什么是最简单(最好)的方法来找到一个数组的整数和在swift? 我有一个数组叫multiples我想知道这些倍数的和。
当前回答
@IBOutlet var valueSource: [MultipleIntBoundSource]!
private var allFieldsCount: Int {
var sum = 0
valueSource.forEach { sum += $0.count }
return sum
}
用于嵌套参数
其他回答
对我来说，这就像使用财产
let blueKills = match.blueTeam.participants.reduce(0, { (result, participant) -> Int in
result + participant.kills
})
Swift 4示例
class Employee {
var salary: Int = 0
init (_ salary: Int){
self.salary = salary
}
}
let employees = [Employee(100),Employee(300),Employee(600)]
var sumSalary = employees.reduce(0, {$0 + $1.salary}) //1000
Swift 3+一行求和对象的属性
var totalSum = scaleData.map({$0.points}).reduce(0, +)
哪里点的属性在我的自定义对象scaleData，我试图减少
@IBOutlet var valueSource: [MultipleIntBoundSource]!
private var allFieldsCount: Int {
var sum = 0
valueSource.forEach { sum += $0.count }
return sum
}
用于嵌套参数
斯威夫特3
如果你有一个通用对象的数组，你想对一些对象属性求和，那么:
class A: NSObject {
var value = 0
init(value: Int) {
self.value = value
}
}
let array = [A(value: 2), A(value: 4)]
let sum = array.reduce(0, { $0 + $1.value })
// ^ ^
// $0=result $1=next A object
print(sum) // 6
尽管for-cycle的形式较短，但很多时候你可能更喜欢经典的for-cycle:
let array = [A(value: 2), A(value: 4)]
var sum = 0
array.forEach({ sum += $0.value})
// or
for element in array {
sum += element.value
}
