例如，在输入框中给定两个日期:
<input id="first" value="1/1/2000"/>
<input id="second" value="1/1/2001"/>
<script>
alert(datediff("day", first, second)); // what goes here?
</script>
如何在JavaScript中获得两个日期之间的天数?
当前回答
// JavaScript / NodeJs answer
let startDate = new Date("2022-09-19");
let endDate = new Date("2022-09-26");
let difference = startDate.getTime() - endDate.getTime();
console.log(difference);
let TotalDiffDays = Math.ceil(difference / (1000 * 3600 * 24));
console.log(TotalDiffDays + " days :) ");
其他回答
我在Angular中也遇到了同样的问题。我复制了一份，否则他会覆盖第一次约会。两个日期的时间都必须为00:00:00(显然)
/*
* Deze functie gebruiken we om het aantal dagen te bereken van een booking.
* */
$scope.berekenDagen = function ()
{
$scope.booking.aantalDagen=0;
/*De loper is gelijk aan de startdag van je reservatie.
* De copy is nodig anders overschijft angular de booking.van.
* */
var loper = angular.copy($scope.booking.van);
/*Zolang de reservatie beschikbaar is, doorloop de weekdagen van je start tot einddatum.*/
while (loper < $scope.booking.tot) {
/*Tel een dag op bij je loper.*/
loper.setDate(loper.getDate() + 1);
$scope.booking.aantalDagen++;
}
/*Start datum telt natuurlijk ook mee*/
$scope.booking.aantalDagen++;
$scope.infomsg +=" aantal dagen: "+$scope.booking.aantalDagen;
};
更好的解决方案
忽略时间部分
如果两个日期相同，则返回0。
function dayDiff(firstDate, secondDate) { firstDate = new Date(firstDate); secondDate = new Date(secondDate); if (!isNaN(firstDate) && !isNaN(secondDate)) { firstDate.setHours(0, 0, 0, 0); //ignore time part secondDate.setHours(0, 0, 0, 0); //ignore time part var dayDiff = secondDate - firstDate; dayDiff = dayDiff / 86400000; // divide by milisec in one day console.log(dayDiff); } else { console.log("Enter valid date."); } } $(document).ready(function() { $('input[type=datetime]').datepicker({ dateFormat: "mm/dd/yy", changeMonth: true, changeYear: true }); $("#button").click(function() { dayDiff($('#first').val(), $('#second').val()); }); }); <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <link rel="stylesheet" href="//code.jquery.com/ui/1.12.1/themes/base/jquery-ui.css"> <script src="//code.jquery.com/ui/1.12.1/jquery-ui.js"></script> <input type="datetime" id="first" value="12/28/2016" /> <input type="datetime" id="second" value="12/28/2017" /> <input type="button" id="button" value="Calculate">
区分两个日期的最简单方法是:
var diff = Math.floor((Date.parse(str2) - Date.parse(str1)) / 86400000);
您将得到不同的天数(如果其中一个或两个都无法解析，则为NaN)。解析日期给出了以毫秒为单位的结果，要按天得到它，你必须除以24 * 60 * 60 * 1000
如果你想用天、小时、分钟、秒和毫秒来划分:
function dateDiff( str1, str2 ) {
var diff = Date.parse( str2 ) - Date.parse( str1 );
return isNaN( diff ) ? NaN : {
diff : diff,
ms : Math.floor( diff % 1000 ),
s : Math.floor( diff / 1000 % 60 ),
m : Math.floor( diff / 60000 % 60 ),
h : Math.floor( diff / 3600000 % 24 ),
d : Math.floor( diff / 86400000 )
};
}
以下是我对James版本的重构版本:
function mydiff(date1,date2,interval) {
var second=1000, minute=second*60, hour=minute*60, day=hour*24, week=day*7;
date1 = new Date(date1);
date2 = new Date(date2);
var timediff = date2 - date1;
if (isNaN(timediff)) return NaN;
switch (interval) {
case "years": return date2.getFullYear() - date1.getFullYear();
case "months": return (
( date2.getFullYear() * 12 + date2.getMonth() )
-
( date1.getFullYear() * 12 + date1.getMonth() )
);
case "weeks" : return Math.floor(timediff / week);
case "days" : return Math.floor(timediff / day);
case "hours" : return Math.floor(timediff / hour);
case "minutes": return Math.floor(timediff / minute);
case "seconds": return Math.floor(timediff / second);
default: return undefined;
}
}
使用Moment.js
Var future = moment('05/02/2015'); Var start = moment('04/23/2015'); Var d =未来。diff(开始,“天”);/ / 9 console.log (d); < script src = " https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.17.1/moment-with-locales.min.js " > < /脚本>
我认为解决方案不是100%正确的，我会使用天花板而不是地板，圆形将工作，但这不是正确的操作。
function dateDiff(str1, str2){
var diff = Date.parse(str2) - Date.parse(str1);
return isNaN(diff) ? NaN : {
diff: diff,
ms: Math.ceil(diff % 1000),
s: Math.ceil(diff / 1000 % 60),
m: Math.ceil(diff / 60000 % 60),
h: Math.ceil(diff / 3600000 % 24),
d: Math.ceil(diff / 86400000)
};
}
