我有一个角foreach循环,我想打破循环,如果我匹配一个值。下面的代码不能工作。
angular.forEach([0,1,2], function(count){
if(count == 1){
break;
}
});
我怎样才能得到这个?
我有一个角foreach循环,我想打破循环,如果我匹配一个值。下面的代码不能工作。
angular.forEach([0,1,2], function(count){
if(count == 1){
break;
}
});
我怎样才能得到这个?
当前回答
使用Return打破循环。
angular.forEach([0,1,2], function(count){
if(count == 1) {
return;
}
});
其他回答
var ary = ["JavaScript", "Java", "CoffeeScript", "TypeScript"];
var keepGoing = true;
ary.forEach(function(value, index, _ary) {
console.log(index)
keepGoing = true;
ary.forEach(function(value, index, _ary) {
if(keepGoing){
if(index==2){
keepGoing=false;
}
else{
console.log(value)
}
}
});
});
我会用return代替break。
angular.forEach([0,1,2], function(count){
if(count == 1){
return;
}
});
效果非常好。
你可以用这个:
var count = 0;
var arr = [0,1,2];
for(var i in arr){
if(count == 1) break;
//console.log(arr[i]);
}
这个例子有用。试一试。
var array = [0,1,2];
for( var i = 0, ii = array.length; i < ii; i++){
if(i === 1){
break;
}
}
请使用ForEach的一些或所有实例,
Array.prototype.some:
some is much the same as forEach but it break when the callback returns true
Array.prototype.every:
every is almost identical to some except it's expecting false to break the loop.
例如:
var ary = ["JavaScript", "Java", "CoffeeScript", "TypeScript"];
ary.some(function (value, index, _ary) {
console.log(index + ": " + value);
return value === "JavaScript";
});
每个的例子:
var ary = ["JavaScript", "Java", "CoffeeScript", "TypeScript"];
ary.every(function(value, index, _ary) {
console.log(index + ": " + value);
return value.indexOf("Script") > -1;
});
查找更多信息 http://www.jsnoob.com/2013/11/26/how-to-break-the-foreach/