我想转换以下(工作)curl片段到一个RestTemplate调用:
curl -i -X POST -d "email=first.last@example.com" https://app.example.com/hr/email
如何正确传递email参数?下面的代码将导致404 Not Found响应:
String url = "https://app.example.com/hr/email";
Map<String, String> params = new HashMap<String, String>();
params.put("email", "first.last@example.com");
RestTemplate restTemplate = new RestTemplate();
ResponseEntity<String> response = restTemplate.postForEntity( url, params, String.class );
我已经尝试在PostMan中制定正确的调用，并且我可以通过将email参数指定为正文中的“form-data”参数来使其正确工作。在RestTemplate中实现此功能的正确方法是什么?
如何POST混合数据:文件，字符串[]，字符串在一个请求。
你只能用你需要的东西。
private String doPOST(File file, String[] array, String name) {
RestTemplate restTemplate = new RestTemplate(true);
//add file
LinkedMultiValueMap<String, Object> params = new LinkedMultiValueMap<>();
params.add("file", new FileSystemResource(file));
//add array
UriComponentsBuilder builder = UriComponentsBuilder.fromHttpUrl("https://my_url");
for (String item : array) {
builder.queryParam("array", item);
}
//add some String
builder.queryParam("name", name);
//another staff
String result = "";
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.MULTIPART_FORM_DATA);
HttpEntity<LinkedMultiValueMap<String, Object>> requestEntity =
new HttpEntity<>(params, headers);
ResponseEntity<String> responseEntity = restTemplate.exchange(
builder.build().encode().toUri(),
HttpMethod.POST,
requestEntity,
String.class);
HttpStatus statusCode = responseEntity.getStatusCode();
if (statusCode == HttpStatus.ACCEPTED) {
result = responseEntity.getBody();
}
return result;
}
POST请求的Body中有File和下一个结构:
POST https://my_url?array=your_value1&array=your_value2&name=bob
Client.java
@PostMapping(value = "/employee", consumes = "application/json")
public Employee createProducts(@RequestBody Employee product) {
HttpHeaders headers = new HttpHeaders();
headers.setAccept(Arrays.asList(MediaType.APPLICATION_JSON));
HttpEntity<Employee> entity = new HttpEntity<Employee>(product,headers);
ResponseEntity<Employee> response = restTemplate.exchange(
"http://hello-server/rest/employee", HttpMethod.POST, entity, Employee.class);
return response.getBody();
}
Server.java
private static List<Employee> list = new ArrayList<>();
@PostMapping(path="rest/employee", consumes = "application/json")
public Employee createEmployee(@RequestBody Employee employee)
{
list.add(employee);
return employee;
}
static
{
list.add(new Employee(1, "albert", "Associate", "mphasis"));
list.add(new Employee(2, "sachin", "software engineer", "mphasis"));
list.add(new Employee(3, "dhilip", "Lead engineer", "IBM"));
}
Employee.java
public class Employee {
private Integer id;
private String name;
private String Designation;
private String company;
// generate getter setter and toString()
}
1. post请求
POST方法应该沿着HTTP请求对象发送。请求可以包含HTTP报头或HTTP正文，或者两者都包含。
因此，让我们创建一个HTTP实体并发送头部和参数。
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);
MultiValueMap<String, String> map= new LinkedMultiValueMap<String, String>();
map.add("email", "first.last@example.com");
HttpEntity<MultiValueMap<String, String>> request = new HttpEntity<MultiValueMap<String, String>>(map, headers);
ResponseEntity<String> response = restTemplate.postForEntity( url, request , String.class );
http://docs.spring.io/spring/docs/current/javadoc-api/org/springframework/web/client/RestTemplate.html#postForObject-java.lang.String-java.lang.Object-java.lang.Class-java.lang.Object...-
下面是使用spring的RestTemplate进行POST rest调用的完整程序。
import java.util.HashMap;
import java.util.Map;
import org.springframework.http.HttpEntity;
import org.springframework.http.ResponseEntity;
import org.springframework.util.LinkedMultiValueMap;
import org.springframework.util.MultiValueMap;
import org.springframework.web.client.RestTemplate;
import com.ituple.common.dto.ServiceResponse;
public class PostRequestMain {
public static void main(String[] args) {
// TODO Auto-generated method stub
MultiValueMap<String, String> headers = new LinkedMultiValueMap<String, String>();
Map map = new HashMap<String, String>();
map.put("Content-Type", "application/json");
headers.setAll(map);
Map req_payload = new HashMap();
req_payload.put("name", "piyush");
HttpEntity<?> request = new HttpEntity<>(req_payload, headers);
String url = "http://localhost:8080/xxx/xxx/";
ResponseEntity<?> response = new RestTemplate().postForEntity(url, request, String.class);
ServiceResponse entityResponse = (ServiceResponse) response.getBody();
System.out.println(entityResponse.getData());
}
}
如何POST混合数据:文件，字符串[]，字符串在一个请求。
你只能用你需要的东西。
private String doPOST(File file, String[] array, String name) {
RestTemplate restTemplate = new RestTemplate(true);
//add file
LinkedMultiValueMap<String, Object> params = new LinkedMultiValueMap<>();
params.add("file", new FileSystemResource(file));
//add array
UriComponentsBuilder builder = UriComponentsBuilder.fromHttpUrl("https://my_url");
for (String item : array) {
builder.queryParam("array", item);
}
//add some String
builder.queryParam("name", name);
//another staff
String result = "";
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.MULTIPART_FORM_DATA);
HttpEntity<LinkedMultiValueMap<String, Object>> requestEntity =
new HttpEntity<>(params, headers);
ResponseEntity<String> responseEntity = restTemplate.exchange(
builder.build().encode().toUri(),
HttpMethod.POST,
requestEntity,
String.class);
HttpStatus statusCode = responseEntity.getStatusCode();
if (statusCode == HttpStatus.ACCEPTED) {
result = responseEntity.getBody();
}
return result;
}
POST请求的Body中有File和下一个结构:
POST https://my_url?array=your_value1&array=your_value2&name=bob
