SQL Server 2005

SELECT Stuff(
  (SELECT N', ' + Name FROM Names FOR XML PATH(''),TYPE)
  .value('text()[1]','nvarchar(max)'),1,2,N'')

SQL Server 2016

你可以使用FOR JSON语法

即。

SELECT per.ID,
Emails = JSON_VALUE(
   REPLACE(
     (SELECT _ = em.Email FROM Email em WHERE em.Person = per.ID FOR JSON PATH)
    ,'"},{"_":"',', '),'$[0]._'
) 
FROM Person per

结果就会变成

Id  Emails
1   abc@gmail.com
2   NULL
3   def@gmail.com, xyz@gmail.com

即使数据包含无效的XML字符，这也可以工作

的 '"},{"":"' 你是安全的,因为如果数据包含吗 '"},{"":"', 它将逃到 "},{\"_\":\"

你可以用任何字符串分隔符替换'，'

在SQL Server 2017, Azure SQL数据库

您可以使用新的STRING_AGG函数

试试这个查询

SELECT v.VehicleId, v.Name, ll.LocationList
FROM Vehicles v 
LEFT JOIN 
    (SELECT 
     DISTINCT
        VehicleId,
        REPLACE(
            REPLACE(
                REPLACE(
                    (
                        SELECT City as c 
                        FROM Locations x 
                        WHERE x.VehicleID = l.VehicleID FOR XML PATH('')
                    ),    
                    '</c><c>',', '
                 ),
             '<c>',''
            ),
        '</c>', ''
        ) AS LocationList
    FROM Locations l
) ll ON ll.VehicleId = v.VehicleId

如果你正在运行SQL Server 2005，你可以编写一个自定义CLR聚合函数来处理这个问题。

c#版本:

using System;
using System.Data;
using System.Data.SqlClient;
using System.Data.SqlTypes;
using System.Text;
using Microsoft.SqlServer.Server;
[Serializable]
[Microsoft.SqlServer.Server.SqlUserDefinedAggregate(Format.UserDefined,MaxByteSize=8000)]
public class CSV:IBinarySerialize
{
    private StringBuilder Result;
    public void Init() {
        this.Result = new StringBuilder();
    }

    public void Accumulate(SqlString Value) {
        if (Value.IsNull) return;
        this.Result.Append(Value.Value).Append(",");
    }
    public void Merge(CSV Group) {
        this.Result.Append(Group.Result);
    }
    public SqlString Terminate() {
        return new SqlString(this.Result.ToString());
    }
    public void Read(System.IO.BinaryReader r) {
        this.Result = new StringBuilder(r.ReadString());
    }
    public void Write(System.IO.BinaryWriter w) {
        w.Write(this.Result.ToString());
    }
}

如果你使用的是SQL Server 2005，你可以使用FOR XML PATH命令。

SELECT [VehicleID]
     , [Name]
     , (STUFF((SELECT CAST(', ' + [City] AS VARCHAR(MAX)) 
         FROM [Location] 
         WHERE (VehicleID = Vehicle.VehicleID) 
         FOR XML PATH ('')), 1, 2, '')) AS Locations
FROM [Vehicle]

这比使用光标容易得多，而且似乎工作得相当好。

更新

对于那些在新版本的SQL Server中仍然使用这种方法的人来说，还有另一种方法，它更简单，性能更好 自SQL Server 2017以来已经可用的STRING_AGG方法。

SELECT  [VehicleID]
       ,[Name]
       ,(SELECT STRING_AGG([City], ', ')
         FROM [Location]
         WHERE VehicleID = V.VehicleID) AS Locations
FROM   [Vehicle] V

这还允许将不同的分隔符指定为第二个参数，比前一种方法提供了更多的灵活性。

妈妈的答案对我没用，所以我对答案做了一些修改，让它起作用。希望这能帮助到一些人。 使用SQL Server 2012:

SELECT [VehicleID]
     , [Name]
     , STUFF((SELECT DISTINCT ',' + CONVERT(VARCHAR,City) 
         FROM [Location] 
         WHERE (VehicleID = Vehicle.VehicleID) 
         FOR XML PATH ('')), 1, 2, '') AS Locations
FROM [Vehicle]

下面的代码将适用于Sql Server 2000/2005/2008

CREATE FUNCTION fnConcatVehicleCities(@VehicleId SMALLINT)
RETURNS VARCHAR(1000) AS
BEGIN
  DECLARE @csvCities VARCHAR(1000)
  SELECT @csvCities = COALESCE(@csvCities + ', ', '') + COALESCE(City,'')
  FROM Vehicles 
  WHERE VehicleId = @VehicleId 
  return @csvCities
END

-- //Once the User defined function is created then run the below sql

SELECT VehicleID
     , dbo.fnConcatVehicleCities(VehicleId) AS Locations
FROM Vehicles
GROUP BY VehicleID