最好的转换方式是什么:
['a','b','c']
to:
{
0: 'a',
1: 'b',
2: 'c'
}
最好的转换方式是什么:
['a','b','c']
to:
{
0: 'a',
1: 'b',
2: 'c'
}
当前回答
这不是直接相关的,但我来这里寻找一个合并嵌套对象如一行
const nodes = {
node1: {
interfaces: {if1: {}, if2: {}}
},
node2: {
interfaces: {if3: {}, if4: {}}
},
node3: {
interfaces: {if5: {}, if6: {}}
},
}
解决方案是结合使用reduce和对象扩展:
const allInterfaces = nodes => Object.keys(nodes).reduce((res, key) => ({...res, ...nodes[key].interfaces}), {})
其他回答
import books from "./books.json";
export const getAllBooks = () => {
return {
data: books,
// a=accoumulator, b=book (data itelf), i=index
bookMap: books.reduce((a, book, i) => {
// since we passed {} as initial data, initially a={}
// {bookID1:book1, bookID2:i}
a[book.id] = book;
// you can add new property index
a[book.id].index=i
return a;
// we are passing initial data structure
}, {}),
};
};
初始数组,并将转换为一个对象的键,这将是一个数组的唯一元素,键的值将是具体的键将重复多少次
var jsTechs = ['angular', 'react', 'ember', 'vanilaJS', 'ember', 'angular', 'react', 'ember', 'vanilaJS', 'angular', 'react', 'ember', 'vanilaJS', 'ember', 'angular', 'react', 'ember', 'vanilaJS', 'ember', 'angular', 'react', 'ember', 'vanilaJS', 'ember', 'react', 'react', 'vanilaJS', 'react', 'vanilaJS', 'vanilaJS'] var initialValue = { java : 4 } var reducerFunc = function reducerFunc (initObj, jsLib) { if (!initObj[jsLib]) { initObj[jsLib] = 1 } else { initObj[jsLib] += 1 } return initObj } var finalResult = jsTechs.reduce(reducerFunc, initialValue) console.log(finalResult)
一个快速而肮脏的问题:
var obj = {},
arr = ['a','b','c'],
l = arr.length;
while( l && (obj[--l] = arr.pop() ) ){};
如果你正在使用jquery:
$.extend({}, ['a', 'b', 'c']);
如果你正在使用angularjs,你可以使用angular。Extend,与$的效果相同。jquery的扩展。
var newObj = {};
angular.extend(newObj, ['a','b','c']);