我正在用PHP构建一个REST web服务客户端,目前我正在使用curl向服务发出请求。

我如何使用curl进行身份验证(http基本)请求?我必须自己添加标题吗?


当前回答

市面上有多种REST框架。我强烈建议你看看Slim mini Framework for PHP 以下是其他一些公司的名单。

其他回答

最简单、最自然的方法是直接使用CURL。

这对我来说很管用:

<?php
$login = 'login';
$password = 'password';
$url = 'http://your.url';
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC);
curl_setopt($ch, CURLOPT_USERPWD, "$login:$password");
$result = curl_exec($ch);
curl_close($ch);  
echo($result);

CURLOPT_USERPWD基本上发送user:password字符串的base64,带有http头,如下所示:

Authorization: Basic dXNlcjpwYXNzd29yZA==

所以除了CURLOPT_USERPWD之外,你还可以使用HTTP-Request头选项,就像下面的其他头一样:

$headers = array(
    'Content-Type:application/json',
    'Authorization: Basic '. base64_encode("user:password") // <---
);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);

Michael Dowling的《Guzzle》便是一个不错的选择。除了优雅的接口、异步调用和符合PSR,它还使REST调用的身份验证头非常简单:

// Create a client with a base URL
$client = new GuzzleHttp\Client(['base_url' => 'http://myservices.io']);

// Send a request to http://myservices.io/status with basic authentication
$response = $client->get('/status', ['auth' => ['username', 'password']]);

去看医生。

你只需要指定CURLOPT_HTTPAUTH和CURLOPT_USERPWD选项:

$curlHandler = curl_init();

$userName = 'postman';
$password = 'password';

curl_setopt_array($curlHandler, [
    CURLOPT_URL => 'https://postman-echo.com/basic-auth',
    CURLOPT_RETURNTRANSFER => true,

    CURLOPT_HTTPAUTH => CURLAUTH_BASIC,
    CURLOPT_USERPWD => $userName . ':' . $password,
]);

$response = curl_exec($curlHandler);
curl_close($curlHandler);

或者指定头文件:

$curlSecondHandler = curl_init();

curl_setopt_array($curlSecondHandler, [
    CURLOPT_URL => 'https://postman-echo.com/basic-auth',
    CURLOPT_RETURNTRANSFER => true,

    CURLOPT_HTTPHEADER => [
        'Authorization: Basic ' . base64_encode($userName . ':' . $password)
    ],
]);

$response = curl_exec($curlSecondHandler);
curl_close($curlSecondHandler);

狂饮的例子:

use GuzzleHttp\Client;
use GuzzleHttp\RequestOptions;

$userName = 'postman';
$password = 'password';

$httpClient = new Client();

$response = $httpClient->get(
    'https://postman-echo.com/basic-auth',
    [
        RequestOptions::AUTH => [$userName, $password]
    ]
);

print_r($response->getBody()->getContents());

看到https://github.com/andriichuk/php-curl-cookbook基本认证

如果授权类型是基本认证,并且发布的数据是json,那么这样做

<?php

$data = array("username" => "test"); // data u want to post                                                                   
$data_string = json_encode($data);                                                                                   
 $api_key = "your_api_key";   
 $password = "xxxxxx";                                                                                                                 
$ch = curl_init(); 
curl_setopt($ch, CURLOPT_URL, "https://xxxxxxxxxxxxxxxxxxxxxxx");    
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 20);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");  
curl_setopt($ch, CURLOPT_POST, true);                                                                   
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);                                                                  
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);     
curl_setopt($ch, CURLOPT_USERPWD, $api_key.':'.$password);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC); 
curl_setopt($ch, CURLOPT_HTTPHEADER, array(   
    'Accept: application/json',
    'Content-Type: application/json')                                                           
);             

if(curl_exec($ch) === false)
{
    echo 'Curl error: ' . curl_error($ch);
}                                                                                                      
$errors = curl_error($ch);                                                                                                            
$result = curl_exec($ch);
$returnCode = (int)curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch);  
echo $returnCode;
var_dump($errors);
print_r(json_decode($result, true));