我扩展了David Coallier的方法：

增加了合并多个对象的可能性支持深层对象override参数（如果最后一个参数是布尔值，则检测到）

如果覆盖为false，则不会覆盖任何属性，但会添加新的财产。

用法：obj.merge（合并…[，覆盖]）；

这是我的代码：

Object.defineProperty(Object.prototype, "merge", {
    enumerable: false,
    value: function () {
        var override = true,
            dest = this,
            len = arguments.length,
            props, merge, i, from;

        if (typeof(arguments[arguments.length - 1]) === "boolean") {
            override = arguments[arguments.length - 1];
            len = arguments.length - 1;
        }

        for (i = 0; i < len; i++) {
            from = arguments[i];
            if (from != null) {
                Object.getOwnPropertyNames(from).forEach(function (name) {
                    var descriptor;

                    // nesting
                    if ((typeof(dest[name]) === "object" || typeof(dest[name]) === "undefined")
                            && typeof(from[name]) === "object") {

                        // ensure proper types (Array rsp Object)
                        if (typeof(dest[name]) === "undefined") {
                            dest[name] = Array.isArray(from[name]) ? [] : {};
                        }
                        if (override) {
                            if (!Array.isArray(dest[name]) && Array.isArray(from[name])) {
                                dest[name] = [];
                            }
                            else if (Array.isArray(dest[name]) && !Array.isArray(from[name])) {
                                dest[name] = {};
                            }
                        }
                        dest[name].merge(from[name], override);
                    } 

                    // flat properties
                    else if ((name in dest && override) || !(name in dest)) {
                        descriptor = Object.getOwnPropertyDescriptor(from, name);
                        if (descriptor.configurable) {
                            Object.defineProperty(dest, name, descriptor);
                        }
                    }
                });
            }
        }
        return this;
    }
});

示例和测试用例：

function clone (obj) {
    return JSON.parse(JSON.stringify(obj));
}
var obj = {
    name : "trick",
    value : "value"
};

var mergeObj = {
    name : "truck",
    value2 : "value2"
};

var mergeObj2 = {
    name : "track",
    value : "mergeObj2",
    value2 : "value2-mergeObj2",
    value3 : "value3"
};

assertTrue("Standard", clone(obj).merge(mergeObj).equals({
    name : "truck",
    value : "value",
    value2 : "value2"
}));

assertTrue("Standard no Override", clone(obj).merge(mergeObj, false).equals({
    name : "trick",
    value : "value",
    value2 : "value2"
}));

assertTrue("Multiple", clone(obj).merge(mergeObj, mergeObj2).equals({
    name : "track",
    value : "mergeObj2",
    value2 : "value2-mergeObj2",
    value3 : "value3"
}));

assertTrue("Multiple no Override", clone(obj).merge(mergeObj, mergeObj2, false).equals({
    name : "trick",
    value : "value",
    value2 : "value2",
    value3 : "value3"
}));

var deep = {
    first : {
        name : "trick",
        val : "value"
    },
    second : {
        foo : "bar"
    }
};

var deepMerge = {
    first : {
        name : "track",
        anotherVal : "wohoo"
    },
    second : {
        foo : "baz",
        bar : "bam"
    },
    v : "on first layer"
};

assertTrue("Deep merges", clone(deep).merge(deepMerge).equals({
    first : {
        name : "track",
        val : "value",
        anotherVal : "wohoo"
    },
    second : {
        foo : "baz",
        bar : "bam"
    },
    v : "on first layer"
}));

assertTrue("Deep merges no override", clone(deep).merge(deepMerge, false).equals({
    first : {
        name : "trick",
        val : "value",
        anotherVal : "wohoo"
    },
    second : {
        foo : "bar",
        bar : "bam"
    },
    v : "on first layer"
}));

var obj1 = {a: 1, b: "hello"};
obj1.merge({c: 3});
assertTrue(obj1.equals({a: 1, b: "hello", c: 3}));

obj1.merge({a: 2, b: "mom", d: "new property"}, false);
assertTrue(obj1.equals({a: 1, b: "hello", c: 3, d: "new property"}));

var obj2 = {};
obj2.merge({a: 1}, {b: 2}, {a: 3});
assertTrue(obj2.equals({a: 3, b: 2}));

var a = [];
var b = [1, [2, 3], 4];
a.merge(b);
assertEquals(1, a[0]);
assertEquals([2, 3], a[1]);
assertEquals(4, a[2]);


var o1 = {};
var o2 = {a: 1, b: {c: 2}};
var o3 = {d: 3};
o1.merge(o2, o3);
assertTrue(o1.equals({a: 1, b: {c: 2}, d: 3}));
o1.b.c = 99;
assertTrue(o2.equals({a: 1, b: {c: 2}}));

