我试图写一个函数,大写字符串中每个单词的第一个字母(将字符串转换为标题情况)。

例如,当输入是“我是一个小茶壶”时,我期望“我是一个小茶壶”是输出。然而,该函数返回“i'm a little tea pot”。

这是我的代码:

函数标题案例(str) { var splitStr = str.toLowerCase().split(“ ”); for (var i = 0; i < splitStr.length; i++) { if (splitStr.length[i] < splitStr.length) { splitStr[i].charAt(0).toUpperCase(); } str = splitStr.join(“ ”); } 返回 str; } console.log(titleCase(“I'm a Little Teapot”));


当前回答

ECMAScript 6版本:

title
    .split(/ /g).map(word =>
        `${word.substring(0,1).toUpperCase()}${word.substring(1)}`)
    .join(" ");

其他回答

这里我使用了replace()函数。

function titleCase(str){
    return str.replace(/\w\S*/g, function(txt){return txt.charAt(0).toUpperCase() + txt.substr(1).toLowerCase();});
}

如果您可以使用第三方库,那么Lodash为您提供了一个帮助函数。

https://lodash.com/docs/4.17.3#startCase

_。startCase (foo栏); // => 'Foo Bar' _.startCase(“——foo bar”); // => 'Foo Bar' _.startCase(“fooBar”); // => 'Foo Bar' _.startCase(“__FOO_BAR__”); // => ' foo bar ' < script src = " https://cdn.jsdelivr.net/lodash/4.17.3/lodash.min.js " > < /脚本>

ECMA2017或ES8

const titleCase = (string) => { return string .split(' ') .map(word => word.substr(0,1).toUpperCase() + word.substr(1,word.length)) .join(' '); }; let result = titleCase('test test test'); console.log(result); Explanation: 1. First, we pass the string "test test test" to our function "titleCase". 2. We split a string on the space basis so the result of first function "split" will be ["test","test","test"] 3. As we got an array, we used map function for manipulation each word in the array. We capitalize the first character and add remaining character to it. 4. In the last, we join the array using space as we split the string by sapce.

function titleCase(str) {

    var myString = str.toLowerCase().split(' ');
    for (var i = 0; i < myString.length; i++) {
        var subString = myString[i].split('');
        for (var j = 0; j < subString.length; j++) {
            subString[0] = subString[0].toUpperCase();
        }
        myString[i] = subString.join('');
    }

    return myString.join(' ');
}

ECMAScript 6版本:

const toTitleCase =(短语)=> { 返回的短语 .toLowerCase () .split (' ') .map(word => word. charat (0).toUpperCase() + word.slice(1)) . join (' '); }; let result = toTitleCase('maRy have a lIttLe LaMb'); console.log(结果);