我有两个日期YYYY-MM-DD和ZZZZ-NN-EE
我怎么知道它们之间有多少秒呢?
我有两个日期YYYY-MM-DD和ZZZZ-NN-EE
我怎么知道它们之间有多少秒呢?
当前回答
var a = new Date("2010 jan 10"),
b = new Date("2010 jan 9");
alert(
a + "\n" +
b + "\n" +
"Difference: " + ((+a - +b) / 1000)
);
其他回答
减:
var a = new Date(); 警报(“等待几秒钟,然后点击确定”); var b = new Date(); Var差= (b - a) / 1000; console.log("You waiting: " + difference + " seconds");
如果你的一个或两个日期都在未来,那么如果你想精确到秒,恐怕你就是SOL了。UTC时间有闰秒,只有在6个月之前才知道,所以任何比这更晚的日期都可能不准确几秒(在实践中,由于人们不经常更新他们的机器,您可能会发现未来的任何时间都有几秒的误差)。
这很好地解释了设计日期/时间库的理论,以及为什么会这样:http://www.boost.org/doc/libs/1_41_0/doc/html/date_time/details.html#date_time.tradeoffs
简单的方法:
function diff_hours(dt2, dt1)
{
var diff =(dt2.getTime() - dt1.getTime()) / 1000;
diff /= (60 * 60);
return Math.abs(Math.round(diff));
}
function diff_minutes(dt2, dt1)
{
var diff =(dt2.getTime() - dt1.getTime()) / 1000;
diff /= (60);
return Math.abs(Math.round(diff));
}
function diff_seconds(dt2, dt1)
{
var diff =(dt2.getTime() - dt1.getTime()) / 1000;
return Math.abs(Math.round(diff));
}
function diff_miliseconds(dt2, dt1)
{
var diff =(dt2.getTime() - dt1.getTime());
return Math.abs(Math.round(diff));
}
dt1 = new Date(2014,10,2);
dt2 = new Date(2014,10,3);
console.log(diff_hours(dt1, dt2));
dt1 = new Date("October 13, 2014 08:11:00");
dt2 = new Date("October 14, 2014 11:13:00");
console.log(diff_hours(dt1, dt2));
console.log(diff_minutes(dt1, dt2));
console.log(diff_seconds(dt1, dt2));
console.log(diff_miliseconds(dt1, dt2));
function parseDate(str) {
const [dateStr, timeStr] = str.split(' ');
const [m,d,y] = dateStr.split('/');
const [h,min] = timeStr.split(':');
const date = new Date(y,m,d,h,min,0, 0);
return date;
}
const date1 = parseDate('28/6/2022 22:55');
const date2 = parseDate('28/6/2022 22:58');
const diffInSeconds = (date2 - date1) / 1000;
console.log(diffInSeconds)
var a = new Date("2010 jan 10"),
b = new Date("2010 jan 9");
alert(
a + "\n" +
b + "\n" +
"Difference: " + ((+a - +b) / 1000)
);