如何让Selenium 2.0等待页面加载?


当前回答

SeleniumWaiter:

import com.google.common.base.Function;
import org.openqa.selenium.By;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.support.ui.WebDriverWait;

public class SeleniumWaiter {

      private WebDriver driver;

      public SeleniumWaiter(WebDriver driver) {
           this.driver = driver;
      }

      public WebElement waitForMe(By locatorname, int timeout){
           WebDriverWait wait = new WebDriverWait(driver, timeout);
           return wait.until(SeleniumWaiter.presenceOfElementLocated(locatorname));
      }

      public static Function<WebDriver, WebElement> presenceOfElementLocated(final By locator) {
            // TODO Auto-generated method stub
            return new Function<WebDriver, WebElement>() {
                 @Override
                 public WebElement apply(WebDriver driver) {
                      return driver.findElement(locator);
                 }
            };
      }
 }

对你来说:

_waiter = new SeleniumWaiter(_driver);

try {
   _waiter.waitForMe(By.xpath("//..."), 10);
} 
catch (Exception e) {
   // Error
}

其他回答

您可以删除系统。线。添加它是为了调试目的。

WebDriver driver_;

public void waitForPageLoad() {

    Wait<WebDriver> wait = new WebDriverWait(driver_, 30);
    wait.until(new Function<WebDriver, Boolean>() {
        public Boolean apply(WebDriver driver) {
            System.out.println("Current Window State       : "
                + String.valueOf(((JavascriptExecutor) driver).executeScript("return document.readyState")));
            return String
                .valueOf(((JavascriptExecutor) driver).executeScript("return document.readyState"))
                .equals("complete");
        }
    });
}

你可以显式地等待一个元素出现在网页上,然后才可以采取任何操作(如element.click()):

driver.get("http://somedomain/url_that_delays_loading");
WebElement myDynamicElement = (new WebDriverWait(driver, 10))
    .until(new ExpectedCondition<WebElement>() {
        @Override
        public WebElement apply(WebDriver d) {
            return d.findElement(By.id("myDynamicElement"));
        }
    }
);

这是我用于类似场景的方法,效果很好。

使用这个函数

public void waitForPageLoad(ChromeDriver d){
        String s="";
        while(!s.equals("complete")){
        s=(String) d.executeScript("return document.readyState");
        try {
            Thread.sleep(1000);
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        }

    }

Imran对Java 7的回答是:

    WebDriverWait wait = new WebDriverWait(driver, 30);

    wait.until(new ExpectedCondition<Boolean>() {
        public Boolean apply(WebDriver wdriver) {
            return ((JavascriptExecutor) driver).executeScript(
                "return document.readyState"
            ).equals("complete");
        }
    });

我使用node + selenium-webdriver(现在的版本是3.5.0)。我所做的是:

var webdriver = require('selenium-webdriver'),
    driver = new webdriver.Builder().forBrowser('chrome').build();
;
driver.wait(driver.executeScript("return document.readyState").then(state => {
  return state === 'complete';
}))