我想检查两个数组是否相等。我的意思是:相同的大小，相同的索引，相同的值。我该怎么做呢?
根据用户的建议使用!==，如果数组中至少有一个元素是不同的，我希望下面的代码会打印enter，但实际上并不是这样。
if (($_POST['atlOriginal'] !== $oldAtlPosition)
or ($_POST['atl'] !== $aext)
or ($_POST['sidesOriginal'] !== $oldSidePosition)
or ($_POST['sidesOriginal'] !== $sideext)) {
echo "enter";
}
当前回答
$arraysAreEqual = ($a == $b); // TRUE if $a and $b have the same key/value pairs.
$arraysAreEqual = ($a === $b); // TRUE if $a and $b have the same key/value pairs in the same order and of the same types.
参见数组操作符。
EDIT
不等式运算符是!=，而非恒等运算符是!==来匹配相等 运算符==和恒等运算符===。
其他回答
比较你的数组的值，也是多维的，关联的和任意组合的:
/**
* @see PHPUnit Assert::assertEqualsCanonicalizing()
* @return true if all keys and values are equal and of the same type,
* irregardless of items or keys order
*/
function array_vals_equal(array $a, array $b): bool {
// sort multi-dimensional recursive
$_deep_sort = function (array $a) use (&$_deep_sort): array{
// sort discarding index association or sort keys, depending on array type
array_is_list($a) ? sort($a) : ksort($a);
return array_map(fn($v) => is_array($v) ? $_deep_sort($v) : $v, $a);
};
// operator === checks that the count, types and order of the elements are the same
return $_deep_sort($a) === $_deep_sort($b);
}
// Test cases
assertEquals(array_vals_equal([1], [1]), true, 'simple eq');
assertEquals(array_vals_equal([0], [false]), false, 'simple eq');
assertEquals(array_vals_equal([0], [null]), false, 'simple eq');
assertEquals(array_vals_equal([0, 1], [1, 0]), true, 'simple eq, diff order');
assertEquals(array_vals_equal([0, 1, 2], [1, 0]), false, 'diff count');
assertEquals(array_vals_equal([0, 1], [0, 1, 2]), false, 'diff count 2');
assertEquals(array_vals_equal([1, 2], [1, 2, 'hello']), false, 'diff count 3');
//
assertEquals(array_vals_equal([1, 2, 2], [2, 1, 1]), false, 'same vals repeated');
assertEquals(array_vals_equal([1, 2, 2], [2, 2, 1]), true, 'same vals, different order');
//
assertEquals(array_vals_equal([1, 2, 3], ['1', '2', '3']), false, 'int should not be eq string');
assertEquals(array_vals_equal([0 => 'a', 1 => 'b'], [0 => 'b', 1 => 'a']), true, 'same vals, diff order');
assertEquals(array_vals_equal(['a', 'b'], [3 => 'b', 5 => 'a']), true, 'same vals, diff indexes');
// associative arrays whose members are ordered differently
assertEquals(array_vals_equal(['aa' => 'a', 'bb' => 'b'], ['bb' => 'b', 'aa' => 'a']), true, 'dict with different order');
assertEquals(array_vals_equal(['aa' => 'a', 'bb' => 'b'], ['aa' => 'a']), false, 'a key is missing');
assertEquals(array_vals_equal(['aa' => 'a', 'bb' => 'b'], ['aa' => 'a', 'zz' => 'b']), false, 'dict same vals diff key');
// nested arrays with keys in different order
assertEquals(array_vals_equal(
['aa' => 'a', 'bb' => ['bb' => 'b', 'aa' => 'a']],
['aa' => 'a', 'bb' => ['aa' => 'a', 'bb' => 'b']]
), true, 'dict multi 2 level, keys in different order');
assertEquals(array_vals_equal(
['aa' => 'a', 'bb' => ['aa2' => 'a', 'bb2' => ['aa3' => 'a', 'bb3' => 'b']]],
['aa' => 'a', 'bb' => ['aa2' => 'a', 'bb2' => ['aa3' => 'a', 'bb3' => 'b']]]
