例如，在输入框中给定两个日期:
<input id="first" value="1/1/2000"/>
<input id="second" value="1/1/2001"/>
<script>
alert(datediff("day", first, second)); // what goes here?
</script>
如何在JavaScript中获得两个日期之间的天数?
当前回答
最好还是取消夏令时吧，马斯。装天花板,数学。楼层等，使用UTC时间:
var firstDate = Date.UTC(2015,01,2);
var secondDate = Date.UTC(2015,04,22);
var diff = Math.abs((firstDate.valueOf()
- secondDate.valueOf())/(24*60*60*1000));
这个例子给出了109天的差异。24*60*60*1000是一天，单位是毫秒。
其他回答
如果我们想计算我们的年龄，这是一个有点不同的答案
{
birthday: 'April 22, 1993',
names: {
first: 'Keith',
last: 'Buckley'
}
},
{
birthday: 'January 3, 1975',
names: {
first: 'Larry',
last: 'Heep'
}
},
{
birthday: 'February 12, 1944',
names: {
first: 'Linda',
last: 'Bermeer'
}
}
];
const cleanPeople = people.map(function ({birthday, names:{first, last}}) {
// birthday, age, fullName;
const now = new Date();
var age = Math.floor(( Date.parse(now) - Date.parse(birthday)) / 31536000000);
return {
age,
fullName:`${first} ${last}`
}
});
console.log(cleanPeople);
console.table(cleanPeople);
更好的解决方案
忽略时间部分
如果两个日期相同，则返回0。
function dayDiff(firstDate, secondDate) { firstDate = new Date(firstDate); secondDate = new Date(secondDate); if (!isNaN(firstDate) && !isNaN(secondDate)) { firstDate.setHours(0, 0, 0, 0); //ignore time part secondDate.setHours(0, 0, 0, 0); //ignore time part var dayDiff = secondDate - firstDate; dayDiff = dayDiff / 86400000; // divide by milisec in one day console.log(dayDiff); } else { console.log("Enter valid date."); } } $(document).ready(function() { $('input[type=datetime]').datepicker({ dateFormat: "mm/dd/yy", changeMonth: true, changeYear: true }); $("#button").click(function() { dayDiff($('#first').val(), $('#second').val()); }); }); <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <link rel="stylesheet" href="//code.jquery.com/ui/1.12.1/themes/base/jquery-ui.css"> <script src="//code.jquery.com/ui/1.12.1/jquery-ui.js"></script> <input type="datetime" id="first" value="12/28/2016" /> <input type="datetime" id="second" value="12/28/2017" /> <input type="button" id="button" value="Calculate">
我来找这个小工具在里面你会找到这个的函数。这里有一个简短的例子:
<script type="text/javascript" src="date.js"></script>
<script type="text/javascript">
var minutes = 1000*60;
var hours = minutes*60;
var days = hours*24;
var foo_date1 = getDateFromFormat("02/10/2009", "M/d/y");
var foo_date2 = getDateFromFormat("02/12/2009", "M/d/y");
var diff_date = Math.round((foo_date2 - foo_date1)/days);
alert("Diff date is: " + diff_date );
</script>
区分两个日期的最简单方法是:
var diff = Math.floor((Date.parse(str2) - Date.parse(str1)) / 86400000);
您将得到不同的天数(如果其中一个或两个都无法解析，则为NaN)。解析日期给出了以毫秒为单位的结果，要按天得到它，你必须除以24 * 60 * 60 * 1000
如果你想用天、小时、分钟、秒和毫秒来划分:
function dateDiff( str1, str2 ) {
var diff = Date.parse( str2 ) - Date.parse( str1 );
return isNaN( diff ) ? NaN : {
diff : diff,
ms : Math.floor( diff % 1000 ),
s : Math.floor( diff / 1000 % 60 ),
m : Math.floor( diff / 60000 % 60 ),
h : Math.floor( diff / 3600000 % 24 ),
d : Math.floor( diff / 86400000 )
};
}
以下是我对James版本的重构版本:
function mydiff(date1,date2,interval) {
var second=1000, minute=second*60, hour=minute*60, day=hour*24, week=day*7;
date1 = new Date(date1);
date2 = new Date(date2);
var timediff = date2 - date1;
if (isNaN(timediff)) return NaN;
switch (interval) {
case "years": return date2.getFullYear() - date1.getFullYear();
case "months": return (
( date2.getFullYear() * 12 + date2.getMonth() )
-
( date1.getFullYear() * 12 + date1.getMonth() )
);
case "weeks" : return Math.floor(timediff / week);
case "days" : return Math.floor(timediff / day);
case "hours" : return Math.floor(timediff / hour);
case "minutes": return Math.floor(timediff / minute);
case "seconds": return Math.floor(timediff / second);
default: return undefined;
}
}
如果你想有一个DateArray日期试试这个:
<script>
function getDates(startDate, stopDate) {
var dateArray = new Array();
var currentDate = moment(startDate);
dateArray.push( moment(currentDate).format('L'));
var stopDate = moment(stopDate);
while (dateArray[dateArray.length -1] != stopDate._i) {
dateArray.push( moment(currentDate).format('L'));
currentDate = moment(currentDate).add(1, 'days');
}
return dateArray;
}
</script>
调试片段
