我有一个问题，试图让我的日期滴答旋转在matplotlib。下面是一个小示例程序。如果我试图在最后旋转刻度，刻度不会被旋转。如果我尝试像注释“崩溃”下显示的那样旋转刻度，那么matplot库崩溃了。
只有当x值是日期时才会发生这种情况。如果我在调用avail_plot时用变量t替换变量dates, xticks(rotation=70)调用在avail_plot中工作得很好。
什么好主意吗?
import numpy as np
import matplotlib.pyplot as plt
import datetime as dt
def avail_plot(ax, x, y, label, lcolor):
ax.plot(x,y,'b')
ax.set_ylabel(label, rotation='horizontal', color=lcolor)
ax.get_yaxis().set_ticks([])
#crashes
#plt.xticks(rotation=70)
ax2 = ax.twinx()
ax2.plot(x, [1 for a in y], 'b')
ax2.get_yaxis().set_ticks([])
ax2.set_ylabel('testing')
f, axs = plt.subplots(2, sharex=True, sharey=True)
t = np.arange(0.01, 5, 1)
s1 = np.exp(t)
start = dt.datetime.now()
dates=[]
for val in t:
next_val = start + dt.timedelta(0,val)
dates.append(next_val)
start = next_val
avail_plot(axs[0], dates, s1, 'testing', 'green')
avail_plot(axs[1], dates, s1, 'testing2', 'red')
plt.subplots_adjust(hspace=0, bottom=0.3)
plt.yticks([0.5,],("",""))
#doesn't crash, but does not rotate the xticks
#plt.xticks(rotation=70)
plt.show()
如果您更喜欢非面向对象的方法，可以将plt.xticks(rotation=70)移动到两个avail_plot调用之前，例如
plt.xticks(rotation=70)
avail_plot(axs[0], dates, s1, 'testing', 'green')
avail_plot(axs[1], dates, s1, 'testing2', 'red')
这将在设置标签之前设置旋转属性。因为这里有两个轴，plt。Xticks在你创造了这两个情节后便会感到困惑。当plt。Xticks什么也不做，plt.gca()不会给你想要修改的轴，所以plt.gca()不会给你想要修改的轴。Xticks，作用于当前轴，是行不通的。
对于不使用plt的面向对象方法。你可以用Xticks
plt.setp( axs[1].xaxis.get_majorticklabels(), rotation=70 )
在两次avail_plot调用之后。这将具体地在正确的轴上设置旋转。
另一种对每个标记标签应用水平对齐和旋转的方法是在你想更改的标记标签上执行for循环:
import numpy as np
import matplotlib.pyplot as plt
import datetime as dt
now = dt.datetime.now()
hours = [now + dt.timedelta(minutes=x) for x in range(0,24*60,10)]
days = [now + dt.timedelta(days=x) for x in np.arange(0,30,1/4.)]
hours_value = np.random.random(len(hours))
days_value = np.random.random(len(days))
fig, axs = plt.subplots(2)
fig.subplots_adjust(hspace=0.75)
axs[0].plot(hours,hours_value)
axs[1].plot(days,days_value)
for label in axs[0].get_xmajorticklabels() + axs[1].get_xmajorticklabels():
label.set_rotation(30)
label.set_horizontalalignment("right")
这里有一个例子，如果你想控制大刻度和小刻度的位置:
import numpy as np
import matplotlib.pyplot as plt
import datetime as dt
fig, axs = plt.subplots(2)
fig.subplots_adjust(hspace=0.75)
now = dt.datetime.now()
hours = [now + dt.timedelta(minutes=x) for x in range(0,24*60,10)]
days = [now + dt.timedelta(days=x) for x in np.arange(0,30,1/4.)]
axs[0].plot(hours,np.random.random(len(hours)))
x_major_lct = mpl.dates.AutoDateLocator(minticks=2,maxticks=10, interval_multiples=True)
x_minor_lct = matplotlib.dates.HourLocator(byhour = range(0,25,1))
x_fmt = matplotlib.dates.AutoDateFormatter(x_major_lct)
axs[0].xaxis.set_major_locator(x_major_lct)
axs[0].xaxis.set_minor_locator(x_minor_lct)
axs[0].xaxis.set_major_formatter(x_fmt)
axs[0].set_xlabel("minor ticks set to every hour, major ticks start with 00:00")
axs[1].plot(days,np.random.random(len(days)))
x_major_lct = mpl.dates.AutoDateLocator(minticks=2,maxticks=10, interval_multiples=True)
x_minor_lct = matplotlib.dates.DayLocator(bymonthday = range(0,32,1))
x_fmt = matplotlib.dates.AutoDateFormatter(x_major_lct)
axs[1].xaxis.set_major_locator(x_major_lct)
axs[1].xaxis.set_minor_locator(x_minor_lct)
axs[1].xaxis.set_major_formatter(x_fmt)
axs[1].set_xlabel("minor ticks set to every day, major ticks show first day of month")
for label in axs[0].get_xmajorticklabels() + axs[1].get_xmajorticklabels():
label.set_rotation(30)
label.set_horizontalalignment("right")
