我需要能够在运行时合并两个(非常简单)JavaScript对象。例如,我想:
var obj1 = { food: 'pizza', car: 'ford' }
var obj2 = { animal: 'dog' }
obj1.merge(obj2);
//obj1 now has three properties: food, car, and animal
是否有一种内置的方法来实现这一点?我不需要递归,也不需要合并函数,只需要平面对象上的方法。
我需要能够在运行时合并两个(非常简单)JavaScript对象。例如,我想:
var obj1 = { food: 'pizza', car: 'ford' }
var obj2 = { animal: 'dog' }
obj1.merge(obj2);
//obj1 now has three properties: food, car, and animal
是否有一种内置的方法来实现这一点?我不需要递归,也不需要合并函数,只需要平面对象上的方法。
当前回答
我扩展了David Coallier的方法:
增加了合并多个对象的可能性支持深层对象override参数(如果最后一个参数是布尔值,则检测到)
如果覆盖为false,则不会覆盖任何属性,但会添加新的财产。
用法:obj.merge(合并…[,覆盖]);
这是我的代码:
Object.defineProperty(Object.prototype, "merge", {
enumerable: false,
value: function () {
var override = true,
dest = this,
len = arguments.length,
props, merge, i, from;
if (typeof(arguments[arguments.length - 1]) === "boolean") {
override = arguments[arguments.length - 1];
len = arguments.length - 1;
}
for (i = 0; i < len; i++) {
from = arguments[i];
if (from != null) {
Object.getOwnPropertyNames(from).forEach(function (name) {
var descriptor;
// nesting
if ((typeof(dest[name]) === "object" || typeof(dest[name]) === "undefined")
&& typeof(from[name]) === "object") {
// ensure proper types (Array rsp Object)
if (typeof(dest[name]) === "undefined") {
dest[name] = Array.isArray(from[name]) ? [] : {};
}
if (override) {
if (!Array.isArray(dest[name]) && Array.isArray(from[name])) {
dest[name] = [];
}
else if (Array.isArray(dest[name]) && !Array.isArray(from[name])) {
dest[name] = {};
}
}
dest[name].merge(from[name], override);
}
// flat properties
else if ((name in dest && override) || !(name in dest)) {
descriptor = Object.getOwnPropertyDescriptor(from, name);
if (descriptor.configurable) {
Object.defineProperty(dest, name, descriptor);
}
}
});
}
}
return this;
}
});
示例和测试用例:
function clone (obj) {
return JSON.parse(JSON.stringify(obj));
}
var obj = {
name : "trick",
value : "value"
};
var mergeObj = {
name : "truck",
value2 : "value2"
};
var mergeObj2 = {
name : "track",
value : "mergeObj2",
value2 : "value2-mergeObj2",
value3 : "value3"
};
assertTrue("Standard", clone(obj).merge(mergeObj).equals({
name : "truck",
value : "value",
value2 : "value2"
}));
assertTrue("Standard no Override", clone(obj).merge(mergeObj, false).equals({
name : "trick",
value : "value",
value2 : "value2"
}));
assertTrue("Multiple", clone(obj).merge(mergeObj, mergeObj2).equals({
name : "track",
value : "mergeObj2",
value2 : "value2-mergeObj2",
value3 : "value3"
}));
assertTrue("Multiple no Override", clone(obj).merge(mergeObj, mergeObj2, false).equals({
name : "trick",
value : "value",
value2 : "value2",
value3 : "value3"
}));
var deep = {
first : {
name : "trick",
val : "value"
},
second : {
foo : "bar"
}
};
var deepMerge = {
first : {
name : "track",
anotherVal : "wohoo"
},
second : {
foo : "baz",
bar : "bam"
},
v : "on first layer"
};
assertTrue("Deep merges", clone(deep).merge(deepMerge).equals({
first : {
name : "track",
val : "value",
anotherVal : "wohoo"
},
second : {
foo : "baz",
bar : "bam"
},
v : "on first layer"
}));
assertTrue("Deep merges no override", clone(deep).merge(deepMerge, false).equals({
first : {
name : "trick",
val : "value",
anotherVal : "wohoo"
},
second : {
foo : "bar",
bar : "bam"
},
v : "on first layer"
}));
var obj1 = {a: 1, b: "hello"};
