我发现了一个快速简单的方法来格式化和打印一个xml文件:

import xml.etree.ElementTree as ET

xmlTree = ET.parse('your XML file')
xmlRoot = xmlTree.getroot()
xmlDoc =  ET.tostring(xmlRoot, encoding="unicode")

print(xmlDoc)

Outuput:

<root>
  <child>
    <subchild>.....</subchild>
  </child>
  <child>
    <subchild>.....</subchild>
  </child>
  ...
  ...
  ...
  <child>
    <subchild>.....</subchild>
  </child>
</root>

我在寻找“如何漂亮地打印html”时发现了这个问题

使用这篇文章中的一些想法，我调整了XML解决方案，以适用于XML或HTML:

from xml.dom.minidom import parseString as string_to_dom

def prettify(string, html=True):
    dom = string_to_dom(string)
    ugly = dom.toprettyxml(indent="  ")
    split = list(filter(lambda x: len(x.strip()), ugly.split('\n')))
    if html:
        split = split[1:]
    pretty = '\n'.join(split)
    return pretty

def pretty_print(html):
    print(prettify(html))

使用时是这样的:

html = """\
<div class="foo" id="bar"><p>'IDK!'</p><br/><div class='baz'><div>
<span>Hi</span></div></div><p id='blarg'>Try for 2</p>
<div class='baz'>Oh No!</div></div>
"""

pretty_print(html)

返回:

<div class="foo" id="bar">
  <p>'IDK!'</p>
  <br/>
  <div class="baz">
    <div>
      <span>Hi</span>
    </div>
  </div>
  <p id="blarg">Try for 2</p>
  <div class="baz">Oh No!</div>
</div>

我用几行代码解决了这个问题，打开文件，通过它并添加缩进，然后再次保存它。我使用的是小的xml文件，不想添加依赖项，也不想为用户安装更多的库。总之，这是我最后得出的结论:

    f = open(file_name,'r')
    xml = f.read()
    f.close()

    #Removing old indendations
    raw_xml = ''        
    for line in xml:
        raw_xml += line

    xml = raw_xml

    new_xml = ''
    indent = '    '
    deepness = 0

    for i in range((len(xml))):

        new_xml += xml[i]   
        if(i<len(xml)-3):

            simpleSplit = xml[i:(i+2)] == '><'
            advancSplit = xml[i:(i+3)] == '></'        
            end = xml[i:(i+2)] == '/>'    
            start = xml[i] == '<'

            if(advancSplit):
                deepness += -1
                new_xml += '\n' + indent*deepness
                simpleSplit = False
                deepness += -1
            if(simpleSplit):
                new_xml += '\n' + indent*deepness
            if(start):
                deepness += 1
            if(end):
                deepness += -1

    f = open(file_name,'w')
    f.write(new_xml)
    f.close()

这对我来说很有用，也许有人会用到它:)

下面是我解决难看的文本节点问题的解决方案。

uglyXml = doc.toprettyxml(indent='  ')

text_re = re.compile('>\n\s+([^<>\s].*?)\n\s+</', re.DOTALL)    
prettyXml = text_re.sub('>\g<1></', uglyXml)

print prettyXml

上面的代码将产生:

<?xml version="1.0" ?>
<issues>
  <issue>
    <id>1</id>
    <title>Add Visual Studio 2005 and 2008 solution files</title>
    <details>We need Visual Studio 2005/2008 project files for Windows.</details>
  </issue>
</issues>

而不是这样:

<?xml version="1.0" ?>
<issues>
  <issue>
    <id>
      1
    </id>
    <title>
      Add Visual Studio 2005 and 2008 solution files
    </title>
    <details>
      We need Visual Studio 2005/2008 project files for Windows.
    </details>
  </issue>
</issues>

免责声明:可能有一些限制。

如果由于某种原因你无法获得其他用户提到的任何Python模块，我建议使用以下Python 2.7解决方案:

import subprocess

def makePretty(filepath):
  cmd = "xmllint --format " + filepath
  prettyXML = subprocess.check_output(cmd, shell = True)
  with open(filepath, "w") as outfile:
    outfile.write(prettyXML)

据我所知，这种解决方案适用于安装了xmllint包的基于unix的系统。

import xml.dom.minidom

dom = xml.dom.minidom.parse(xml_fname) # or xml.dom.minidom.parseString(xml_string)
pretty_xml_as_string = dom.toprettyxml()