如何使用Flask从URL中获得命名参数?

当用户访问我的flask应用程序上运行的这个URL时，我希望web服务能够处理问号后指定的参数:

http://10.1.1.1:5000/login?username=alex&password=pw1

#I just want to be able to manipulate the parameters
@app.route('/login', methods=['GET', 'POST'])
def login():
    username = request.form['username']
    print(username)
    password = request.form['password']
    print(password)

当前回答

如果你在URL中传递了一个参数，你可以这样做

from flask import request
#url
http://10.1.1.1:5000/login/alex

from flask import request
@app.route('/login/<username>', methods=['GET'])
def login(username):
    print(username)

如果你有多个参数:

#url
http://10.1.1.1:5000/login?username=alex&password=pw1

from flask import request
@app.route('/login', methods=['GET'])
    def login():
        username = request.args.get('username')
        print(username)
        password= request.args.get('password')
        print(password)

在POST请求中，参数作为表单参数传递，而不出现在URL中。在实际开发登录API的情况下，使用POST请求而不是GET请求并将数据公开给用户是明智的。

如有职位要求，其工作方式如下:

#url
http://10.1.1.1:5000/login

HTML代码片段:

<form action="http://10.1.1.1:5000/login" method="POST">
  Username : <input type="text" name="username"><br>
  Password : <input type="password" name="password"><br>
  <input type="submit" value="submit">
</form>

路线:

from flask import request
@app.route('/login', methods=['POST'])
    def login():
        username = request.form.get('username')
        print(username)
        password= request.form.get('password')
        print(password)

2018-07-17 15:18:54

其他回答

这真的很简单。让我把这个过程分成两个简单的步骤。

在html模板中，你将像这样声明用户名和密码的name属性:

<form method="POST">
<input type="text" name="user_name"></input>
<input type="text" name="password"></input>
</form>

然后，像这样修改你的代码:

from flask import request

@app.route('/my-route', methods=['POST'])
# you should always parse username and 
# password in a POST method not GET
def my_route():
    username = request.form.get("user_name")
    print(username)
    password = request.form.get("password")
    print(password)
    #now manipulate the username and password variables as you wish
    #Tip: define another method instead of methods=['GET','POST'], if you want to  
    # render the same template with a GET request too

2019-04-22 23:04:36

你也可以在视图定义的URL上使用括号<>，这个输入将进入你的视图函数参数

@app.route('/<name>')
def my_view_func(name):
    return name

2018-03-14 00:29:48

这应该可以

@app.route('/login$username=<username>$password=<password>', methods=['GET', 'POST'])
def login(username, password):
    # you can add stuff
    return f"Username: {username}\nPassword: {password}"

2021-05-11 08:52:03

url:

http://0.0.0.0:5000/user/name/

代码:

@app.route('/user/<string:name>/', methods=['GET', 'POST'])
def user_view(name):
    print(name)

(编辑:删除格式字符串中的空格)

2019-04-05 05:58:47