Java 8：

String[] strArray = {"eins", "zwei", "drei", "vier"};

Set<String> strSet = Arrays.stream(strArray).collect(Collectors.toSet());
System.out.println(strSet);
// [eins, vier, zwei, drei]

使用Guava，您可以做到：

T[] array = ...
Set<T> set = Sets.newHashSet(array);

快速：您可以做到：

// Fixed-size list
List list = Arrays.asList(array);

// Growable list
list = new LinkedList(Arrays.asList(array));

// Duplicate elements are discarded
Set set = new HashSet(Arrays.asList(array));

并反转

// Create an array containing the elements in a list
Object[] objectArray = list.toArray();
MyClass[] array = (MyClass[])list.toArray(new MyClass[list.size()]);

// Create an array containing the elements in a set
objectArray = set.toArray();
array = (MyClass[])set.toArray(new MyClass[set.size()]);

在Eclipse集合中，以下功能将起作用：

Set<Integer> set1 = Sets.mutable.of(1, 2, 3, 4, 5);
Set<Integer> set2 = Sets.mutable.of(new Integer[]{1, 2, 3, 4, 5});
MutableSet<Integer> mutableSet = Sets.mutable.of(1, 2, 3, 4, 5);
ImmutableSet<Integer> immutableSet = Sets.immutable.of(1, 2, 3, 4, 5);

Set<Integer> unmodifiableSet = Sets.mutable.of(1, 2, 3, 4, 5).asUnmodifiable();
Set<Integer> synchronizedSet = Sets.mutable.of(1, 2, 3, 4, 5).asSynchronized();
ImmutableSet<Integer> immutableSet = Sets.mutable.of(1, 2, 3, 4, 5).toImmutable();

注意：我是Eclipse集合的提交人

Varargs也会起作用！

Stream.of(T... values).collect(Collectors.toSet());

new HashSet＜Object＞（Arrays.asList（Object[]a））；

但我认为这会更有效率：

final Set s = new HashSet<Object>();    
for (Object o : a) { s.add(o); }