我想通过分隔符“-”将字符串“004-034556”拆分为两个字符串:

part1 = "004";
part2 = "034556";

这意味着第一个字符串将包含“-”之前的字符,第二个字符串将包括“-”之后的字符。

我还想检查字符串中是否有“-”。


当前回答

使用模式是Java 8。下面是路!!

package com.company;

import java.util.regex.Pattern;

public class umeshtest {

    public static void main(String a[]) {
        String ss = "I'm Testing and testing the new feature";
        Pattern.compile(" ").splitAsStream(ss).forEach(s -> System.out.println(s));
    }
}

其他回答

无论是否有任何类型的分隔符,您都可以简单地使用StringTokenizer将字符串拆分为两个或多个部分:

StringTokenizer st = new StringTokenizer("004-034556", "-");
while(st.hasMoreTokens())
{
    System.out.println(st.nextToken());
}

你也可以这样做

 String concatenated_String="hi^Hello";

 String split_string_array[]=concatenated_String.split("\\^");

要拆分字符串,请使用string.split(regex)。查看以下示例:

String data = "004-034556";
String[] output = data.split("-");
System.out.println(output[0]);
System.out.println(output[1]);

输出

004
034556

注:

此拆分(正则表达式)以正则表达式作为参数。记住转义正则表达式特殊字符,如句点/点。

我查看了所有答案,发现所有答案都是第三方许可或基于正则表达式的。

下面是我使用的一个很好的哑实现:

/**
 * Separates a string into pieces using
 * case-sensitive-non-regex-char-separators.
 * <p>
 * &nbsp;&nbsp;<code>separate("12-34", '-') = "12", "34"</code><br>
 * &nbsp;&nbsp;<code>separate("a-b-", '-') = "a", "b", ""</code>
 * <p>
 * When the separator is the first character in the string, the first result is
 * an empty string. When the separator is the last character in the string the
 * last element will be an empty string. One separator after another in the
 * string will create an empty.
 * <p>
 * If no separators are set the source is returned.
 * <p>
 * This method is very fast, but it does not focus on memory-efficiency. The memory
 * consumption is approximately double the size of the string. This method is
 * thread-safe but not synchronized.
 *
 * @param source    The string to split, never <code>null</code>.
 * @param separator The character to use as splitting.
 * @return The mutable array of pieces.
 * @throws NullPointerException When the source or separators are <code>null</code>.
 */
public final static String[] separate(String source, char... separator) throws NullPointerException {
    String[] resultArray = {};
    boolean multiSeparators = separator.length > 1;
    if (!multiSeparators) {
        if (separator.length == 0) {
            return new String[] { source };
        }
    }
    int charIndex = source.length();
    int lastSeparator = source.length();
    while (charIndex-- > -1) {
        if (charIndex < 0 || (multiSeparators ? Arrays.binarySearch(separator, source.charAt(charIndex)) >= 0 : source.charAt(charIndex) == separator[0])) {
            String piece = source.substring(charIndex + 1, lastSeparator);
            lastSeparator = charIndex;
            String[] tmp = new String[resultArray.length + 1];
            System.arraycopy(resultArray, 0, tmp, 1, resultArray.length);
            tmp[0] = piece;
            resultArray = tmp;
        }
    }
    return resultArray;
}
public class SplitTest {

    public static String[] split(String text, String delimiter) {
        java.util.List<String> parts = new java.util.ArrayList<String>();

        text += delimiter;

        for (int i = text.indexOf(delimiter), j=0; i != -1;) {
            String temp = text.substring(j,i);
            if(temp.trim().length() != 0) {
                parts.add(temp);
            }
            j = i + delimiter.length();
            i = text.indexOf(delimiter,j);
        }

        return parts.toArray(new String[0]);
    }


    public static void main(String[] args) {
        String str = "004-034556";
        String delimiter = "-";
        String result[] = split(str, delimiter);
        for(String s:result)
            System.out.println(s);
    }
}