SELECT DISTINCT field1, field2, field3, ......
FROM table;

我试图完成以下SQL语句,但我希望它返回所有列。 这可能吗?

就像这样:

SELECT DISTINCT field1, * 
FROM table;

当前回答

SELECT * from table where field in (SELECT distinct field from table)

其他回答

它可以通过内部查询来完成

$query = "SELECT * 
            FROM (SELECT field
                FROM table
                ORDER BY id DESC) as rows               
            GROUP BY field";
SELECT *
FROM tblname
GROUP BY duplicate_values
ORDER BY ex.VISITED_ON DESC
LIMIT 0 , 30

在ORDER BY我刚刚把例子放在这里,你也可以在这里添加ID字段

SELECT  c2.field1 ,
        field2
FROM    (SELECT DISTINCT
                field1
         FROM   dbo.TABLE AS C
        ) AS c1
        JOIN dbo.TABLE AS c2 ON c1.field1 = c2.field1

只需将所有字段包含在GROUP BY子句中。

这是一个简单的解决方法:

 WITH cte AS /* Declaring a new table named 'cte' to be a clone of your table */
 (SELECT *, ROW_NUMBER() OVER (PARTITION BY id ORDER BY val1 DESC) AS rn
 FROM MyTable /* Selecting only unique values based on the "id" field */
 )
 SELECT * /* Here you can specify several columns to retrieve */
 FROM cte
 WHERE rn = 1