场景:用户点击视图控制器上的按钮。视图控制器是导航堆栈中最顶层的(很明显)。tap调用在另一个类上调用的实用程序类方法。这里发生了不好的事情我想在控件返回到视图控制器之前在那里显示一个警告。
+ (void)myUtilityMethod {
// do stuff
// something bad happened, display an alert.
}
这是可能的UIAlertView(但可能不太合适)。
在这种情况下，你如何在myUtilityMethod中呈现UIAlertController ?
当前回答
斯威夫特5
我刚刚创建了一个新窗口，并在其中添加了警报视图控制器。
查看类TopViewController:
https://gist.github.com/odnaks/3f3fd0d20f318c6276e76d0f9d7de5a7
我使用它很简单，像UIAlertController:
let alert = TopAlertController()
alert.title = "title"
alert.message = "message"
alert.addAction(UIAlertAction(title: "Ок", style: .default, handler: { _ in }))
alert.show()
其他回答
创建helper类AlertWindow并使用as
let alertWindow = AlertWindow();
let alert = UIAlertController(title: "Hello", message: "message", preferredStyle: .alert);
let cancel = UIAlertAction(title: "Ok", style: .cancel){(action) in
//.... action code here
// reference to alertWindow retain it. Every action must have this at end
alertWindow.isHidden = true;
// here AlertWindow.deinit{ }
}
alert.addAction(cancel);
alertWindow.present(alert, animated: true, completion: nil)
class AlertWindow:UIWindow{
convenience init(){
self.init(frame:UIScreen.main.bounds);
}
override init(frame: CGRect) {
super.init(frame: frame);
if let color = UIApplication.shared.delegate?.window??.tintColor {
tintColor = color;
}
rootViewController = UIViewController()
windowLevel = UIWindowLevelAlert + 1;
makeKeyAndVisible()
}
required init?(coder aDecoder: NSCoder) {
fatalError("init(coder:) has not been implemented")
}
deinit{
// semaphor.signal();
}
func present(_ ctrl:UIViewController, animated:Bool, completion: (()->Void)?){
rootViewController!.present(ctrl, animated: animated, completion: completion);
}
}
这在Swift中适用于普通的视图控制器，即使屏幕上有一个导航控制器:
let alert = UIAlertController(...)
let alertWindow = UIWindow(frame: UIScreen.main.bounds)
alertWindow.rootViewController = UIViewController()
alertWindow.windowLevel = UIWindowLevelAlert + 1;
alertWindow.makeKeyAndVisible()
alertWindow.rootViewController?.presentViewController(alert, animated: true, completion: nil)
你可以将当前视图或控制器作为参数发送:
+ (void)myUtilityMethod:(id)controller {
// do stuff
// something bad happened, display an alert.
}
似乎有效:
static UIViewController *viewControllerForView(UIView *view) {
UIResponder *responder = view;
do {
responder = [responder nextResponder];
}
while (responder && ![responder isKindOfClass:[UIViewController class]]);
return (UIViewController *)responder;
}
-(void)showActionSheet {
UIAlertController *alertController = [UIAlertController alertControllerWithTitle:nil message:nil preferredStyle:UIAlertControllerStyleActionSheet];
[alertController addAction:[UIAlertAction actionWithTitle:@"Cancel" style:UIAlertActionStyleCancel handler:nil]];
[alertController addAction:[UIAlertAction actionWithTitle:@"Do it" style:UIAlertActionStyleDefault handler:nil]];
[viewControllerForView(self) presentViewController:alertController animated:YES completion:nil];
}
下面的解决方案没有发挥作用，尽管它在所有版本中看起来都很有前途。这个解决方案正在生成WARNING。
警告:试图显示不在窗口层次结构中的视图!
https://stackoverflow.com/a/34487871/2369867 = > 这在当时看起来很有希望。但在Swift 3中没有。 所以我在Swift 3中回答这个问题，这不是模板示例。
一旦粘贴到任何函数中，这是相当完整的功能代码。
快速Swift 3自包含代码
let alertController = UIAlertController(title: "<your title>", message: "<your message>", preferredStyle: UIAlertControllerStyle.alert)
alertController.addAction(UIAlertAction(title: "Close", style: UIAlertActionStyle.cancel, handler: nil))
let alertWindow = UIWindow(frame: UIScreen.main.bounds)
alertWindow.rootViewController = UIViewController()
alertWindow.windowLevel = UIWindowLevelAlert + 1;
alertWindow.makeKeyAndVisible()
alertWindow.rootViewController?.present(alertController, animated: true, completion: nil)
这是在Swift 3中测试和工作的代码。
