我已经上传了备份到一个表,打开表我看到这个:

Warning in ./libraries/sql.lib.php#601
count(): Parameter must be an array or an object that implements Countable

Backtrace

./libraries/sql.lib.php#2038: PMA_isRememberSortingOrder(array)
./libraries/sql.lib.php#1984: PMA_executeQueryAndGetQueryResponse(
array,
boolean true,
string 'alternativegirls',
string 'tgp_photo',
NULL,
NULL,
NULL,
NULL,
NULL,
NULL,
string '',
string './themes/pmahomme/img/',
NULL,
NULL,
NULL,
string 'SELECT * FROM `tgp_photo`',
NULL,
NULL,
)
./sql.php#216: PMA_executeQueryAndSendQueryResponse(
array,
boolean true,
string 'alternativegirls',
string 'tgp_photo',
NULL,
NULL,
NULL,
NULL,
NULL,
NULL,
string '',
string './themes/pmahomme/img/',
NULL,
NULL,
NULL,
string 'SELECT * FROM `tgp_photo`',
NULL,
NULL,
)
./index.php#53: include(./sql.php)

在phpMyAdmin……

PHP是7.2,服务器是Ubuntu 16.04,昨天安装的。

我看到一些人在他们的代码中有这个错误,但我没有发现任何人在phpMyAdmin中收到它…

我该怎么办?这是我的错误吗?phpmyadmin错误?等待更新?回到PHP 7.1?


当前回答

由于conf文件中的代码错误可能会有所不同(@Jacky Nguyen vs @ĦΔŇĐŘΔ ŇΔҜҜΔ answers),一般解决方案的答案是 A)修正conf文件中的条件逻辑使之有意义 (x)或b)安装正确的/当前phpmyadmin

至于a)

open the file with error code For the terminal people: sudo nano /usr/share/phpmyadmin/libraries/sql.lib.php For the regular folks: sudo gedit /usr/share/phpmyadmin/libraries/sql.lib.php find the condition - basically search for $analyzed_sql_results['select_expr'] now the logic should be to check whether this sub array is empty, or, whether it has just 1 element with a value "* so basically the block between && $analyzed_sql_results['select_from']and && count($analyzed_sql_results['select_tables']) == 1 should look something like this

& & ( Empty ($analyzed_sql_results['select_expr']) //子数组为空, | | / /, ( (count($analyzed_sql_results['select_expr']) == 1) //只有一个元素 && //和同时 ($analyzed_sql_results['select_expr'][0] == '*') // 1元素值为"*" ) )

这是一个很好的例子,为什么缩进和美化你的代码,如果它将缩进正确,我相信这永远不会发生,或者至少,会更容易找到。

其他回答

add-apt-repository ppa:phpmyadmin/ppa
apt-get clean
apt-get update
apt-get purge phpmyadmin
apt-get install phpmyadmin

在Ubuntu 18.04上为我修复了它。

Ubuntu 18.10(2018年12月)

第613、614、615行,替换为:

        || count($analyzed_sql_results['select_expr']) == 1
            && ($analyzed_sql_results['select_expr'][0] == '*'))
    && count($analyzed_sql_results['select_tables']) == 1;

尝试在文件中替换此函数: /usr/share/phpmyadmin/libraries/sql.lib.php

function PMA_isRememberSortingOrder($analyzed_sql_results)
{
    return $GLOBALS['cfg']['RememberSorting']
        && ! ($analyzed_sql_results['is_count']
            || $analyzed_sql_results['is_export']
            || $analyzed_sql_results['is_func']
            || $analyzed_sql_results['is_analyse'])
        && $analyzed_sql_results['select_from']
        && ((empty($analyzed_sql_results['select_expr']))
            || (count($analyzed_sql_results['select_expr']) == 1)
                && ($analyzed_sql_results['select_expr'][0] == '*'))
        && count($analyzed_sql_results['select_tables']) == 1;
}

这对我很管用;

sudo nano /usr/share/phpmyadmin/libraries/sql.lib.php 

线路:614

替换两个代码:

替换:

(count($analyzed_sql_results[‘select_expr’] == 1)

:

(count($analyzed_sql_results[‘select_expr’]) == 1)

AND

替换:

($analyzed_sql_results[‘select_expr’][0] == ‘*’)))

:

($analyzed_sql_results[‘select_expr’][0] == ‘*’))

保存,退出并运行

sudo service apache2 restart

适用于UBUNTU 16.04.3 打开

usr / share /图书馆/ sql.lib.php

修改

|| (count($analyzed_sql_results['select_expr'] == 1)

To

| | ((count ($ analyzed_sql_results [' select_expr ']) = = 1)