我试图创建一个完整的路径,如果它不存在。
代码如下所示:
var fs = require('fs');
if (!fs.existsSync(newDest)) fs.mkdirSync(newDest);
只要只有一个子目录(像'dir1'这样的newDest),这段代码就能很好地工作,但是当有一个目录路径('dir1/dir2')时,它就会失败
错误:ENOENT,没有这样的文件或目录
我希望能够用尽可能少的代码行创建完整的路径。
我读到fs上有一个递归选项,并尝试了这样做
var fs = require('fs');
if (!fs.existsSync(newDest)) fs.mkdirSync(newDest,'0777', true);
我觉得递归地创建一个不存在的目录应该这么简单。我是否遗漏了一些东西,或者我是否需要解析路径并检查每个目录,如果它不存在,则创建它?
我对Node很陌生。也许我使用的是旧版本的FS?
我对fs的递归选项有问题。mkdir,所以我做了一个函数,做以下工作:
Creates a list of all directories, starting with the final target dir and working up to the root parent.
Creates a new list of needed directories for the mkdir function to work
Makes each directory needed, including the final
function createDirectoryIfNotExistsRecursive(dirname) {
return new Promise((resolve, reject) => {
const fs = require('fs');
var slash = '/';
// backward slashes for windows
if(require('os').platform() === 'win32') {
slash = '\\';
}
// initialize directories with final directory
var directories_backwards = [dirname];
var minimize_dir = dirname;
while (minimize_dir = minimize_dir.substring(0, minimize_dir.lastIndexOf(slash))) {
directories_backwards.push(minimize_dir);
}
var directories_needed = [];
//stop on first directory found
for(const d in directories_backwards) {
if(!(fs.existsSync(directories_backwards[d]))) {
directories_needed.push(directories_backwards[d]);
} else {
break;
}
}
//no directories missing
if(!directories_needed.length) {
return resolve();
}
// make all directories in ascending order
var directories_forwards = directories_needed.reverse();
for(const d in directories_forwards) {
fs.mkdirSync(directories_forwards[d]);
}
return resolve();
});
}
递归创建目录的异步方法:
import fs from 'fs'
const mkdirRecursive = function(path, callback) {
let controlledPaths = []
let paths = path.split(
'/' // Put each path in an array
).filter(
p => p != '.' // Skip root path indicator (.)
).reduce((memo, item) => {
// Previous item prepended to each item so we preserve realpaths
const prevItem = memo.length > 0 ? memo.join('/').replace(/\.\//g, '')+'/' : ''
controlledPaths.push('./'+prevItem+item)
return [...memo, './'+prevItem+item]
}, []).map(dir => {
fs.mkdir(dir, err => {
if (err && err.code != 'EEXIST') throw err
// Delete created directory (or skipped) from controlledPath
controlledPaths.splice(controlledPaths.indexOf(dir), 1)
if (controlledPaths.length === 0) {
return callback()
}
})
})
}
// Usage
mkdirRecursive('./photos/recent', () => {
console.log('Directories created succesfully!')
})
您可以使用下一个函数
const recursiveUpload =(路径:字符串)=> {
Const paths = path.split("/")
const fullPath = paths.reduce((accumulator, current) => {
fs.mkdirSync(accumulator)
return `${accumulator}/${current}`
})
fs.mkdirSync(fullPath)
return fullPath
}
它的作用是:
创建路径变量,它将每个路径单独存储为数组的一个元素。
在数组中每个元素的末尾添加"/"。
形成循环:
从索引从0到当前迭代的数组元素的连接中创建一个目录。基本上,它是递归的。
希望有帮助!
顺便说一下,在Node v10.12.0中,可以通过将递归路径创建作为附加参数来使用。
fs。mkdir(“/ tmp / /苹果”,{递归:真},(err) = > {
如果(错误)抛出错误;
});
https://nodejs.org/api/fs.html#fs_fs_mkdirsync_path_options