我正在设置一个带有Rails后端的React应用程序。我得到的错误“对象是无效的React子(发现:对象与键{id,名称,信息,created_at, updated_at})。如果你想呈现一组子元素,请使用数组。”

这是我的数据:

[
    {
        "id": 1,
        "name": "Home Page",
        "info": "This little bit of info is being loaded from a Rails 
        API.",
        "created_at": "2018-09-18T16:39:22.184Z",
        "updated_at": "2018-09-18T16:39:22.184Z"
    }
]

我的代码如下:

import React from 'react';

class Home extends React.Component {

  constructor(props) {
    super(props);
    this.state = {
      error: null,
      isLoaded: false,
      homes: []
    };
  }

  componentDidMount() {
    fetch('http://localhost:3000/api/homes')
      .then(res => res.json())
      .then(
        (result) => {
          this.setState({
            isLoaded: true,
            homes: result
          });
        },
        // error handler
        (error) => {
          this.setState({
            isLoaded: true,
            error
          });
        }
      )
  }

  render() {

    const { error, isLoaded, homes } = this.state;

    if (error) {
      return (
        <div className="col">
          Error: {error.message}
        </div>
      );
    } else if (!isLoaded) {
      return (
        <div className="col">
          Loading...
        </div>
      );
    } else {
      return (
        <div className="col">
          <h1>Mi Casa</h1>
          <p>This is my house y'all!</p>
          <p>Stuff: {homes}</p>
        </div>
      );
    }
  }
}

export default Home;

我做错了什么?


当前回答

我今天得到了同样的错误,但与这个问题中发布的场景相比,情况有所不同。希望下面的解决方案能帮助到一些人。

下面的渲染函数足以理解我的场景和解决方案:

render() {
    let orderDetails = null;
    if(this.props.loading){
        orderDetails = <Spinner />;
    }
    if(this.props.orders.length == 0){
        orderDetails = null;
    }
    orderDetails = (
        <div>
            {
                this.props.orders && 
                this.props.orders.length > 0 && 
                this.props.orders.map(order => (
                <Order 
                    key={order.id}
                    ingredient={order.ingredients}
                    price={order.price} />
                ))
            }
        </div>
    );
    return orderDetails;
}

在上面的代码片段中:如果return orderDetails作为return {orderDetails}发送,那么尽管'orderDetails'的值(值为<Spinner/>或null或与<Order />组件相关的JSX),这个问题中发布的错误仍然会弹出。

错误描述:React -dom.development.js:57未捕获的不变性违规:对象作为React子对象无效(发现:带有键{orderDetails}的对象)。如果要呈现子元素的集合,请使用数组。

我们不能从render()方法内部的返回调用中返回JavaScript对象。原因是React期望一些JSX, false, null, undefined, true在UI中呈现,而不是一些JavaScript对象,当我使用返回{orderDetails}时,我试图呈现,因此得到如上所述的错误。

有效:

<div />

<div></div>

<div>{false}</div>

<div>{null}</div>

<div>{undefined}</div>

<div>{true}</div>

无效:

<div>{orderDetails}</div> // This is WRONG, orderDetails is an object and NOT a valid return value that React expects.

Edit: I also got this error on my company's test server used by QA's for their testing. I pointed my local code to that test server and tested the scenario in which this error was reported by QA team and found NO ERROR in my local machine. I got surprised. I re-checked multiple number of times, re-checked the scenario with QA team and I was doing right but still I was not able to replicate the issue. I consulted my fellow devs but still were not able to figure out the root cause. So keeping with the information in the error message I started scanning all the code I had deployed in my last deployment commit ( to be more specific last 4-5 commits because I suspected it could be there from last few deployments but was caught in the current deployment), especially all the components I had developed and found that there was a component - inside which there was no specified condition being met so it was returning NOTHING from it. So see below sample pseudo code. I hope it helps.

render () {
return (
    {this.props.condition1 && (
       return some jsx 1
    )}

    {this.props.condition1 && (
       return some jsx 2
    )})
}

如果你在上面的伪代码中看到,如果条件1和条件2不满足,那么这个组件将从它呈现NOTHING,理想情况下,react组件必须从它返回一些JSX, false, null, undefined, true。

其他回答

在设置为UseState之前,我在使用BigNumber库的值时出现了这个错误:

const { toBN } = web3.utils;
...
 setOwner0Balance(toBN(await getBalance(owner0)));

在您的状态下,home被初始化为一个数组 家庭:[]

在返回中,尝试呈现home(这是一个数组)。 < p >东西:{家园}< / p >

不能这样做——如果你想渲染它,你需要渲染一个数组到每个单独的项目。例如:使用map()

Ex:{家(item = >)的项目文件夹。

好吧,在我的情况下,我想渲染的数据包含一个对象在数组中,因此,它会给出错误,所以对于其他人来说,请检查你的数据也一次,如果它包含一个对象,你需要将它转换为数组打印它的所有值,或者如果你需要一个特定的值,然后使用。

我的数据:

body: " d fvsdv"
photo: "http://res.cloudinary.com/imvr7/image/upload/v1591563988/hhanfhiyalwnv231oweg.png"
postedby: {_id: "5edbf948cdfafc4e38e74081", name: "vit"}       
//this is the object I am talking about.
title: "c sx "
__v: 0
_id: "5edd56d7e64a9e58acfd499f"
__proto__: Object

只打印单个值

<h5>{item.postedby.name}</h5>

在JavaScript中,数组和集合是不同的,尽管它们有点相似,但在这里react需要一个数组。 您需要从集合中创建一个数组并应用它。

let homeArray = new Array(homes.length);
let i = 0

for (var key in homes) {
    homeArray[i] =  homes[key];
    i = i + 1;
}

我也发生了错误,我通过删除花括号来解决它,希望它能帮助其他人。

你可以看到,我没有把con放在花括号里,错误发生了,当我移除粗括号时,错误消失了。

const modal = (props) => {
const { show, onClose } = props;

let con = <div className="modal" onClick={onClose}>
        {props.children}
        </div>;

return show === true ? (
    {con}
) : (
    <div>hello</div>
);

有一篇文章是关于花括号的用法的。点击这里