我们需要YouTube的频道名称的视频列表(使用API)。

我们可以通过下面的API获得一个频道列表(只有频道名):

https://gdata.youtube.com/feeds/api/channels?v=2&q=tendulkar

下面是频道的直接链接

https://www.youtube.com/channel/UCqAEtEr0A0Eo2IVcuWBfB9g

Or

WWW.YouTube.com/channel/HC-8jgBP-4rlI

现在,我们需要>> UCqAEtEr0A0Eo2IVcuWBfB9g或HC-8jgBP-4rlI频道的视频。

我们尝试

https://gdata.youtube.com/feeds/api/videos?v=2&uploader=partner&User=UC7Xayrf2k0NZiz3S04WuDNQ https://gdata.youtube.com/feeds/api/videos?v=2&uploader=partner&q=UC7Xayrf2k0NZiz3S04WuDNQ

但是,这并没有帮助。

我们需要把所有视频发到频道上。上传到一个频道的视频可以来自多个用户,因此我不认为提供用户参数会有帮助…


当前回答

Python中的示例解决方案。从这个视频中得到帮助:视频 与许多其他答案一样,上传id首先从通道id中检索。

import urllib.request
import json

key = "YOUR_YOUTUBE_API_v3_BROWSER_KEY"

#List of channels : mention if you are pasting channel id or username - "id" or "forUsername"
ytids = [["bbcnews","forUsername"],["UCjq4pjKj9X4W9i7UnYShpVg","id"]]

newstitles = []
for ytid,ytparam in ytids:
    urld = "https://www.googleapis.com/youtube/v3/channels?part=contentDetails&"+ytparam+"="+ytid+"&key="+key
    with urllib.request.urlopen(urld) as url:
        datad = json.loads(url.read())
    uploadsdet = datad['items']
    #get upload id from channel id
    uploadid = uploadsdet[0]['contentDetails']['relatedPlaylists']['uploads']

    #retrieve list
    urld = "https://www.googleapis.com/youtube/v3/playlistItems?part=snippet%2CcontentDetails&maxResults=50&playlistId="+uploadid+"&key="+key
    with urllib.request.urlopen(urld) as url:
        datad = json.loads(url.read())

    for data in datad['items']:
        ntitle =  data['snippet']['title']
        nlink = data['contentDetails']['videoId']
        newstitles.append([nlink,ntitle])

for link,title in newstitles:
    print(link, title)

其他回答

下面是返回频道下所有视频id的代码

<?php 
    $baseUrl = 'https://www.googleapis.com/youtube/v3/';
    // https://developers.google.com/youtube/v3/getting-started
    $apiKey = 'API_KEY';
    // If you don't know the channel ID see below
    $channelId = 'CHANNEL_ID';

    $params = [
        'id'=> $channelId,
        'part'=> 'contentDetails',
        'key'=> $apiKey
    ];
    $url = $baseUrl . 'channels?' . http_build_query($params);
    $json = json_decode(file_get_contents($url), true);

    $playlist = $json['items'][0]['contentDetails']['relatedPlaylists']['uploads'];

    $params = [
        'part'=> 'snippet',
        'playlistId' => $playlist,
        'maxResults'=> '50',
        'key'=> $apiKey
    ];
    $url = $baseUrl . 'playlistItems?' . http_build_query($params);
    $json = json_decode(file_get_contents($url), true);

    $videos = [];
    foreach($json['items'] as $video)
        $videos[] = $video['snippet']['resourceId']['videoId'];

    while(isset($json['nextPageToken'])){
        $nextUrl = $url . '&pageToken=' . $json['nextPageToken'];
        $json = json_decode(file_get_contents($nextUrl), true);
        foreach($json['items'] as $video)
            $videos[] = $video['snippet']['resourceId']['videoId'];
    }
    print_r($videos);

注意:你可以在 登录https://www.youtube.com/account_advanced。

Python中的示例解决方案。从这个视频中得到帮助:视频 与许多其他答案一样,上传id首先从通道id中检索。

import urllib.request
import json

key = "YOUR_YOUTUBE_API_v3_BROWSER_KEY"

#List of channels : mention if you are pasting channel id or username - "id" or "forUsername"
ytids = [["bbcnews","forUsername"],["UCjq4pjKj9X4W9i7UnYShpVg","id"]]

newstitles = []
for ytid,ytparam in ytids:
    urld = "https://www.googleapis.com/youtube/v3/channels?part=contentDetails&"+ytparam+"="+ytid+"&key="+key
    with urllib.request.urlopen(urld) as url:
        datad = json.loads(url.read())
    uploadsdet = datad['items']
    #get upload id from channel id
    uploadid = uploadsdet[0]['contentDetails']['relatedPlaylists']['uploads']

    #retrieve list
    urld = "https://www.googleapis.com/youtube/v3/playlistItems?part=snippet%2CcontentDetails&maxResults=50&playlistId="+uploadid+"&key="+key
    with urllib.request.urlopen(urld) as url:
        datad = json.loads(url.read())

    for data in datad['items']:
        ntitle =  data['snippet']['title']
        nlink = data['contentDetails']['videoId']
        newstitles.append([nlink,ntitle])

for link,title in newstitles:
    print(link, title)

使用gapi JavaScript API可以做到这一点

<script src="https://apis.google.com/js/api.js"></script>
const start = () => {
  gapi.client
    .init({
      apiKey: "your_youtubeApiKey",
      discoveryDocs: ["https://www.googleapis.com/discovery/v1/apis/youtube/v3/rest"],
      scope: "https://www.googleapis.com/auth/youtube.readonly",
    })
    .then(() => {
      console.log("gapi.client initiated");
    })
    .then(() =>
      gapi.client.youtube.channels.list({
        part: "snippet,contentDetails,statistics",
        id: "youtube_channelId",
        // forUsername: 'Bankless',
      })
    )
    .then(
      (res) =>
        // get the youtube related playlist id
        res.result.items[0].contentDetails.relatedPlaylists.uploads
    )
    .then((playlistId) =>
      gapi.client.youtube.playlistItems.list({
        part: "snippet",
        playlistId,
        maxResults: 50,
      })
    )
    .then((res) =>
      // get youtube videos snippets
      res.result.items.map((item) => item.snippet)
    )
    .then((snippets) =>
      snippets.map((snippet) => {
        const { title, description, resourceId } = snippet;
        const { videoId } = resourceId;
        return { title, description, videoId };
      })
    )
    .then((videos) => {
      console.log(videos);
    })
    .catch((err) => console.error(err));
};
gapi.load("client", start);

文档:

https://github.com/google/google-api-javascript-client https://developers.google.com/youtube/v3/guides/auth/client-side-web-apps#callinganapi

你需要看看YouTube数据API。您将在那里找到关于如何访问API的文档。您还可以找到客户端库。

你也可以自己提出要求。下面是一个从频道检索最新视频的示例URL:

https://www.googleapis.com/youtube/v3/search?key={your_key_here}&channelId={channel_id_here}&part=snippet,id&order=date&maxResults=20

之后,你会收到一个包含视频id和详细信息的JSON,你可以像这样构建你的视频URL:

http://www.youtube.com/watch?v={video_id_here}

使用已弃用的API版本2,用于上传的URL(通道UCqAEtEr0A0Eo2IVcuWBfB9g)是:

https://gdata.youtube.com/feeds/users/UCqAEtEr0A0Eo2IVcuWBfB9g/uploads

有一个API版本3。