我在这里发布了类似的内容

来自约阿希姆的回答，来自Dianne Hackborn:

http://groups.google.com/group/android-developers/browse_thread/thread/d2a5c203dad6ec42

最后我只用了:

FragmentManager fm = getActivity().getSupportFragmentManager();
for(int i = 0; i < fm.getBackStackEntryCount(); ++i) {    
    fm.popBackStack();
}

但同样可以使用类似的东西:

((AppCompatActivity)getContext()).getSupportFragmentManager().popBackStack(String name, FragmentManager.POP_BACK_STACK_INCLUSIVE)

这将弹出所有的状态到指定的一个。然后你可以用你想要的东西替换这个片段

private boolean removeFragFromBackStack() {
    try {
        FragmentManager manager = getSupportFragmentManager();
        List<Fragment> fragsList = manager.getFragments();
        if (fragsList.size() == 0) {
            return true;
        }
        manager.popBackStack(null, FragmentManager.POP_BACK_STACK_INCLUSIVE);
        return true;
    } catch (Exception e) {
        e.printStackTrace();
    }
    return false;
}

接受的答案对我来说是不够的。我不得不使用:

FragmentManager fm = getSupportFragmentManager();
int count = fm.getBackStackEntryCount();
for(int i = 0; i < count; ++i) {
    fm.popBackStackImmediate();
}

我让它这样工作:

public void showHome() {
    getHandler().post(new Runnable() {
        @Override
        public void run() {
            final FragmentManager fm = getSupportFragmentManager();
            while (fm.getBackStackEntryCount() > 0) {
                fm.popBackStackImmediate();
            }
        }
    });
}

这对我很有效，试试这个:

public void clearFragmentBackStack() {
        FragmentManager fm = getSupportFragmentManager();
        for (int i = 0; i < fm.getBackStackEntryCount() - 1; i++) {
            fm.popBackStack();
        }
    }

清除无循环的backstack

String name = getSupportFragmentManager().getBackStackEntryAt(0).getName();
getSupportFragmentManager().popBackStack(name, FragmentManager.POP_BACK_STACK_INCLUSIVE);

addToBackStack()参数的名称在哪里

getSupportFragmentManager().beginTransaction().
                .replace(R.id.container, fragments.get(titleCode))
                .addToBackStack(name)