2023年末

我的实现

def obj_to_dict(obj, remove=['_sa_instance_state'], debug=False):
    result = {}

    if type(obj).__name__ == "Row":
        return dict(obj)

    obj = obj.__dict__
    for key in obj:
        if key in remove:
            continue

        result[key] = obj[key]

    if debug:
        print(result)

    return result

虽然这是一篇老文章，也许我没有回答上面的问题，但我想谈谈我的连载，至少它对我有用。

我使用FastAPI,SqlAlchemy和MySQL，但我不使用orm模型;

# from sqlalchemy import create_engine
# from sqlalchemy.orm import sessionmaker
# engine = create_engine(config.SQLALCHEMY_DATABASE_URL, pool_pre_ping=True)
# SessionLocal = sessionmaker(autocommit=False, autoflush=False, bind=engine)

序列化代码

import decimal
import datetime


def alchemy_encoder(obj):
    """JSON encoder function for SQLAlchemy special classes."""
    if isinstance(obj, datetime.date):
        return obj.strftime("%Y-%m-%d %H:%M:%S")
    elif isinstance(obj, decimal.Decimal):
        return float(obj)

import json
from sqlalchemy import text

# db is SessionLocal() object 

app_sql = 'SELECT * FROM app_info ORDER BY app_id LIMIT :page,:page_size'

# The next two are the parameters passed in
page = 1
page_size = 10

# execute sql and return a <class 'sqlalchemy.engine.result.ResultProxy'> object
app_list = db.execute(text(app_sql), {'page': page, 'page_size': page_size})

# serialize
res = json.loads(json.dumps([dict(r) for r in app_list], default=alchemy_encoder))

如果不行，请忽略我的回答。我在这里提到它

https://codeandlife.com/2014/12/07/sqlalchemy-results-to-json-the-easy-way/

def alc2json(row):
    return dict([(col, str(getattr(row,col))) for col in row.__table__.columns.keys()])

我想和她玩会儿代码高尔夫。

供参考:我使用automap_base，因为我们有一个根据业务需求单独设计的模式。我今天才开始使用SQLAlchemy，但是文档指出automap_base是declarative_base的扩展，这似乎是SQLAlchemy ORM中的典型范例，所以我相信这应该可以工作。

根据Tjorriemorrie的解决方案，它并没有跟随外键，而是简单地将列与值匹配，并通过str()-ing列值来处理Python类型。我们的值包括Python datetime。时间和小数。十进位类类型的结果，所以它完成了工作。

希望对路人有所帮助!

你可以像这样将RowProxy转换为dict:

 d = dict(row.items())

然后将其序列化为JSON(必须为datetime值等指定编码器) 如果您只想要一条记录(而不是相关记录的完整层次结构)，这并不难。

json.dumps([(dict(row.items())) for row in rs])

下面是一个解决方案，它允许您选择希望在输出中包含的关系。 注意:这是一个完整的重写，将dict/str作为一个参数，而不是一个列表。修复了一些东西..

def deep_dict(self, relations={}):
    """Output a dict of an SA object recursing as deep as you want.

    Takes one argument, relations which is a dictionary of relations we'd
    like to pull out. The relations dict items can be a single relation
    name or deeper relation names connected by sub dicts

    Example:
        Say we have a Person object with a family relationship
            person.deep_dict(relations={'family':None})
        Say the family object has homes as a relation then we can do
            person.deep_dict(relations={'family':{'homes':None}})
            OR
            person.deep_dict(relations={'family':'homes'})
        Say homes has a relation like rooms you can do
            person.deep_dict(relations={'family':{'homes':'rooms'}})
            and so on...
    """
    mydict =  dict((c, str(a)) for c, a in
                    self.__dict__.items() if c != '_sa_instance_state')
    if not relations:
        # just return ourselves
        return mydict

    # otherwise we need to go deeper
    if not isinstance(relations, dict) and not isinstance(relations, str):
        raise Exception("relations should be a dict, it is of type {}".format(type(relations)))

    # got here so check and handle if we were passed a dict
    if isinstance(relations, dict):
        # we were passed deeper info
        for left, right in relations.items():
            myrel = getattr(self, left)
            if isinstance(myrel, list):
                mydict[left] = [rel.deep_dict(relations=right) for rel in myrel]
            else:
                mydict[left] = myrel.deep_dict(relations=right)
    # if we get here check and handle if we were passed a string
    elif isinstance(relations, str):
        # passed a single item
        myrel = getattr(self, relations)
        left = relations
        if isinstance(myrel, list):
            mydict[left] = [rel.deep_dict(relations=None)
                                 for rel in myrel]
        else:
            mydict[left] = myrel.deep_dict(relations=None)

    return mydict

举个关于person/family/homes/rooms的例子…把它转换成json，你只需要

json.dumps(person.deep_dict(relations={'family':{'homes':'rooms'}}))

当使用sqlalchemy连接到db I时，这是一个高度可配置的简单解决方案。使用熊猫。

import pandas as pd
import sqlalchemy

#sqlalchemy engine configuration
engine = sqlalchemy.create_engine....

def my_function():
  #read in from sql directly into a pandas dataframe
  #check the pandas documentation for additional config options
  sql_DF = pd.read_sql_table("table_name", con=engine)

  # "orient" is optional here but allows you to specify the json formatting you require
  sql_json = sql_DF.to_json(orient="index")

  return sql_json