: throw new Error('Unknown type:', type); } }).join(''); const s = objToStr(someObj); console.log(s);
如果你想要的只是一个字符串输出，那么这应该工作:
如果你想在内联表达式类型的情况下用最简单的方法将变量转换为字符串，“+variablename是我打过的最好的球。
如果'variablename'是一个对象，你使用空字符串连接操作，它将给出烦人的[object object]，在这种情况下，你可能想要Gary C。JSON获得了极大的好评。stringify问题的答案，你可以在Mozilla的开发者网络的答案在顶部的链接中阅读。
如果只是想查看用于调试的对象，可以使用
var o = {a:1, b:2}
console.dir(o)
