setDate()在月份边界上有问题，在上面的注释中已经注意到。一个简单的解决方法是使用epoch时间戳来查找日期差异，而不是使用date对象上的方法(令人惊讶地违反直觉)。即。

function getPreviousMonday(fromDate) {
    var dayMillisecs = 24 * 60 * 60 * 1000;

    // Get Date object truncated to date.
    var d = new Date(new Date(fromDate || Date()).toISOString().slice(0, 10));

    // If today is Sunday (day 0) subtract an extra 7 days.
    var dayDiff = d.getDay() === 0 ? 7 : 0;

    // Get date diff in millisecs to avoid setDate() bugs with month boundaries.
    var mondayMillisecs = d.getTime() - (d.getDay() + dayDiff) * dayMillisecs;

    // Return date as YYYY-MM-DD string.
    return new Date(mondayMillisecs).toISOString().slice(0, 10);
}

一周的第一天/最后一天

为了得到即将到来的一周的第一天，你可以这样使用:

函数getUpcomingSunday() { const date = new date (); const today = date.getDate(); const currentDay = date.getDay(); const newDate =日期。setDate(今天- currentDay + 7); return newDate (newDate); ｝ console.log (getUpcomingSunday ());

或者获得最晚的第一天:

函数getLastSunday() { const date = new date (); const today = date.getDate(); const currentDay = date.getDay(); const newDate =日期。setDate(今天- (currentDay || 7)); return newDate (newDate); ｝ console.log (getLastSunday ());

*根据您所在的时区，一周的开始不必从周日开始，它可以从周五、周六、周一或您的机器设置的任何其他日子开始。这些方法可以解释。

*你也可以像这样使用toISOString方法格式化它:

setDate()在月份边界上有问题，在上面的注释中已经注意到。一个简单的解决方法是使用epoch时间戳来查找日期差异，而不是使用date对象上的方法(令人惊讶地违反直觉)。即。

function getPreviousMonday(fromDate) {
    var dayMillisecs = 24 * 60 * 60 * 1000;

    // Get Date object truncated to date.
    var d = new Date(new Date(fromDate || Date()).toISOString().slice(0, 10));

    // If today is Sunday (day 0) subtract an extra 7 days.
    var dayDiff = d.getDay() === 0 ? 7 : 0;

    // Get date diff in millisecs to avoid setDate() bugs with month boundaries.
    var mondayMillisecs = d.getTime() - (d.getDay() + dayDiff) * dayMillisecs;

    // Return date as YYYY-MM-DD string.
    return new Date(mondayMillisecs).toISOString().slice(0, 10);
}

不知道它的性能如何，但这是可行的。

var today = new Date();
var day = today.getDay() || 7; // Get current day number, converting Sun. to 7
if( day !== 1 )                // Only manipulate the date if it isn't Mon.
    today.setHours(-24 * (day - 1));   // Set the hours to day number minus 1
                                         //   multiplied by negative 24
alert(today); // will be Monday

或作为一个函数:

# modifies _date_
function setToMonday( date ) {
    var day = date.getDay() || 7;  
    if( day !== 1 ) 
        date.setHours(-24 * (day - 1)); 
    return date;
}

setToMonday(new Date());

我在用这个

function get_next_week_start() {
   var now = new Date();
   var next_week_start = new Date(now.getFullYear(), now.getMonth(), now.getDate()+(8 - now.getDay()));
   return next_week_start;
}

晚上好,

我更喜欢有一个简单的扩展方法:

Date.prototype.startOfWeek = function (pStartOfWeek) {
    var mDifference = this.getDay() - pStartOfWeek;

    if (mDifference < 0) {
        mDifference += 7;
    }

    return new Date(this.addDays(mDifference * -1));
}

你会注意到这实际上利用了我使用的另一个扩展方法:

Date.prototype.addDays = function (pDays) {
    var mDate = new Date(this.valueOf());
    mDate.setDate(mDate.getDate() + pDays);
    return mDate;
};

现在，如果你的周从周日开始，为pStartOfWeek参数传递一个“0”，如下所示:

var mThisSunday = new Date（）.startOfWeek（0）;

类似地，如果你的周从星期一开始，为pStartOfWeek参数传递一个“1”:

var mThisMonday = new Date（）.startOfWeek（1）;

问候,