在你的模型和LoginViewModel和RegisterViewModel属性中创建一个新类: 公共类UserDefinedModel() { 属性a1作为LoginViewModel property a2 as RegisterViewModel ｝ 然后在视图中使用UserDefinedModel。

我是否需要创建另一个包含这两个视图的视图?

回答:不

有没有其他的方法，比如(没有BigViewModel):

是的，你可以使用Tuple(在有多个模型的视图中带来魔力)。

代码:

 @model Tuple<LoginViewModel, RegisterViewModel>


    @using (Html.BeginForm("Login", "Auth", FormMethod.Post))
    {
     @Html.TextBoxFor(tuple=> tuple.Item.Name)
     @Html.TextBoxFor(tuple=> tuple.Item.Email)
     @Html.PasswordFor(tuple=> tuple.Item.Password)
    }


    @using (Html.BeginForm("Login", "Auth", FormMethod.Post))
     {
      @Html.TextBoxFor(tuple=> tuple.Item1.Email)
      @Html.PasswordFor(tuple=> tuple.Item1.Password)
     }

一个简单的方法

我们可以先呼叫所有型号

@using project.Models

然后发送你的模型与viewbag

// for list
ViewBag.Name = db.YourModel.ToList();

// for one
ViewBag.Name = db.YourModel.Find(id);

在视图中

// for list
List<YourModel> Name = (List<YourModel>)ViewBag.Name ;

//for one
YourModel Name = (YourModel)ViewBag.Name ;

然后很容易使用这个模型

有很多方法……

with your BigViewModel you do: @model BigViewModel @using(Html.BeginForm()) { @Html.EditorFor(o => o.LoginViewModel.Email) ... } you can create 2 additional views Login.cshtml @model ViewModel.LoginViewModel @using (Html.BeginForm("Login", "Auth", FormMethod.Post)) { @Html.TextBoxFor(model => model.Email) @Html.PasswordFor(model => model.Password) } and register.cshtml same thing after creation you have to render them in the main view and pass them the viewmodel/viewdata so it could be like this: @{Html.RenderPartial("login", ViewBag.Login);} @{Html.RenderPartial("register", ViewBag.Register);} or @{Html.RenderPartial("login", Model.LoginViewModel)} @{Html.RenderPartial("register", Model.RegisterViewModel)} using ajax parts of your web-site become more independent iframes, but probably this is not the case

另一种方法是使用:

@model Tuple<LoginViewModel,RegisterViewModel>

我已经在另一个例子中解释了如何在视图和控制器中使用这个方法:在ASP MVC 3的一个视图中有两个模型

在你的情况下，你可以使用下面的代码来实现它:

在视图中:

@using YourProjectNamespace.Models;
@model Tuple<LoginViewModel,RegisterViewModel>

@using (Html.BeginForm("Login1", "Auth", FormMethod.Post))
{
        @Html.TextBoxFor(tuple => tuple.Item2.Name, new {@Name="Name"})
        @Html.TextBoxFor(tuple => tuple.Item2.Email, new {@Name="Email"})
        @Html.PasswordFor(tuple => tuple.Item2.Password, new {@Name="Password"})
}

@using (Html.BeginForm("Login2", "Auth", FormMethod.Post))
{
        @Html.TextBoxFor(tuple => tuple.Item1.Email, new {@Name="Email"})
        @Html.PasswordFor(tuple => tuple.Item1.Password, new {@Name="Password"})
}

Note that I have manually changed the Name attributes for each property when building the form. This needs to be done, otherwise it wouldn't get properly mapped to the method's parameter of type model when values are sent to the associated method for processing. I would suggest using separate methods to process these forms separately, for this example I used Login1 and Login2 methods. Login1 method requires to have a parameter of type RegisterViewModel and Login2 requires a parameter of type LoginViewModel.

如果需要一个actionlink，你可以使用:

@Html.ActionLink("Edit", "Edit", new { id=Model.Item1.Id })

在控制器的视图方法中，需要创建一个类型为Tuple的变量，然后传递给视图。

例子:

public ActionResult Details()
{
    var tuple = new Tuple<LoginViewModel, RegisterViewModel>(new LoginViewModel(),new RegisterViewModel());
    return View(tuple);
}

或者您可以用值填充LoginViewModel和RegisterViewModel的两个实例，然后将其传递给视图。

在你的模型和LoginViewModel和RegisterViewModel属性中创建一个新类: 公共类UserDefinedModel() { 属性a1作为LoginViewModel property a2 as RegisterViewModel ｝ 然后在视图中使用UserDefinedModel。