// checking types with arrays and objects
var bo;
a = [];
bo = [1, {0:2, 1:3}, 4];
b = [1, [2, 3], 4];

a.merge(b);
assertTrue("Array stays Array?", Array.isArray(a[1]));

a = [];
a.merge(bo);
assertTrue("Object stays Object?", !Array.isArray(a[1]));

a = [];
a.merge(b);
a.merge(bo);
assertTrue("Object overrides Array", !Array.isArray(a[1]));

a = [];
a.merge(b);
a.merge(bo, false);
assertTrue("Object does not override Array", Array.isArray(a[1]));

a = [];
a.merge(bo);
a.merge(b);
assertTrue("Array overrides Object", Array.isArray(a[1]));

a = [];
a.merge(bo);
a.merge(b, false);
assertTrue("Array does not override Object", !Array.isArray(a[1]));

我的equals方法可以在这里找到：JavaScript中的对象比较

对于不太复杂的对象，可以使用JSON：

var obj1 = { food: 'pizza', car: 'ford' }
var obj2 = { animal: 'dog', car: 'chevy'}
var objMerge;

objMerge = JSON.stringify(obj1) + JSON.stringify(obj2);

// {"food": "pizza","car":"ford"}{"animal":"dog","car":"chevy"}

objMerge = objMerge.replace(/\}\{/, ","); //  \_ replace with comma for valid JSON

objMerge = JSON.parse(objMerge); // { food: 'pizza', animal: 'dog', car: 'chevy'}
// Of same keys in both objects, the last object's value is retained_/

请注意，在此示例中，“｝｛”不能出现在字符串中！

您可以为每个对象分配一个默认的合并（也许“继承”一个更好的名称）方法：

它应该使用对象或实例化函数。

如果需要，下面的代码处理重写合并值：

Object.prototype.merge = function(obj, override) {
// Don't override by default

    for (var key in obj) {
        var n = obj[key];
        var t = this[key];
        this[key] = (override && t) ? n : t;
    };

};

测试数据如下：

var Mammal = function () {
    this.eyes = 2;
    this.thinking_brain = false;
    this.say = function () {
    console.log('screaming like a mammal')};
}

var Human = function () {
    this.thinking_brain = true;
    this.say = function() {console.log('shouting like a human')};
}

john = new Human();

// Extend mammal, but do not override from mammal
john.merge(new Mammal());
john.say();

// Extend mammal and override from mammal
john.merge(new Mammal(), true);
john.say();

函数扩展（o，o1，o2）{如果（！（o instanceof Object））o=｛｝；副本（o，o1）；如果（o2）副本（o，o2）函数isObject（obj）{var type=Object.protype.toString.call（obj）；return obj===对象（obj）&&type！='[object Array]'&&type！='[object函数]'；};功能副本（a，b）{//将o2复制到ofor（b中的var键）if（b.hasOwnProperty（键））{if（isObject（b[key]））{if（！isObject（a[key]））a[key]=Object.assign（{}，b[key]）；其他副本（a[key]，b[key]）}其他的a[key]=b[key]；}}返回o；};变量o1＝｛a:｛foo:1｝，b:1｝，o2={a:{bar:2}，b:[1]，c:（）=>{}}，newMerged=扩展（{}，o1，o2）；console.log（newMerged）控制台日志（o1）控制台日志（o2）

浅的

var obj = { name : "Jacob" , address : ["America"] }
var obj2 = { name : "Shaun" , address : ["Honk Kong"] }

var merged = Object.assign({} , obj,obj2 ); //shallow merge 
obj2.address[0] = "new city"

result.地址[0]更改为“新城”，即合并对象也更改。这就是浅层合并的问题。

deep

var obj = { name : "Jacob" , address : ["America"] }
var obj2 = { name : "Shaun" , address : ["Honk Kong"] }

var result = Object.assign({} , JSON.parse(JSON.stringify(obj)),JSON.parse(JSON.stringify(obj2)) )

obj2.address[0] = "new city"

result.address[0]未更改

使用以下助手，可以将两个对象合并为一个新对象：

function extend(obj, src) {
    for (var key in src) {
        if (src.hasOwnProperty(key)) obj[key] = src[key];
    }
    return obj;
}

// example
var a = { foo: true }, b = { bar: false };
var c = extend(a, b);

console.log(c);
// { foo: true, bar: false }

当将选项dict与函数或插件中的默认设置合并时，这通常很有用。

如果不需要支持IE 8，您可以使用Object.keys来实现相同的功能：

function extend(obj, src) {
    Object.keys(src).forEach(function(key) { obj[key] = src[key]; });
    return obj;
}

这涉及的代码稍微少一点，速度也快一点。