我想通过分隔符“-”将字符串“004-034556”拆分为两个字符串:
part1 = "004";
part2 = "034556";
这意味着第一个字符串将包含“-”之前的字符,第二个字符串将包括“-”之后的字符。
我还想检查字符串中是否有“-”。
我想通过分隔符“-”将字符串“004-034556”拆分为两个字符串:
part1 = "004";
part2 = "034556";
这意味着第一个字符串将包含“-”之前的字符,第二个字符串将包括“-”之后的字符。
我还想检查字符串中是否有“-”。
当前回答
使用模式是Java 8。下面是路!!
package com.company;
import java.util.regex.Pattern;
public class umeshtest {
public static void main(String a[]) {
String ss = "I'm Testing and testing the new feature";
Pattern.compile(" ").splitAsStream(ss).forEach(s -> System.out.println(s));
}
}
其他回答
无论是否有任何类型的分隔符,您都可以简单地使用StringTokenizer将字符串拆分为两个或多个部分:
StringTokenizer st = new StringTokenizer("004-034556", "-");
while(st.hasMoreTokens())
{
System.out.println(st.nextToken());
}
你也可以这样做
String concatenated_String="hi^Hello";
String split_string_array[]=concatenated_String.split("\\^");
要拆分字符串,请使用string.split(regex)。查看以下示例:
String data = "004-034556";
String[] output = data.split("-");
System.out.println(output[0]);
System.out.println(output[1]);
输出
004
034556
注:
此拆分(正则表达式)以正则表达式作为参数。记住转义正则表达式特殊字符,如句点/点。
我查看了所有答案,发现所有答案都是第三方许可或基于正则表达式的。
下面是我使用的一个很好的哑实现:
/**
* Separates a string into pieces using
* case-sensitive-non-regex-char-separators.
* <p>
* <code>separate("12-34", '-') = "12", "34"</code><br>
* <code>separate("a-b-", '-') = "a", "b", ""</code>
* <p>
* When the separator is the first character in the string, the first result is
* an empty string. When the separator is the last character in the string the
* last element will be an empty string. One separator after another in the
* string will create an empty.
* <p>
* If no separators are set the source is returned.
* <p>
* This method is very fast, but it does not focus on memory-efficiency. The memory
* consumption is approximately double the size of the string. This method is
* thread-safe but not synchronized.
*
* @param source The string to split, never <code>null</code>.
* @param separator The character to use as splitting.
* @return The mutable array of pieces.
* @throws NullPointerException When the source or separators are <code>null</code>.
*/
public final static String[] separate(String source, char... separator) throws NullPointerException {
String[] resultArray = {};
boolean multiSeparators = separator.length > 1;
if (!multiSeparators) {
if (separator.length == 0) {
return new String[] { source };
}
}
int charIndex = source.length();
int lastSeparator = source.length();
while (charIndex-- > -1) {
if (charIndex < 0 || (multiSeparators ? Arrays.binarySearch(separator, source.charAt(charIndex)) >= 0 : source.charAt(charIndex) == separator[0])) {
String piece = source.substring(charIndex + 1, lastSeparator);
lastSeparator = charIndex;
String[] tmp = new String[resultArray.length + 1];
System.arraycopy(resultArray, 0, tmp, 1, resultArray.length);
tmp[0] = piece;
resultArray = tmp;
}
}
return resultArray;
}
public class SplitTest {
public static String[] split(String text, String delimiter) {
java.util.List<String> parts = new java.util.ArrayList<String>();
text += delimiter;
for (int i = text.indexOf(delimiter), j=0; i != -1;) {
String temp = text.substring(j,i);
if(temp.trim().length() != 0) {
parts.add(temp);
}
j = i + delimiter.length();
i = text.indexOf(delimiter,j);
}
return parts.toArray(new String[0]);
}
public static void main(String[] args) {
String str = "004-034556";
String delimiter = "-";
String result[] = split(str, delimiter);
for(String s:result)
System.out.println(s);
}
}