obj1.merge({c: 3});
assertTrue(obj1.equals({a: 1, b: "hello", c: 3}));
obj1.merge({a: 2, b: "mom", d: "new property"}, false);
assertTrue(obj1.equals({a: 1, b: "hello", c: 3, d: "new property"}));
var obj2 = {};
obj2.merge({a: 1}, {b: 2}, {a: 3});
assertTrue(obj2.equals({a: 3, b: 2}));
var a = [];
var b = [1, [2, 3], 4];
a.merge(b);
assertEquals(1, a[0]);
assertEquals([2, 3], a[1]);
assertEquals(4, a[2]);
var o1 = {};
var o2 = {a: 1, b: {c: 2}};
var o3 = {d: 3};
o1.merge(o2, o3);
assertTrue(o1.equals({a: 1, b: {c: 2}, d: 3}));
o1.b.c = 99;
assertTrue(o2.equals({a: 1, b: {c: 2}}));
// checking types with arrays and objects
var bo;
a = [];
bo = [1, {0:2, 1:3}, 4];
b = [1, [2, 3], 4];
a.merge(b);
assertTrue("Array stays Array?", Array.isArray(a[1]));
a = [];
a.merge(bo);
assertTrue("Object stays Object?", !Array.isArray(a[1]));
a = [];
a.merge(b);
a.merge(bo);
assertTrue("Object overrides Array", !Array.isArray(a[1]));
a = [];
a.merge(b);
a.merge(bo, false);
assertTrue("Object does not override Array", Array.isArray(a[1]));
a = [];
a.merge(bo);
a.merge(b);
assertTrue("Array overrides Object", Array.isArray(a[1]));
a = [];
a.merge(bo);
a.merge(b, false);
assertTrue("Array does not override Object", !Array.isArray(a[1]));
我的equals方法可以在这里找到:JavaScript中的对象比较
其他回答
我在谷歌上搜索了合并对象财产的代码,结果出现在这里。然而,由于没有递归合并的代码,我自己编写了它。(也许jQuery扩展是递归的BTW?)无论如何,希望其他人也会发现它很有用。
(现在代码不使用Object.prototype:)
Code
/*
* Recursively merge properties of two objects
*/
function MergeRecursive(obj1, obj2) {
for (var p in obj2) {
try {
// Property in destination object set; update its value.
if ( obj2[p].constructor==Object ) {
obj1[p] = MergeRecursive(obj1[p], obj2[p]);
} else {
obj1[p] = obj2[p];
}
} catch(e) {
// Property in destination object not set; create it and set its value.
obj1[p] = obj2[p];
}
}
return obj1;
}
一个例子
o1 = { a : 1,
b : 2,
c : {
ca : 1,
cb : 2,
cc : {
cca : 100,
ccb : 200 } } };
o2 = { a : 10,
c : {
ca : 10,
cb : 20,
cc : {
cca : 101,
ccb : 202 } } };
o3 = MergeRecursive(o1, o2);
生成类似o3的对象
o3 = { a : 10,
b : 2,
c : {
ca : 10,
cb : 20,
cc : {
cca : 101,
ccb : 202 } } };
我今天需要合并对象,这个问题(和答案)对我帮助很大。我尝试了一些答案,但没有一个符合我的需要,所以我组合了一些答案并自己添加了一些东西,并提出了一个新的合并函数。这里是:
var merge = function() {
var obj = {},
i = 0,
il = arguments.length,
key;
for (; i < il; i++) {
for (key in arguments[i]) {
if (arguments[i].hasOwnProperty(key)) {
obj[key] = arguments[i][key];
}
}
}
return obj;
};
一些示例用法:
var t1 = {
key1: 1,
key2: "test",
key3: [5, 2, 76, 21]
};
var t2 = {
key1: {
ik1: "hello",
ik2: "world",
ik3: 3
}
};
var t3 = {
key2: 3,
key3: {
t1: 1,
t2: 2,
t3: {
a1: 1,
a2: 3,
a4: [21, 3, 42, "asd"]
}
}
};
console.log(merge(t1, t2));
console.log(merge(t1, t3));
console.log(merge(t2, t3));
console.log(merge(t1, t2, t3));
console.log(merge({}, t1, { key1: 1 }));
值得一提的是,140byt.es集合的版本在最小空间内解决了这一任务,值得一试:
代码:
function m(a,b,c){for(c in b)b.hasOwnProperty(c)&&((typeof a[c])[0]=='o'?m(a[c],b[c]):a[c]=b[c])}
用途:
m(obj1,obj2);
这是原始的Gist。
在YUI Y.merge中,应完成以下工作:
Y.merge(obj1, obj2, obj3....)
我刚开始使用JavaScript,所以如果我错了,请纠正我。
但如果可以合并任意数量的对象,不是更好吗?下面是我如何使用本机Arguments对象实现的。
关键在于,实际上可以向JavaScript函数传递任意数量的参数,而无需在函数声明中定义它们。如果不使用Arguments对象,就无法访问它们。
function mergeObjects() (
var tmpObj = {};
for(var o in arguments) {
for(var m in arguments[o]) {
tmpObj[m] = arguments[o][m];
}
}
return tmpObj;
}