您可以使用String类中的两个方法。

string .contains()检查字符串是否包含指定的char值序列 string . indexof()返回字符串中第一次出现指定字符或子字符串的索引，如果没有找到该字符则返回-1(此方法有4种变体)

方法1:

String myString = "foobar";
if (myString.contains("x") {
    // Do something.
}

方法2:

String myString = "foobar";
if (myString.indexOf("x") >= 0 {
    // Do something.
}

链接作者:Zach Scrivena

要检查字符串中是否存在某些东西，您至少需要查看字符串中的每个字符。所以即使你没有显式地使用循环，它也会有同样的效率。也就是说，您可以尝试使用str.contains(""+char)。

string .contains()检查字符串是否包含指定的char值序列 string . indexof()返回字符串中第一次出现指定字符或子字符串的索引(此方法有4种变体)

String temp = "abcdefghi";
if(temp.indexOf("b")!=-1)
{
   System.out.println("there is 'b' in temp string");
}
else
{
   System.out.println("there is no 'b' in temp string");
}

static String removeOccurences(String a, String b)
{
    StringBuilder s2 = new StringBuilder(a);

    for(int i=0;i<b.length();i++){
        char ch = b.charAt(i);  
        System.out.println(ch+"  first index"+a.indexOf(ch));

        int lastind = a.lastIndexOf(ch);

    for(int k=new String(s2).indexOf(ch);k > 0;k=new String(s2).indexOf(ch)){
            if(s2.charAt(k) == ch){
                s2.deleteCharAt(k);
        System.out.println("val of s2 :             "+s2.toString());
            }
        }
      }

    System.out.println(s1.toString());

    return (s1.toString());
}

you can use this code. It will check the char is present or not. If it is present then the return value is >= 0 otherwise it's -1. Here I am printing alphabets that is not present in the input.

import java.util.Scanner;

public class Test {

public static void letters()
{
    System.out.println("Enter input char");
    Scanner sc = new Scanner(System.in);
    String input = sc.next();
    System.out.println("Output : ");
    for (char alphabet = 'A'; alphabet <= 'Z'; alphabet++) {
            if(input.toUpperCase().indexOf(alphabet) < 0) 
                System.out.print(alphabet + " ");
    }
}
public static void main(String[] args) {
    letters();
}

}

//Ouput Example
Enter input char
nandu
Output : 
B C E F G H I J K L M O P Q R S T V W X Y Z