function timeDifference(date1, date2) { var oneDay = 24 * 60 * 60; // hours*minutes*seconds var oneHour = 60 * 60; // minutes*seconds var oneMinute = 60; // 60 seconds var firstDate = date1.getTime(); // convert to milliseconds var secondDate = date2.getTime(); // convert to milliseconds var seconds = Math.round(Math.abs(firstDate - secondDate) / 1000); //calculate the diffrence in seconds // the difference object var difference = { "days": 0, "hours": 0, "minutes": 0, "seconds": 0, } //calculate all the days and substract it from the total while (seconds >= oneDay) { difference.days++; seconds -= oneDay; } //calculate all the remaining hours then substract it from the total while (seconds >= oneHour) { difference.hours++; seconds -= oneHour; } //calculate all the remaining minutes then substract it from the total while (seconds >= oneMinute) { difference.minutes++; seconds -= oneMinute; } //the remaining seconds : difference.seconds = seconds; //return the difference object return difference; } console.log(timeDifference(new Date(2017,0,1,0,0,0),new Date()));

   function validateDate() {
        // get dates from input fields
        var startDate = $("#startDate").val();
        var endDate = $("#endDate").val();
        var sdate = startDate.split("-");
        var edate = endDate.split("-");
        var diffd = (edate[2] - sdate[2]) + 1;
        var leap = [ 0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ];
        var nonleap = [ 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ];
        if (sdate[0] > edate[0]) {
            alert("Please enter End Date Year greater than Start Date Year");
            document.getElementById("endDate").value = "";
            diffd = "";
        } else if (sdate[1] > edate[1]) {
            alert("Please enter End Date month greater than Start Date month");
            document.getElementById("endDate").value = "";
            diffd = "";
        } else if (sdate[2] > edate[2]) {
            alert("Please enter End Date greater than Start Date");
            document.getElementById("endDate").value = "";
            diffd = "";
        } else {
            if (sdate[0] / 4 == 0) {
                while (sdate[1] < edate[1]) {
                    diffd = diffd + leap[sdate[1]++];
                }
            } else {
                while (sdate[1] < edate[1]) {
                    diffd = diffd + nonleap[sdate[1]++];
                }
            }
            document.getElementById("numberOfDays").value = diffd;
        }
    }

最好还是取消夏令时吧，马斯。装天花板,数学。楼层等，使用UTC时间:

var firstDate = Date.UTC(2015,01,2);
var secondDate = Date.UTC(2015,04,22);
var diff = Math.abs((firstDate.valueOf() 
    - secondDate.valueOf())/(24*60*60*1000));

这个例子给出了109天的差异。24*60*60*1000是一天，单位是毫秒。

您可以使用UnderscoreJS来格式化和计算差异。

演示https://jsfiddle.net/sumitridhal/8sv94msp/

var startDate = moment(“206 -08- 29t23:35:01”); var endDate = moment(“206 -08- 30t23:35:01”); 游戏机。log (startDate); 游戏机。log (endDate); var结果= endDate。diff(startDate, hours, true); 文件。 文档全身appendChild(文档。createTextNode (resultHours)); 身体(白色空间:pre;font-family: monospace;) “https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.5.1/moment.min.js”< script src = > / < script >

下面是datediff的快速实现，作为解决问题的概念证明。它依赖于这样一个事实，即您可以通过减去两个日期之间经过的毫秒，这将它们强制转换为原始数字值(自1970年初以来的毫秒)。

/** * Take the difference between the dates and divide by milliseconds per day. * Round to nearest whole number to deal with DST. */ function datediff(first, second) { return Math.round((second - first) / (1000 * 60 * 60 * 24)); } /** * new Date("dateString") is browser-dependent and discouraged, so we'll write * a simple parse function for U.S. date format (which does no error checking) */ function parseDate(str) { var mdy = str.split('/'); return new Date(mdy[2], mdy[0] - 1, mdy[1]); } alert(datediff(parseDate(first.value), parseDate(second.value))); <input id="first" value="1/1/2000"/> <input id="second" value="1/1/2001"/>

You should be aware that the "normal" Date APIs (without "UTC" in the name) operate in the local timezone of the user's browser, so in general you could run into issues if your user is in a timezone that you don't expect, and your code will have to deal with Daylight Saving Time transitions. You should carefully read the documentation for the Date object and its methods, and for anything more complicated, strongly consider using a library that offers more safe and powerful APIs for date manipulation.

数字和日期——MDN JavaScript指南 日期——MDN JavaScript参考

同样，出于说明的目的，为了简洁起见，该代码段对窗口对象使用了命名访问，但在生产中应该使用getElementById之类的标准化api，或者更有可能使用一些UI框架。

计算两个日期之间天数的简单方法是去掉它们的时间分量，即将小时、分钟、秒和毫秒设置为0，然后减去它们的时间，用一天的毫秒值来计算。

var firstDate= new Date(firstDate.setHours(0,0,0,0));
var secondDate= new Date(secondDate.setHours(0,0,0,0));
var timeDiff = firstDate.getTime() - secondDate.getTime();
var diffDays =timeDiff / (1000 * 3600 * 24);