SELECT DISTINCT field1, field2, field3, ......
FROM table;

我试图完成以下SQL语句,但我希望它返回所有列。 这可能吗?

就像这样:

SELECT DISTINCT field1, * 
FROM table;

当前回答

SELECT * from table where field in (SELECT distinct field from table)

其他回答

你可以用with子句来实现。

例如:

WITH c AS (SELECT DISTINCT a, b, c FROM tableName)
SELECT * FROM tableName r, c WHERE c.rowid=r.rowid AND c.a=r.a AND c.b=r.b AND c.c=r.c

这还允许您只选择WITH子句查询中选择的行。

select min(table.id), table.column1
from table 
group by table.column1

只需将所有字段包含在GROUP BY子句中。

它可以通过内部查询来完成

$query = "SELECT * 
            FROM (SELECT field
                FROM table
                ORDER BY id DESC) as rows               
            GROUP BY field";

这是一个简单的解决方法:

 WITH cte AS /* Declaring a new table named 'cte' to be a clone of your table */
 (SELECT *, ROW_NUMBER() OVER (PARTITION BY id ORDER BY val1 DESC) AS rn
 FROM MyTable /* Selecting only unique values based on the "id" field */
 )
 SELECT * /* Here you can specify several columns to retrieve */
 FROM cte
 WHERE rn = 1