如何在几列的最大值中每行返回1个值:
的表
[Number, Date1, Date2, Date3, Cost]
我需要返回这样的东西:
[Number, Most_Recent_Date, Cost]
查询?
如何在几列的最大值中每行返回1个值:
的表
[Number, Date1, Date2, Date3, Cost]
我需要返回这样的东西:
[Number, Most_Recent_Date, Cost]
查询?
当前回答
如果你正在使用MySQL或PostgreSQL或Oracle或BigQuery,你可以使用
SELECT GREATEST(col1, col2 ...) FROM table
其他回答
最后,针对以下内容:
SQL Server 2022 (16.x)预览 Azure SQL数据库 Azure SQL托管实例
我们也可以用GREATEST。与其他T-SQL函数类似,这里有一些重要的注意事项:
如果所有参数都具有相同的数据类型,并且 的类型为 支持 进行比较, GREATEST将返回该类型; 否则, 函数 将隐式地将所有参数转换为 最高优先级 的数据类型进行比较,并使用 这个 类型 作为返回类型; 如果一个或多个参数不是NULL,那么NULL参数将在比较过程中被忽略;如果所有参数都为NULL,则GREATEST将返回NULL;
在GREATEST中不支持以下类型进行比较:varchar(max)、varbinary(max)或nvarchar(max)超过8,000字节、游标、几何、地理、图像、非字节顺序的用户定义类型、ntext、table、text和xml。
For T-SQL (MSSQL 2008+)
SELECT
(SELECT
MAX(MyMaxName)
FROM ( VALUES
(MAX(Field1)),
(MAX(Field2))
) MyAlias(MyMaxName)
)
FROM MyTable1
使用CROSS APPLY (2005+) ....
SELECT MostRecentDate
FROM SourceTable
CROSS APPLY (SELECT MAX(d) MostRecentDate FROM (VALUES (Date1), (Date2), (Date3)) AS a(d)) md
DECLARE @TableName TABLE (Number INT, Date1 DATETIME, Date2 DATETIME, Date3 DATETIME, Cost MONEY)
INSERT INTO @TableName
SELECT 1, '20000101', '20010101','20020101',100 UNION ALL
SELECT 2, '20000101', '19900101','19980101',99
SELECT Number,
Cost ,
(SELECT MAX([Date])
FROM (SELECT Date1 AS [Date]
UNION ALL
SELECT Date2
UNION ALL
SELECT Date3
)
D
)
[Most Recent Date]
FROM @TableName
我更喜欢基于case-when的解决方案,我的假设是,与其他可能的解决方案(如交叉应用、values()、自定义函数等)相比,它对可能的性能下降的影响应该最小。
下面是case-when版本,它在大多数可能的测试用例中处理空值:
SELECT
CASE
WHEN Date1 > coalesce(Date2,'0001-01-01') AND Date1 > coalesce(Date3,'0001-01-01') THEN Date1
WHEN Date2 > coalesce(Date3,'0001-01-01') THEN Date2
ELSE Date3
END AS MostRecentDate
, *
from
(values
( 1, cast('2001-01-01' as Date), cast('2002-01-01' as Date), cast('2003-01-01' as Date))
,( 2, cast('2001-01-01' as Date), cast('2003-01-01' as Date), cast('2002-01-01' as Date))
,( 3, cast('2002-01-01' as Date), cast('2001-01-01' as Date), cast('2003-01-01' as Date))
,( 4, cast('2002-01-01' as Date), cast('2003-01-01' as Date), cast('2001-01-01' as Date))
,( 5, cast('2003-01-01' as Date), cast('2001-01-01' as Date), cast('2002-01-01' as Date))
,( 6, cast('2003-01-01' as Date), cast('2002-01-01' as Date), cast('2001-01-01' as Date))
,( 11, cast(NULL as Date), cast('2002-01-01' as Date), cast('2003-01-01' as Date))
,( 12, cast(NULL as Date), cast('2003-01-01' as Date), cast('2002-01-01' as Date))
,( 13, cast('2003-01-01' as Date), cast(NULL as Date), cast('2002-01-01' as Date))
,( 14, cast('2002-01-01' as Date), cast(NULL as Date), cast('2003-01-01' as Date))
,( 15, cast('2003-01-01' as Date), cast('2002-01-01' as Date), cast(NULL as Date))
,( 16, cast('2002-01-01' as Date), cast('2003-01-01' as Date), cast(NULL as Date))
,( 21, cast('2003-01-01' as Date), cast(NULL as Date), cast(NULL as Date))
,( 22, cast(NULL as Date), cast('2003-01-01' as Date), cast(NULL as Date))
,( 23, cast(NULL as Date), cast(NULL as Date), cast('2003-01-01' as Date))
,( 31, cast(NULL as Date), cast(NULL as Date), cast(NULL as Date))
) as demoValues(id, Date1,Date2,Date3)
order by id
;
结果是:
MostRecent id Date1 Date2 Date3
2003-01-01 1 2001-01-01 2002-01-01 2003-01-01
2003-01-01 2 2001-01-01 2003-01-01 2002-01-01
2003-01-01 3 2002-01-01 2001-01-01 2002-01-01
2003-01-01 4 2002-01-01 2003-01-01 2001-01-01
2003-01-01 5 2003-01-01 2001-01-01 2002-01-01
2003-01-01 6 2003-01-01 2002-01-01 2001-01-01
2003-01-01 11 NULL 2002-01-01 2003-01-01
2003-01-01 12 NULL 2003-01-01 2002-01-01
2003-01-01 13 2003-01-01 NULL 2002-01-01
2003-01-01 14 2002-01-01 NULL 2003-01-01
2003-01-01 15 2003-01-01 2002-01-01 NULL
2003-01-01 16 2002-01-01 2003-01-01 NULL
2003-01-01 21 2003-01-01 NULL NULL
2003-01-01 22 NULL 2003-01-01 NULL
2003-01-01 23 NULL NULL 2003-01-01
NULL 31 NULL NULL NULL