我想用天、小时、分钟、秒、毫秒、纳秒来计算日期差异。我该怎么做呢?
当前回答
var date1 = new Date("06/30/2019");
var date2 = new Date("07/30/2019");
// To calculate the time difference of two dates
var Difference_In_Time = date2.getTime() - date1.getTime();
// To calculate the no. of days between two dates
var Difference_In_Days = Difference_In_Time / (1000 * 3600 * 24);
//To display the final no. of days (result)
document.write("Total number of days between dates <br>"
+ date1 + "<br> and <br>"
+ date2 + " is: <br> "
+ Difference_In_Days);
其他回答
如果你使用的是moment.js,那么查找日期差异就很简单了。
var now = "04/09/2013 15:00:00";
var then = "04/09/2013 14:20:30";
moment.utc(moment(now,"DD/MM/YYYY HH:mm:ss").diff(moment(then,"DD/MM/YYYY HH:mm:ss"))).format("HH:mm:ss")
function daysInMonth (month, year) { return new Date(year, month, 0).getDate(); } function getduration(){ let A= document.getElementById("date1_id").value let B= document.getElementById("date2_id").value let C=Number(A.substring(3,5)) let D=Number(B.substring(3,5)) let dif=D-C let arr=[]; let sum=0; for (let i=0;i<dif+1;i++){ sum+=Number(daysInMonth(i+C,2019)) } let sum_alter=0; for (let i=0;i<dif;i++){ sum_alter+=Number(daysInMonth(i+C,2019)) } let no_of_month=(Number(B.substring(3,5)) - Number(A.substring(3,5))) let days=[]; if ((Number(B.substring(3,5)) - Number(A.substring(3,5)))>0||Number(B.substring(0,2)) - Number(A.substring(0,2))<0){ days=Number(B.substring(0,2)) - Number(A.substring(0,2)) + sum_alter } if ((Number(B.substring(3,5)) == Number(A.substring(3,5)))){ console.log(Number(B.substring(0,2)) - Number(A.substring(0,2)) + sum_alter) } time_1=[]; time_2=[]; let hour=[]; time_1=document.getElementById("time1_id").value time_2=document.getElementById("time2_id").value if (time_1.substring(0,2)=="12"){ time_1="00:00:00 PM" } if (time_1.substring(9,11)==time_2.substring(9,11)){ hour=Math.abs(Number(time_2.substring(0,2)) - Number(time_1.substring(0,2))) } if (time_1.substring(9,11)!=time_2.substring(9,11)){ hour=Math.abs(Number(time_2.substring(0,2)) - Number(time_1.substring(0,2)))+12 } let min=Math.abs(Number(time_1.substring(3,5))-Number(time_2.substring(3,5))) document.getElementById("duration_id").value=days +" days "+ hour+" hour " + min+" min " } <input type="text" id="date1_id" placeholder="28/05/2019"> <input type="text" id="date2_id" placeholder="29/06/2019"> <br><br> <input type="text" id="time1_id" placeholder="08:01:00 AM"> <input type="text" id="time2_id" placeholder="00:00:00 PM"> <br><br> <button class="text" onClick="getduration()">Submit </button> <br><br> <input type="text" id="duration_id" placeholder="days hour min">
另一种解决方案是将difference转换为一个新的Date对象,并获得该日期的年(与1970年不同)、月、日等。
var date1 = new Date(2010, 6, 17);
var date2 = new Date(2013, 12, 18);
var diff = new Date(date2.getTime() - date1.getTime());
// diff is: Thu Jul 05 1973 04:00:00 GMT+0300 (EEST)
console.log(diff.getUTCFullYear() - 1970); // Gives difference as year
// 3
console.log(diff.getUTCMonth()); // Gives month count of difference
// 6
console.log(diff.getUTCDate() - 1); // Gives day count of difference
// 4
所以差异就像“3年6个月零4天”。如果你想以一种人类可读的风格呈现不同,这将对你有所帮助。
可以是有用的:
const date_diff = (date1, date2) => Math.ceil(Math.abs(date1 - date2)/24 * 60 * 60 * 1000)
or
const date_diff = (date1, date2) => Math.ceil(Math.abs(date1 - date2)/86400000)
24 * 60 * 60 * 1000在一天内(天*分*秒*毫秒)= 86400000毫秒
谢谢你!
var date1 = new Date("06/30/2019");
var date2 = new Date("07/30/2019");
// To calculate the time difference of two dates
var Difference_In_Time = date2.getTime() - date1.getTime();
// To calculate the no. of days between two dates
var Difference_In_Days = Difference_In_Time / (1000 * 3600 * 24);
//To display the final no. of days (result)
document.write("Total number of days between dates <br>"
+ date1 + "<br> and <br>"
+ date2 + " is: <br> "
+ Difference_In_Days);