明确一点,我并不是在寻找MIME类型。
假设我有以下输入:/path/to/file/foo.txt
我想要一种方法来分解这个输入,特别是扩展为.txt。在Java中有任何内置的方法来做到这一点吗?我希望避免编写自己的解析器。
明确一点,我并不是在寻找MIME类型。
假设我有以下输入:/path/to/file/foo.txt
我想要一种方法来分解这个输入,特别是扩展为.txt。在Java中有任何内置的方法来做到这一点吗?我希望避免编写自己的解析器。
当前回答
在这里我做了一个小方法(然而不是那么安全,并没有检查很多错误),但如果只有你在编写一个普通的java程序,这就足够找到文件类型了。这对于复杂的文件类型并不适用,但这些文件类型通常不常用。
public static String getFileType(String path){
String fileType = null;
fileType = path.substring(path.indexOf('.',path.lastIndexOf('/'))+1).toUpperCase();
return fileType;
}
其他回答
你真的需要一个“解析器”吗?
String extension = "";
int i = fileName.lastIndexOf('.');
if (i > 0) {
extension = fileName.substring(i+1);
}
假设您正在处理简单的类似windows的文件名,而不是像archive.tar.gz这样的文件名。
顺便说一下,对于目录可能有一个'。',但文件名本身没有(像/path/to.a/file),你可以这样做
String extension = "";
int i = fileName.lastIndexOf('.');
int p = Math.max(fileName.lastIndexOf('/'), fileName.lastIndexOf('\\'));
if (i > p) {
extension = fileName.substring(i+1);
}
流利的方式:
fileExtension(String fileName) { 返回Optional.of (fileName.lastIndexOf(“。”))。过滤器(i-> i >= 0) .filter(i-> i > fileName.lastIndexOf(File.separator)) . map(文件名::substring) .orElse (" "); }
如果在Android上,你可以使用这个:
String ext = android.webkit.MimeTypeMap.getFileExtensionFromUrl(file.getName());
从文件名获取文件扩展名
/**
* The extension separator character.
*/
private static final char EXTENSION_SEPARATOR = '.';
/**
* The Unix separator character.
*/
private static final char UNIX_SEPARATOR = '/';
/**
* The Windows separator character.
*/
private static final char WINDOWS_SEPARATOR = '\\';
/**
* The system separator character.
*/
private static final char SYSTEM_SEPARATOR = File.separatorChar;
/**
* Gets the extension of a filename.
* <p>
* This method returns the textual part of the filename after the last dot.
* There must be no directory separator after the dot.
* <pre>
* foo.txt --> "txt"
* a/b/c.jpg --> "jpg"
* a/b.txt/c --> ""
* a/b/c --> ""
* </pre>
* <p>
* The output will be the same irrespective of the machine that the code is running on.
*
* @param filename the filename to retrieve the extension of.
* @return the extension of the file or an empty string if none exists.
*/
public static String getExtension(String filename) {
if (filename == null) {
return null;
}
int index = indexOfExtension(filename);
if (index == -1) {
return "";
} else {
return filename.substring(index + 1);
}
}
/**
* Returns the index of the last extension separator character, which is a dot.
* <p>
* This method also checks that there is no directory separator after the last dot.
* To do this it uses {@link #indexOfLastSeparator(String)} which will
* handle a file in either Unix or Windows format.
* <p>
* The output will be the same irrespective of the machine that the code is running on.
*
* @param filename the filename to find the last path separator in, null returns -1
* @return the index of the last separator character, or -1 if there
* is no such character
*/
public static int indexOfExtension(String filename) {
if (filename == null) {
return -1;
}
int extensionPos = filename.lastIndexOf(EXTENSION_SEPARATOR);
int lastSeparator = indexOfLastSeparator(filename);
return (lastSeparator > extensionPos ? -1 : extensionPos);
}
/**
* Returns the index of the last directory separator character.
* <p>
* This method will handle a file in either Unix or Windows format.
* The position of the last forward or backslash is returned.
* <p>
* The output will be the same irrespective of the machine that the code is running on.
*
* @param filename the filename to find the last path separator in, null returns -1
* @return the index of the last separator character, or -1 if there
* is no such character
*/
public static int indexOfLastSeparator(String filename) {
if (filename == null) {
return -1;
}
int lastUnixPos = filename.lastIndexOf(UNIX_SEPARATOR);
int lastWindowsPos = filename.lastIndexOf(WINDOWS_SEPARATOR);
return Math.max(lastUnixPos, lastWindowsPos);
}
学分
复制自Apache FileNameUtils Class - http://grepcode.com/file/repo1.maven.org/maven2/commons-io/commons-io/1.3.2/org/apache/commons/io/FilenameUtils.java#FilenameUtils.getExtension%28java.lang.String%29
我的肮脏和可能最小的使用String.replaceAll:
.replaceAll("^.*\\.(.*)$", "$1")
请注意,第一个*是贪婪的,所以它会尽可能地抓取大多数可能的字符,然后只剩下最后一个点和文件扩展名。