对于java.util.Date
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "dd/MM/yyyy")
private Date dateOfBirth;
然后在JSON请求中发送
{ {"dateOfBirth":"01/01/2000"} }
它的工作原理。
我应该如何为Java 8的LocalDate字段这样做??
我试着
@JsonDeserialize(using = LocalDateDeserializer.class)
@JsonSerialize(using = LocalDateSerializer.class)
private LocalDate dateOfBirth;
但是没有成功。
谁能告诉我正确的方法是什么?
下面是依赖关系
<dependency>
<groupId>org.jboss.resteasy</groupId>
<artifactId>jaxrs-api</artifactId>
<version>3.0.9.Final</version>
</dependency>
<dependency>
<groupId>com.fasterxml.jackson.jaxrs</groupId>
<artifactId>jackson-jaxrs-json-provider</artifactId>
<version>2.4.2</version>
</dependency>
<dependency>
<groupId>com.wordnik</groupId>
<artifactId>swagger-annotations</artifactId>
<version>1.3.10</version>
</dependency>
只是更新了克里斯托弗的回答。
从2.6.0版本开始
<dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
<version>2.9.0</version>
</dependency>
使用JavaTimeModule而不是JSR310Module(已弃用)。
@Provider
public class ObjectMapperContextResolver implements ContextResolver<ObjectMapper> {
private final ObjectMapper MAPPER;
public ObjectMapperContextResolver() {
MAPPER = new ObjectMapper();
MAPPER.registerModule(new JavaTimeModule());
MAPPER.configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false);
}
@Override
public ObjectMapper getContext(Class<?> type) {
return MAPPER;
}
}
根据文档，新的JavaTimeModule使用相同的标准设置默认为序列化，不使用Timezone id，而只使用ISO-8601兼容的Timezone偏移量。
可以使用SerializationFeature改变行为。WRITE_DATES_WITH_ZONE_ID
在配置类中定义LocalDateSerializer和LocalDateDeserializer类，并通过JavaTimeModule将它们注册到ObjectMapper，如下所示:
@Configuration
public class AppConfig
{
@Bean
public ObjectMapper objectMapper()
{
ObjectMapper mapper = new ObjectMapper();
mapper.setSerializationInclusion(Include.NON_EMPTY);
//other mapper configs
// Customize de-serialization
JavaTimeModule javaTimeModule = new JavaTimeModule();
javaTimeModule.addSerializer(LocalDate.class, new LocalDateSerializer());
javaTimeModule.addDeserializer(LocalDate.class, new LocalDateDeserializer());
mapper.registerModule(javaTimeModule);
return mapper;
}
public class LocalDateSerializer extends JsonSerializer<LocalDate> {
@Override
public void serialize(LocalDate value, JsonGenerator gen, SerializerProvider serializers) throws IOException {
gen.writeString(value.format(Constant.DATE_TIME_FORMATTER));
}
}
public class LocalDateDeserializer extends JsonDeserializer<LocalDate> {
@Override
public LocalDate deserialize(JsonParser p, DeserializationContext ctxt) throws IOException {
return LocalDate.parse(p.getValueAsString(), Constant.DATE_TIME_FORMATTER);
}
}
}
因为LocalDateSerializer默认将其转换为“[年，月，日]”(json数组)而不是“年-月-日”(json字符串)，并且因为我不想需要任何特殊的ObjectMapper设置(如果禁用SerializationFeature，您可以使LocalDateSerializer生成字符串)。WRITE_DATES_AS_TIMESTAMPS，但这需要额外的设置到您的ObjectMapper)，我使用以下:
进口:
import com.fasterxml.jackson.databind.ser.std.ToStringSerializer;
import com.fasterxml.jackson.datatype.jsr310.deser.LocalDateDeserializer;
代码:
// generates "yyyy-MM-dd" output
@JsonSerialize(using = ToStringSerializer.class)
// handles "yyyy-MM-dd" input just fine (note: "yyyy-M-d" format will not work)
@JsonDeserialize(using = LocalDateDeserializer.class)
private LocalDate localDate;
现在我可以使用new ObjectMapper()来读写我的对象，而不需要任何特殊的设置。
