我认为问题在于你没有处理os的输出。正确的走路。

首先,改变:

filePath = rootdir + '/' + file

to:

filePath = root + '/' + file

Rootdir是固定的起始目录;Root是os.walk返回的目录。

其次，您不需要缩进您的文件处理循环，因为对每个子目录运行这个没有意义。您将获得每个子目录的根集。您不需要手动处理子目录，除非您想对目录本身做一些事情。

在我看来，os.walk()有点太复杂和啰嗦了。你可以做接受的答案清洁:

all_files = [str(f) for f in pathlib.Path(dir_path).glob("**/*") if f.is_file()]

with open(outfile, 'wb') as fout:
    for f in all_files:
        with open(f, 'rb') as fin:
            fout.write(fin.read())
            fout.write(b'\n')

如果你想要一个给定目录下的所有路径的平面列表(比如find。在壳中):

   files = [ 
       os.path.join(parent, name)
       for (parent, subdirs, files) in os.walk(YOUR_DIRECTORY)
       for name in files + subdirs
   ]

若要只包含基本目录下文件的完整路径，请省略+ subdirs。

pathlib库非常适合处理文件。你可以在Path对象上做这样的递归glob。

from pathlib import Path

for elem in Path('/path/to/my/files').rglob('*.*'):
    print(elem)

操作系统。Walk默认情况下执行递归遍历。对于每个dir，它从根目录开始生成一个3元组(dirpath, dirnames, filename)

from os import walk
from os.path import splitext, join

def select_files(root, files):
    """
    simple logic here to filter out interesting files
    .py files in this example
    """

    selected_files = []

    for file in files:
        #do concatenation here to get full path 
        full_path = join(root, file)
        ext = splitext(file)[1]

        if ext == ".py":
            selected_files.append(full_path)

    return selected_files

def build_recursive_dir_tree(path):
    """
    path    -    where to begin folder scan
    """
    selected_files = []

    for root, dirs, files in walk(path):
        selected_files += select_files(root, files)

    return selected_files

同意Dave Webb的观点。Walk将为树中的每个目录生成一个项。事实上，您不需要关心子文件夹。

这样的代码应该可以工作:

import os
import sys

rootdir = sys.argv[1]

for folder, subs, files in os.walk(rootdir):
    with open(os.path.join(folder, 'python-outfile.txt'), 'w') as dest:
        for filename in files:
            with open(os.path.join(folder, filename), 'r') as src:
                dest.write(src.read())