我正在设置一个带有Rails后端的React应用程序。我得到的错误“对象是无效的React子(发现:对象与键{id,名称,信息,created_at, updated_at})。如果你想呈现一组子元素,请使用数组。”

这是我的数据:

[
    {
        "id": 1,
        "name": "Home Page",
        "info": "This little bit of info is being loaded from a Rails 
        API.",
        "created_at": "2018-09-18T16:39:22.184Z",
        "updated_at": "2018-09-18T16:39:22.184Z"
    }
]

我的代码如下:

import React from 'react';

class Home extends React.Component {

  constructor(props) {
    super(props);
    this.state = {
      error: null,
      isLoaded: false,
      homes: []
    };
  }

  componentDidMount() {
    fetch('http://localhost:3000/api/homes')
      .then(res => res.json())
      .then(
        (result) => {
          this.setState({
            isLoaded: true,
            homes: result
          });
        },
        // error handler
        (error) => {
          this.setState({
            isLoaded: true,
            error
          });
        }
      )
  }

  render() {

    const { error, isLoaded, homes } = this.state;

    if (error) {
      return (
        <div className="col">
          Error: {error.message}
        </div>
      );
    } else if (!isLoaded) {
      return (
        <div className="col">
          Loading...
        </div>
      );
    } else {
      return (
        <div className="col">
          <h1>Mi Casa</h1>
          <p>This is my house y'all!</p>
          <p>Stuff: {homes}</p>
        </div>
      );
    }
  }
}

export default Home;

我做错了什么?


当前回答

有同样的问题,在我的情况下 1. 将字符串解析为Json 2. 确保在渲染视图时不试图显示整个对象,而是显示object.value

data = [
{
    "id": 1,
    "name": "Home Page",
    "info": "This little bit of info is being loaded from a Rails 
    API.",
    "created_at": "2018-09-18T16:39:22.184Z",
    "updated_at": "2018-09-18T16:39:22.184Z"
}];
var jsonData = JSON.parse(data)

然后是我的观点

return (
<View style={styles.container}>
  <FlatList
    data={jsonData}
    renderItem={({ item }) => <Item title={item.name} />}
    keyExtractor={item => item.id}
  />
</View>);

因为我使用数组,我使用平面列表来显示,并确保我与对象一起工作。值,而不是对象,否则你会遇到同样的问题

其他回答

为了我的案子

 return (
    <div >
      {updated.map((one) => {
        <div>
          <h2>{one.name}</h2>
        </div>
      })}

    </div>
  );

然后改为

 return (
    <div >
      {updated.map((one,index) => {
        return (
          <div key={index}>
          <h2>{one.name}</h2>
          </div>
        )
      })}

    </div>
  );

问题是在map函数之后没有返回语句

虽然不是特定于答案,但此错误主要发生在在JavaScript上下文中使用{}错误地使用JavaScript表达式时。

例如

let x=5;

export default function App(){ return( {x} ); };

正确的做法是

let x=5;
export default function App(){ return( x ); };

我还捕捉到了另一个场景。要渲染的DOM依赖于一些检查。我用null初始化它,Switch给它赋值。在返回时,返回那个DOM。

export function test() {
  let DOM = null;
  switch (conditions) {
    case 1: {
      DOM = <div>SOME DIV</div>;
    }
    case 2: {
      DOM = <div>SOME DIV2</div>;
    }
    default: {
      DOM = null;
    }
  }
  return { DOM }; // -----1 Problem was here
}

它的分辨率是用<></>来包装它

return <>{DOM}</>

您的数据家是一个数组,因此您必须使用array .prototype.map()迭代数组才能使其工作。

return (
    <div className="col">
      <h1>Mi Casa</h1>
      <p>This is my house y&apos;all!</p>
      {homes.map(home => <div>{home.name}</div>)}
    </div>
  );

我今天得到了同样的错误,但与这个问题中发布的场景相比,情况有所不同。希望下面的解决方案能帮助到一些人。

下面的渲染函数足以理解我的场景和解决方案:

render() {
    let orderDetails = null;
    if(this.props.loading){
        orderDetails = <Spinner />;
    }
    if(this.props.orders.length == 0){
        orderDetails = null;
    }
    orderDetails = (
        <div>
            {
                this.props.orders && 
                this.props.orders.length > 0 && 
                this.props.orders.map(order => (
                <Order 
                    key={order.id}
                    ingredient={order.ingredients}
                    price={order.price} />
                ))
            }
        </div>
    );
    return orderDetails;
}

在上面的代码片段中:如果return orderDetails作为return {orderDetails}发送,那么尽管'orderDetails'的值(值为<Spinner/>或null或与<Order />组件相关的JSX),这个问题中发布的错误仍然会弹出。

错误描述:React -dom.development.js:57未捕获的不变性违规:对象作为React子对象无效(发现:带有键{orderDetails}的对象)。如果要呈现子元素的集合,请使用数组。

我们不能从render()方法内部的返回调用中返回JavaScript对象。原因是React期望一些JSX, false, null, undefined, true在UI中呈现,而不是一些JavaScript对象,当我使用返回{orderDetails}时,我试图呈现,因此得到如上所述的错误。

有效:

<div />

<div></div>

<div>{false}</div>

<div>{null}</div>

<div>{undefined}</div>

<div>{true}</div>

无效:

<div>{orderDetails}</div> // This is WRONG, orderDetails is an object and NOT a valid return value that React expects.

Edit: I also got this error on my company's test server used by QA's for their testing. I pointed my local code to that test server and tested the scenario in which this error was reported by QA team and found NO ERROR in my local machine. I got surprised. I re-checked multiple number of times, re-checked the scenario with QA team and I was doing right but still I was not able to replicate the issue. I consulted my fellow devs but still were not able to figure out the root cause. So keeping with the information in the error message I started scanning all the code I had deployed in my last deployment commit ( to be more specific last 4-5 commits because I suspected it could be there from last few deployments but was caught in the current deployment), especially all the components I had developed and found that there was a component - inside which there was no specified condition being met so it was returning NOTHING from it. So see below sample pseudo code. I hope it helps.

render () {
return (
    {this.props.condition1 && (
       return some jsx 1
    )}

    {this.props.condition1 && (
       return some jsx 2
    )})
}

如果你在上面的伪代码中看到,如果条件1和条件2不满足,那么这个组件将从它呈现NOTHING,理想情况下,react组件必须从它返回一些JSX, false, null, undefined, true。