要指示活动的进度，请尝试以下命令:

while true; do sleep 0.25 && echo -ne "\r\\" && sleep 0.25 && echo -ne "\r|" && sleep 0.25 && echo -ne "\r/" && sleep 0.25 && echo -ne "\r-"; done;

OR

while true; do sleep 0.25 && echo -ne "\rActivity: \\" && sleep 0.25 && echo -ne "\rActivity: |" && sleep 0.25 && echo -ne "\rActivity: /" && sleep 0.25 && echo -ne "\rActivity: -"; done;

OR

while true; do sleep 0.25 && echo -ne "\r" && sleep 0.25 && echo -ne "\r>" && sleep 0.25 && echo -ne "\r>>" && sleep 0.25 && echo -ne "\r>>>"; sleep 0.25 && echo -ne "\r>>>>"; done;

OR

while true; do sleep .25 && echo -ne "\r:Active:" && sleep .25 && echo -ne "\r:aCtive:" && sleep .25 && echo -ne "\r:acTive:" && sleep .25 && echo -ne "\r:actIve:" && sleep .25 && echo -ne "\r:actiVe:" && sleep .25 && echo -ne "\r:activE:"; done;

可以在while循环中使用标志/变量来检查和显示进度的值/范围。

关于这个主题有很多不同的答案，但是当计算文本文件操作的百分比时，使用当前长度/总大小的方式，例如显示ver_big_file的百分比。我建议使用awk来实现这个目的，如下所示:

awk '
    function bar(x){s="";i=0;while (i++ < x) s=s "#";return s}
    BEGIN{
        ("ls -l " ARGV[1]) | getline total;
        split(total,array);
        total=array[5];
    }
    {
        cur+=length($0)+1;
        percent=int(cur / total * 100);
        printf "LINE %s:%s %s%%\r", NR, bar(percent*.8), percent 
    }
    END {print}' very_big_file.json | grep "keyword" | ...

这种方法非常精确，基于流，但只适用于文本文件。

使用Linux命令pv。

如果它在管道中间，它不知道大小，但它给出了速度和总数，从那里你可以计算出它需要多长时间，并得到反馈，这样你就知道它没有挂起。

我需要一个进度条来迭代csv文件中的行。能够将cprn的代码改编成对我有用的东西:

BAR='##############################'
FILL='------------------------------'
totalLines=$(wc -l $file | awk '{print $1}')  # num. lines in file
barLen=30

# --- iterate over lines in csv file ---
count=0
while IFS=, read -r _ col1 col2 col3; do
    # update progress bar
    count=$(($count + 1))
    percent=$((($count * 100 / $totalLines * 100) / 100))
    i=$(($percent * $barLen / 100))
    echo -ne "\r[${BAR:0:$i}${FILL:$i:barLen}] $count/$totalLines ($percent%)"

    # other stuff
    (...)
done <$file

看起来是这样的:

[##----------------------------] 17128/218210 (7%)

你可能也对如何做一个旋转器感兴趣:

我能在Bash中做旋转吗?

Sure! i=1 sp="/-\|" echo -n ' ' while true do printf "\b${sp:i++%${#sp}:1}" done Each time the loop iterates, it displays the next character in the sp string, wrapping around as it reaches the end. (i is the position of the current character to display and ${#sp} is the length of the sp string). The \b string is replaced by a 'backspace' character. Alternatively, you could play with \r to go back to the beginning of the line. If you want it to slow down, put a sleep command inside the loop (after the printf). A POSIX equivalent would be: sp='/-\|' printf ' ' while true; do printf '\b%.1s' "$sp" sp=${sp#?}${sp%???} done If you already have a loop which does a lot of work, you can call the following function at the beginning of each iteration to update the spinner: sp="/-\|" sc=0 spin() { printf "\b${sp:sc++:1}" ((sc==${#sp})) && sc=0 } endspin() { printf "\r%s\n" "$@" } until work_done; do spin some_work ... done endspin

我在寻找比选定的答案更性感的东西，我自己的剧本也是如此。

预览

源

我把它放在github的progress-bar.sh上

progress-bar() {
  local duration=${1}


    already_done() { for ((done=0; done<$elapsed; done++)); do printf "▇"; done }
    remaining() { for ((remain=$elapsed; remain<$duration; remain++)); do printf " "; done }
    percentage() { printf "| %s%%" $(( (($elapsed)*100)/($duration)*100/100 )); }
    clean_line() { printf "\r"; }

  for (( elapsed=1; elapsed<=$duration; elapsed++ )); do
      already_done; remaining; percentage
      sleep 1
      clean_line
  done
  clean_line
}

使用

 progress-bar 100