“this”模块的源代码在做什么?

如果你打开一个Python解释器，输入"import this"，如你所知，它会打印:

The Zen of Python, by Tim Peters Beautiful is better than ugly. Explicit is better than implicit. Simple is better than complex. Complex is better than complicated. Flat is better than nested. Sparse is better than dense. Readability counts. Special cases aren't special enough to break the rules. Although practicality beats purity. Errors should never pass silently. Unless explicitly silenced. In the face of ambiguity, refuse the temptation to guess. There should be one-- and preferably only one --obvious way to do it. Although that way may not be obvious at first unless you're Dutch. Now is better than never. Although never is often better than right now. If the implementation is hard to explain, it's a bad idea. If the implementation is easy to explain, it may be a good idea. Namespaces are one honking great idea -- let's do more of those!

在python源代码(Lib/this.py)中，这段文本是由一段奇怪的代码生成的:

s = """Gur Mra bs Clguba, ol Gvz Crgref

Ornhgvshy vf orggre guna htyl.
Rkcyvpvg vf orggre guna vzcyvpvg.
Fvzcyr vf orggre guna pbzcyrk.
Pbzcyrk vf orggre guna pbzcyvpngrq.
Syng vf orggre guna arfgrq.
Fcnefr vf orggre guna qrafr.
Ernqnovyvgl pbhagf.
Fcrpvny pnfrf nera'g fcrpvny rabhtu gb oernx gur ehyrf.
Nygubhtu cenpgvpnyvgl orngf chevgl.
Reebef fubhyq arire cnff fvyragyl.
Hayrff rkcyvpvgyl fvyraprq.
Va gur snpr bs nzovthvgl, ershfr gur grzcgngvba gb thrff.
Gurer fubhyq or bar-- naq cersrenoyl bayl bar --boivbhf jnl gb qb vg.
Nygubhtu gung jnl znl abg or boivbhf ng svefg hayrff lbh'er Qhgpu.
Abj vf orggre guna arire.
Nygubhtu arire vf bsgra orggre guna *evtug* abj.
Vs gur vzcyrzragngvba vf uneq gb rkcynva, vg'f n onq vqrn.
Vs gur vzcyrzragngvba vf rnfl gb rkcynva, vg znl or n tbbq vqrn.
Anzrfcnprf ner bar ubaxvat terng vqrn -- yrg'f qb zber bs gubfr!"""

d = {}
for c in (65, 97):
    for i in range(26):
        d[chr(i+c)] = chr((i+13) % 26 + c)

print "".join([d.get(c, c) for c in s])

当前回答

它使用ROT13编码。使用这个是因为它是一个笑话。

你也可以使用Python函数来解码字符串。

仅限Python 2:

import this
print(this.s.decode('rot13'))

Python 2和3:

import codecs
print(codecs.decode(this.s, 'rot-13'))

2016-09-14 12:09:06

其他回答

如果你想手动或心算ROT13替换，你可以检查一下，因为13*2 = 26(英语字母表的字母数)，它本质上是一个交换:

a <-> n
b <-> o
c <-> p
...
m <-> z

A <-> N
B <-> O
C <-> P
...
M <-> Z

Vs lbh cenpgvfr ybat rabhtu, lbh'yy riraghnyyl znfgre gur Mra bs EBG-13 nytbevguz naq ernq guvf Xyvatba ybbxvat grkgf jvgubhg pbzchgre uryc。

2011-05-02 11:00:12

这是个替换密码，rot13。

2011-05-02 10:00:05

这是一个替换密码(如前所述)。从历史上讲，这是凯撒密码。

https://www.google.de/search?q=caesar+cipher&cad=h

2016-05-25 12:43:56

这被称为rot13编码:

d = {}
for c in (65, 97):
    for i in range(26):
        d[chr(i+c)] = chr((i+13) % 26 + c)

为大写字符(65为大写字符)和小写字符(97为小写字符)构建转换表。

print "".join([d.get(c, c) for c in s])

打印翻译后的字符串。

2011-05-02 10:00:02