我刚刚在c# 2.0中写了一个字符串反向函数(即LINQ不可用),然后想到了这个:

public string Reverse(string text)
{
    char[] cArray = text.ToCharArray();
    string reverse = String.Empty;
    for (int i = cArray.Length - 1; i > -1; i--)
    {
        reverse += cArray[i];
    }
    return reverse;
}

就我个人而言,我并不喜欢这个功能,我相信有更好的方法来实现它。是吗?


当前回答

private static string Reverse(string str)
        {
            string revStr = string.Empty;
            for (int i = str.Length - 1; i >= 0; i--)
            {
                revStr += str[i].ToString();
            }
            return revStr;
        }

比上述方法快

private static string ReverseEx(string str)
        {
            char[] chrArray = str.ToCharArray();
            int len = chrArray.Length - 1;
            char rev = 'n';
            for (int i = 0; i <= len/2; i++)
            {
                rev = chrArray[i];
                chrArray[i] = chrArray[len - i];
                chrArray[len - i] = rev;
            }
            return new string(chrArray);
        }

其他回答

Greg Beech发布了一个不安全的选项,它确实很快(这是一个原地逆转);但是,正如他在回答中指出的那样,这完全是一个灾难性的想法。

也就是说,我很惊讶有这么多的共识,Array。逆向是最快的方法。仍然有一种不安全的方法,它返回字符串的反向副本(没有原地反转的恶作剧),比Array快得多。小字符串的反向方法:

public static unsafe string Reverse(string text)
{
    int len = text.Length;

    // Why allocate a char[] array on the heap when you won't use it
    // outside of this method? Use the stack.
    char* reversed = stackalloc char[len];

    // Avoid bounds-checking performance penalties.
    fixed (char* str = text)
    {
        int i = 0;
        int j = i + len - 1;
        while (i < len)
        {
            reversed[i++] = str[j--];
        }
    }

    // Need to use this overload for the System.String constructor
    // as providing just the char* pointer could result in garbage
    // at the end of the string (no guarantee of null terminator).
    return new string(reversed, 0, len);
}

以下是一些基准测试结果。

您可以看到,相对于Array,性能增益会缩小,然后消失。当字符串变大时,反向方法。然而,对于小型到中型的字符串,很难击败这种方法。

如果你想玩一个非常危险的游戏,那么这是目前为止最快的方法(比Array快4倍左右)。反向方法)。这是使用指针的原地反向。

请注意,我真的不建议在任何情况下使用这个方法(在这里看看为什么不应该使用这个方法的一些原因),但有趣的是,它可以做到,而且一旦您打开不安全的代码,字符串就不是真正不可变的。

public static unsafe string Reverse(string text)
{
    if (string.IsNullOrEmpty(text))
    {
        return text;
    }

    fixed (char* pText = text)
    {
        char* pStart = pText;
        char* pEnd = pText + text.Length - 1;
        for (int i = text.Length / 2; i >= 0; i--)
        {
            char temp = *pStart;
            *pStart++ = *pEnd;
            *pEnd-- = temp;
        }

        return text;
    }
}

反转字符串,甚至不使用新字符串。让说

String input  = "Mark Henry";
//Just to convert into char array. One can simply take input in char array.
Char[] array = input.toCharArray(input);
int a = input.length;

for(int i=0; i<(array.length/2 -1) ; i++)
{
    array[i] = array[i] + array[a];
    array[a] = array[i] - array[a];
    array[i] = array[i] - array[a--];
}

这是一个非常棘手的问题。

我推荐使用Array。大多数情况下是反向的,因为它是原生编码的,维护和理解非常简单。

在我测试的所有情况下,它似乎都优于StringBuilder。

public string Reverse(string text)
{
   if (text == null) return null;

   // this was posted by petebob as well 
   char[] array = text.ToCharArray();
   Array.Reverse(array);
   return new String(array);
}

