就像这样做

NSString * strCheck = @"A\nB";

strCheck = [strCheck stringByReplacingOccurrencesOfString:@"\\n" withString:@"\n"];  //This is to prevent for fetching string from plist or data structure

label.numberOfLines = 0;

label.lineBreakMode = NSLineBreakByWordWrapping;

label.text = strCheck;

在Xcode 6上，我可以在swift编程上使用\n没有问题

//不要忘记将numberolines设置为0

UILabel* locationTitle = [[UILabel alloc] initWithFrame:CGRectMake(5, 30, 230, 40)];
locationTitle.font = [UIFont systemFontOfSize:13.0];
locationTitle.numberOfLines = 0;
locationTitle.text = [NSString stringWithFormat:@"Eaton industries pvt. Ltd \nUK Apr 12"];
[cell addSubview:locationTitle];

在xCode 11, Swift 5的\n工作良好，尝试以下代码:

textlabel.numberOfLines = 0
textlabel.text = "This is line one \n This is line two \n This is line three"

对于那些想要一个简单的解决方案的人，请在Interface Builder中的文本标签输入框中执行以下操作:

确保你的行数设置为0。

Alt + Enter

(Alt是你的选项键)

干杯!

对于任何其他人，可能有问题sizeWithFont:constrainedToSize:lineBreakMode:或任何人切换到ios8(该方法已弃用ios7)，我通过使用sizeToFit来调整我的高度。

UILabel *label;
label.numberOfLines = 0;
// Setup label with desired settings
...
[label sizeToFit];
label.frame = CGRectMake(label.frame.origin.x,     // Or use any desired origin
                         label.frame.origin.y, 
                         label.frame.size.width,   // Or use any desired width
                         label.frame.size.height);