映射API v3 -设置边界和中心

我最近切换到谷歌Maps API V3。我正在处理一个简单的例子，从数组中绘制标记，但是我不知道如何对标记自动居中和缩放。

我已经搜索了净高和低，包括谷歌自己的文档，但没有找到一个明确的答案。我知道我可以简单地取坐标的平均值，但我如何相应地设置缩放?

function initialize() {
  var myOptions = {
    zoom: 10,
    center: new google.maps.LatLng(-33.9, 151.2),


    mapTypeId: google.maps.MapTypeId.ROADMAP
  }
  var map = new google.maps.Map(document.getElementById("map_canvas"),myOptions);

  setMarkers(map, beaches);
}


var beaches = [
  ['Bondi Beach', -33.890542, 151.274856, 4],
  ['Coogee Beach', -33.423036, 151.259052, 5],
  ['Cronulla Beach', -34.028249, 121.157507, 3],
  ['Manly Beach', -33.80010128657071, 151.28747820854187, 2],
  ['Maroubra Beach', -33.450198, 151.259302, 1]
];

function setMarkers(map, locations) {

  var image = new google.maps.MarkerImage('images/beachflag.png',
      new google.maps.Size(20, 32),
      new google.maps.Point(0,0),
      new google.maps.Point(0, 32));
    var shadow = new google.maps.MarkerImage('images/beachflag_shadow.png',

      new google.maps.Size(37, 32),
      new google.maps.Point(0,0),
      new google.maps.Point(0, 32));


      var lat = map.getCenter().lat(); 
      var lng = map.getCenter().lng();      


  var shape = {
      coord: [1, 1, 1, 20, 18, 20, 18 , 1],
      type: 'poly'
  };
  for (var i = 0; i < locations.length; i++) {
    var beach = locations[i];
    var myLatLng = new google.maps.LatLng(beach[1], beach[2]);
    var marker = new google.maps.Marker({
        position: myLatLng,
        map: map,
        shadow: shadow,
        icon: image,
        shape: shape,
        title: beach[0],
        zIndex: beach[3]
    });
  }
}

当前回答

把所有东西都排序了-请参阅最后几行代码- (bounds.extend(myLatLng);map.fitBounds(范围);

function initialize() {
  var myOptions = {
    zoom: 10,
    center: new google.maps.LatLng(0, 0),
    mapTypeId: google.maps.MapTypeId.ROADMAP
  }
  var map = new google.maps.Map(
    document.getElementById("map_canvas"),
    myOptions);
  setMarkers(map, beaches);
}

var beaches = [
  ['Bondi Beach', -33.890542, 151.274856, 4],
  ['Coogee Beach', -33.923036, 161.259052, 5],
  ['Cronulla Beach', -36.028249, 153.157507, 3],
  ['Manly Beach', -31.80010128657071, 151.38747820854187, 2],
  ['Maroubra Beach', -33.950198, 151.159302, 1]
];

function setMarkers(map, locations) {
  var image = new google.maps.MarkerImage('images/beachflag.png',
    new google.maps.Size(20, 32),
    new google.maps.Point(0,0),
    new google.maps.Point(0, 32));
  var shadow = new google.maps.MarkerImage('images/beachflag_shadow.png',
    new google.maps.Size(37, 32),
    new google.maps.Point(0,0),
    new google.maps.Point(0, 32));
  var shape = {
    coord: [1, 1, 1, 20, 18, 20, 18 , 1],
    type: 'poly'
  };
  var bounds = new google.maps.LatLngBounds();
  for (var i = 0; i < locations.length; i++) {
    var beach = locations[i];
    var myLatLng = new google.maps.LatLng(beach[1], beach[2]);
    var marker = new google.maps.Marker({
      position: myLatLng,
      map: map,
      shadow: shadow,
      icon: image,
      shape: shape,
      title: beach[0],
      zIndex: beach[3]
    });
    bounds.extend(myLatLng);
  }
  map.fitBounds(bounds);
}

2009-10-13 19:28:17

其他回答

使用以下一种，

map.setCenter (bounds.getCenter (), map.getBoundsZoomLevel(范围);

2010-03-17 15:23:21

是的，您可以声明新的边界对象。

 var bounds = new google.maps.LatLngBounds();

然后对于每个标记，扩展bounds对象:

bounds.extend(myLatLng);
map.fitBounds(bounds);

火:谷歌LatLngBounds映射。

2010-02-05 07:14:28

把所有东西都排序了-请参阅最后几行代码- (bounds.extend(myLatLng);map.fitBounds(范围);

function initialize() {
  var myOptions = {
    zoom: 10,
    center: new google.maps.LatLng(0, 0),
    mapTypeId: google.maps.MapTypeId.ROADMAP
  }
  var map = new google.maps.Map(
    document.getElementById("map_canvas"),
    myOptions);
  setMarkers(map, beaches);
}

var beaches = [
  ['Bondi Beach', -33.890542, 151.274856, 4],
  ['Coogee Beach', -33.923036, 161.259052, 5],
  ['Cronulla Beach', -36.028249, 153.157507, 3],
  ['Manly Beach', -31.80010128657071, 151.38747820854187, 2],
  ['Maroubra Beach', -33.950198, 151.159302, 1]
];

function setMarkers(map, locations) {
  var image = new google.maps.MarkerImage('images/beachflag.png',
    new google.maps.Size(20, 32),
    new google.maps.Point(0,0),
    new google.maps.Point(0, 32));
  var shadow = new google.maps.MarkerImage('images/beachflag_shadow.png',
    new google.maps.Size(37, 32),
    new google.maps.Point(0,0),
    new google.maps.Point(0, 32));
  var shape = {
    coord: [1, 1, 1, 20, 18, 20, 18 , 1],
    type: 'poly'
  };
  var bounds = new google.maps.LatLngBounds();
  for (var i = 0; i < locations.length; i++) {
    var beach = locations[i];
    var myLatLng = new google.maps.LatLng(beach[1], beach[2]);
    var marker = new google.maps.Marker({
      position: myLatLng,
      map: map,
      shadow: shadow,
      icon: image,
      shape: shape,
      title: beach[0],
      zIndex: beach[3]
    });
    bounds.extend(myLatLng);
  }
  map.fitBounds(bounds);
}

2009-10-13 19:28:17

setCenter()方法仍然适用于最新版本的Maps API for Flash，其中fitBounds()不存在。

2010-11-20 22:09:47

我对谷歌maps api v3的建议是(不认为它可以更有效地完成):

gmap : {
    fitBounds: function(bounds, mapId)
    {
        //incoming: bounds - bounds object/array; mapid - map id if it was initialized in global variable before "var maps = [];"
        if (bounds==null) return false;
        maps[mapId].fitBounds(bounds);
    }
}

结果u将适合你的地图窗口内的所有点。

例子工作完美，你可以自由检查这里www.zemelapis.lt

2011-04-19 16:35:30

映射API v3 -设置边界和中心

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