), true, 'dict multi 3 level');
assertEquals(array_vals_equal(
['aa' => 'a', 'bb' => [0, 1]],
['aa' => 'a', 'bb' => [1, 0]]
), true, 'dict multi level, 2^ level sequential in different order');
assertEquals(array_vals_equal([[0, 1], ['a', 'b']], [['b', 'a'], [1, 0]]), true, 'multi level sequential');
另一种不考虑值顺序检查是否相等的方法使用http://php.net/manual/en/function.array-intersect.php，如下所示:
$array1 = array(2,5,3);
$array2 = array(5,2,3);
if($array1 === array_intersect($array1, $array2) && $array2 === array_intersect($array2, $array1)) {
echo 'Equal';
} else {
echo 'Not equal';
}
下面是一个使用http://php.net/manual/en/function.array-uintersect.php:也可以用于多维数组的版本
$array1 = array(
array(5, 2),
array(3, 6),
array(2, 9, 4)
);
$array2 = array(
array(3, 6),
array(2, 9, 4),
array(5, 2)
);
if($array1 === array_uintersect($array1, $array2, 'compare') && $array2 === array_uintersect($array2, $array1, 'compare')) {
echo 'Equal';
} else {
echo 'Not equal';
}
function compare($v1, $v2) {
if ($v1===$v2) {
return 0;
}
if ($v1 > $v2) return 1;
return -1;
}
简单的解决方案，即使是数组的键以不同的顺序给出:
public static function arrays_are_equal($array1, $array2)
{
array_multisort($array1);
array_multisort($array2);
return ( serialize($array1) === serialize($array2) );
}
$arraysAreEqual = ($a == $b); // TRUE if $a and $b have the same key/value pairs.
$arraysAreEqual = ($a === $b); // TRUE if $a and $b have the same key/value pairs in the same order and of the same types.
参见数组操作符。
EDIT
不等式运算符是!=，而非恒等运算符是!==来匹配相等 运算符==和恒等运算符===。
下面的解决方案使用可作为回调传递的自定义相等函数。注意，它不检查数组的顺序。
trait AssertTrait
{
/**
* Determine if two arrays have the same elements, possibly in different orders. Elements comparison function must be passed as argument.
*
* @param array<mixed> $expected
* @param array<mixed> $actual
*
* @throws InvalidArgumentException
*/
public static function assertArraysContainSameElements(array $expected, array $actual, callable $comparisonFunction): void
{
Assert::assertEquals(\count($expected), \count($actual));
self::assertEveryElementOfArrayIsInAnotherArrayTheSameAmountOfTimes($expected, $actual, $comparisonFunction);
self::assertEveryElementOfArrayIsInAnotherArrayTheSameAmountOfTimes($actual, $expected, $comparisonFunction);
}
/**
* @param array<mixed> $needles
* @param array<mixed> $haystack
*
* @throws InvalidArgumentException
*/
private static function assertEveryElementOfArrayIsInAnotherArrayTheSameAmountOfTimes(
array $needles,
array $haystack,
callable $comparisonFunction
): void {
Assert::assertLessThanOrEqual(\count($needles), \count($haystack));
foreach ($needles as $expectedElement) {
$matchesOfExpectedElementInExpected = \array_filter(
$needles,
static fn($element): bool => $comparisonFunction($expectedElement, $element),
);
$matchesOfExpectedElementInActual = \array_filter(
$haystack,
static fn($element): bool => $comparisonFunction($expectedElement, $element),
);
Assert::assertEquals(\count($matchesOfExpectedElementInExpected), \count($matchesOfExpectedElementInActual));
}
}
}
我通常在数据库集成测试中使用它，当我想确保返回预期的元素，但我不关心排序。
