我想在Python中执行一个curl命令。
通常，我只需要在终端输入命令，然后按回车键。但是，我不知道它在Python中是如何工作的。
命令如下所示:
curl -d @request.json --header "Content-Type: application/json" https://www.googleapis.com/qpxExpress/v1/trips/search?key=mykeyhere
有一个请求。Json文件发送以获得响应。
我找了很多遍，结果搞糊涂了。我试着写了一段代码，尽管我不能完全理解它，它没有工作。
import pycurl
import StringIO
response = StringIO.StringIO()
c = pycurl.Curl()
c.setopt(c.URL, 'https://www.googleapis.com/qpxExpress/v1/trips/search?key=mykeyhere')
c.setopt(c.WRITEFUNCTION, response.write)
c.setopt(c.HTTPHEADER, ['Content-Type: application/json','Accept-Charset: UTF-8'])
c.setopt(c.POSTFIELDS, '@request.json')
c.perform()
c.close()
print response.getvalue()
response.close()
错误消息是“解析错误”。如何正确地从服务器获得响应?
import requests
url = "https://www.googleapis.com/qpxExpress/v1/trips/search?key=mykeyhere"
data = requests.get(url).json
也许?
如果您正在尝试发送文件
files = {'request_file': open('request.json', 'rb')}
r = requests.post(url, files=files)
print r.text, print r.json
啊，谢谢@LukasGraf，现在我更好地理解了他原来的代码是做什么的
import requests,json
url = "https://www.googleapis.com/qpxExpress/v1/trips/search?key=mykeyhere"
my_json_data = json.load(open("request.json"))
req = requests.post(url,data=my_json_data)
print req.text
print
print req.json # maybe?
为了简单起见，您应该考虑使用Requests库。
JSON响应内容的示例如下:
import requests
r = requests.get('https://github.com/timeline.json')
r.json()
如果你想了解更多的信息，在快速入门部分，他们有很多实际的例子。
对于特定的旋度平移:
import requests
url = 'https://www.googleapis.com/qpxExpress/v1/trips/search?key=mykeyhere'
payload = open("request.json")
headers = {'content-type': 'application/json', 'Accept-Charset': 'UTF-8'}
r = requests.post(url, data=payload, headers=headers)
PYTHON 3
仅适用于UNIX (Linux / Mac) (!)
使用Python 3执行cURL并解析其JSON数据。
import shlex
import json
import subprocess
# Make sure that cURL has Silent mode (--silent) activated
# otherwise we receive progress data inside err message later
cURL = r"""curl -X --silent POST http://www.test.testtestest/ -d 'username=test'"""
lCmd = shlex.split(cURL) # Splits cURL into an array
p = subprocess.Popen(lCmd, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
out, err = p.communicate() # Get the output and the err message
json_data = json.loads(out.decode("utf-8"))
print(json_data) # Display now the data
有时你还需要在UNIX上安装这些依赖项，如果你遇到奇怪的错误:
# Dependencies
sudo apt install libcurl4-openssl-dev libssl-dev
sudo apt install curl
curl -d @request.json --header "Content-Type: application/json" https://www.googleapis.com/qpxExpress/v1/trips/search?key=mykeyhere
它的Python实现是这样的:
import requests
headers = {
'Content-Type': 'application/json',
}
params = {
'key': 'mykeyhere',
}
with open('request.json') as f:
data = f.read().replace('\n', '')
response = requests.post('https://www.googleapis.com/qpxExpress/v1/trips/search', params=params, headers=headers, data=data)
检查这个链接，它将帮助将cURL命令转换为Python, PHP和Node.js
