此函数以字符分隔的数字格式验证字符串日期，例如dd/mm/yyyy、mm/dd/yyyy

/*
Param  : 
1)the date in string data type 
2)[optional - string - default is "/"] the date delimiter, most likely "/" or "-"
3)[optional - int - default is 0] the position of the day component when the date string is broken up via the String.split function (into arrays)
4)[optional - int - default is 1] the position of the month component when the date string is broken up via the String.split function (into arrays)
5)[optional - int - default is 2] the position of the year component when the date string is broken up via the String.split function (into arrays)

Return : a javascript date is returned if the params are OK else null
*/
function IsValidDate(strDate, strDelimiter, iDayPosInArray, iMonthPosInArray, iYearPosInArray) {
    var strDateArr; //a string array to hold constituents day, month, and year components
    var dtDate; //our internal converted date
    var iDay, iMonth, iYear;


    //sanity check 
    //no integer checks are performed on day, month, and year tokens as parsing them below will result in NaN if they're invalid
    if (null == strDate || typeof strDate != "string")
        return null;

    //defaults
    strDelimiter = strDelimiter || "/";
    iDayPosInArray = undefined == iDayPosInArray ? 0 : iDayPosInArray;
    iMonthPosInArray = undefined == iMonthPosInArray ? 1 : iMonthPosInArray;
    iYearPosInArray = undefined == iYearPosInArray ? 2 : iYearPosInArray;

    strDateArr = strDate.split(strDelimiter);

    iDay = parseInt(strDateArr[iDayPosInArray],10);
    iMonth = parseInt(strDateArr[iMonthPosInArray],10) - 1; // Note: months are 0-based
    iYear = parseInt(strDateArr[iYearPosInArray],10);

    dtDate = new Date(
        iYear,
        iMonth, // Note: months are 0-based
        iDay);

    return (!isNaN(dtDate) && dtDate.getFullYear() == iYear && dtDate.getMonth() == iMonth && dtDate.getDate() == iDay) ? dtDate : null; // Note: months are 0-based
}

示例调用：

var strDate="18-01-1971";

if (null == IsValidDate(strDate)) {

  alert("invalid date");
}

NaN是假的。invalidDateObject.valueOf（）为NaN。

const d = new Date('foo');
if (!d.valueOf()) {
  console.error('Not a valid date object');
}
else {
  // act on your validated date object
}

尽管valueOf（）在功能上等同于getTime（），但我觉得在这种情况下更合适。

我有一个解决办法。

const isInvalidDate = (dateString) => JSON.stringify(new Date(dateString)) === 'null';

const invalidDate = new Date('Hello');
console.log(isInvalidDate(invalidDate)); //true

const validDate = new Date('2021/02/08');
console.log(isInvalidDate(validDate)); //false

我很少推荐没有的图书馆。但考虑到目前为止的大量答案，似乎值得指出的是，流行的库“date fns”有一个函数isValid。以下文件摘自其网站：

对于Angular.js项目，您可以使用：

angular.isDate(myDate);

function isValidDate(date) {
  return !! (Object.prototype.toString.call(date) === "[object Date]" && +date);
}