对于特定长度的字符串,使用Xor的第二种方法更快。

    public static string ReverseXor(string s)
    {
        if (s == null) return null;
        char[] charArray = s.ToCharArray();
        int len = s.Length - 1;

        for (int i = 0; i < len; i++, len--)
        {
            charArray[i] ^= charArray[len];
            charArray[len] ^= charArray[i];
            charArray[i] ^= charArray[len];
        }

        return new string(charArray);
    }

注意:如果你想支持完整的Unicode UTF16字符集,请阅读此。而是使用那里的实现。它可以通过使用上述算法之一进一步优化,并在反转字符后遍历字符串以清理它。

下面是StringBuilder和Array之间的性能比较。逆向和异或法。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Diagnostics;

namespace ConsoleApplication4
{
    class Program
    {
        delegate string StringDelegate(string s);

        static void Benchmark(string description, StringDelegate d, int times, string text)
        {
            Stopwatch sw = new Stopwatch();
            sw.Start();
            for (int j = 0; j < times; j++)
            {
                d(text);
            }
            sw.Stop();
            Console.WriteLine("{0} Ticks {1} : called {2} times.", sw.ElapsedTicks, description, times);
        }

        public static string ReverseXor(string s)
        {
            char[] charArray = s.ToCharArray();
            int len = s.Length - 1;

            for (int i = 0; i < len; i++, len--)
            {
                charArray[i] ^= charArray[len];
                charArray[len] ^= charArray[i];
                charArray[i] ^= charArray[len];
            }

            return new string(charArray);
        }

        public static string ReverseSB(string text)
        {
            StringBuilder builder = new StringBuilder(text.Length);
            for (int i = text.Length - 1; i >= 0; i--)
            {
                builder.Append(text[i]);
            }
            return builder.ToString();
        }

        public static string ReverseArray(string text)
        {
            char[] array = text.ToCharArray();
            Array.Reverse(array);
            return (new string(array));
        }

        public static string StringOfLength(int length)
        {
            Random random = new Random();
            StringBuilder sb = new StringBuilder();
            for (int i = 0; i < length; i++)
            {
                sb.Append(Convert.ToChar(Convert.ToInt32(Math.Floor(26 * random.NextDouble() + 65))));
            }
            return sb.ToString();
        }

        static void Main(string[] args)
        {

            int[] lengths = new int[] {1,10,15,25,50,75,100,1000,100000};

            foreach (int l in lengths)
            {
                int iterations = 10000;
                string text = StringOfLength(l);
                Benchmark(String.Format("String Builder (Length: {0})", l), ReverseSB, iterations, text);
                Benchmark(String.Format("Array.Reverse (Length: {0})", l), ReverseArray, iterations, text);
                Benchmark(String.Format("Xor (Length: {0})", l), ReverseXor, iterations, text);

                Console.WriteLine();    
            }

            Console.Read();
        }
    }
}

以下是调查结果:

26251 Ticks String Builder (Length: 1) : called 10000 times.
33373 Ticks Array.Reverse (Length: 1) : called 10000 times.
20162 Ticks Xor (Length: 1) : called 10000 times.

51321 Ticks String Builder (Length: 10) : called 10000 times.
37105 Ticks Array.Reverse (Length: 10) : called 10000 times.
23974 Ticks Xor (Length: 10) : called 10000 times.

66570 Ticks String Builder (Length: 15) : called 10000 times.
26027 Ticks Array.Reverse (Length: 15) : called 10000 times.
24017 Ticks Xor (Length: 15) : called 10000 times.

101609 Ticks String Builder (Length: 25) : called 10000 times.
28472 Ticks Array.Reverse (Length: 25) : called 10000 times.
35355 Ticks Xor (Length: 25) : called 10000 times.

161601 Ticks String Builder (Length: 50) : called 10000 times.
35839 Ticks Array.Reverse (Length: 50) : called 10000 times.
51185 Ticks Xor (Length: 50) : called 10000 times.

230898 Ticks String Builder (Length: 75) : called 10000 times.
40628 Ticks Array.Reverse (Length: 75) : called 10000 times.
78906 Ticks Xor (Length: 75) : called 10000 times.

312017 Ticks String Builder (Length: 100) : called 10000 times.
52225 Ticks Array.Reverse (Length: 100) : called 10000 times.
110195 Ticks Xor (Length: 100) : called 10000 times.

2970691 Ticks String Builder (Length: 1000) : called 10000 times.
292094 Ticks Array.Reverse (Length: 1000) : called 10000 times.
846585 Ticks Xor (Length: 1000) : called 10000 times.

305564115 Ticks String Builder (Length: 100000) : called 10000 times.
74884495 Ticks Array.Reverse (Length: 100000) : called 10000 times.
125409674 Ticks Xor (Length: 100000) : called 10000 times.

对于短字符串,Xor似乎更快。

使用Substring怎么样

static string ReverseString(string text)
{
    string sub = "";
    int indexCount = text.Length - 1;
    for (int i = indexCount; i > -1; i--)
    {
        sub = sub + text.Substring(i, 1);
    }
    return sub;
}