使用splitext时，具有双扩展名的文件存在问题（例如file.tar.gz、file.tar.bz2等）

>>> fileName, fileExtension = os.path.splitext('/path/to/somefile.tar.gz')
>>> fileExtension 
'.gz'

但应该是：.tar.gz

可能的解决方案如下

这是一种直接的字符串表示技术：我看到提到了很多解决方案，但我认为大多数都在考虑拆分。然而，每次出现“.”时，Split都会执行此操作。您更希望查找的是分区。

string = "folder/to_path/filename.ext"
extension = string.rpartition(".")[-1]

# try this, it works for anything, any length of extension
# e.g www.google.com/downloads/file1.gz.rs -> .gz.rs

import os.path

class LinkChecker:

    @staticmethod
    def get_link_extension(link: str)->str:
        if link is None or link == "":
            return ""
        else:
            paths = os.path.splitext(link)
            ext = paths[1]
            new_link = paths[0]
            if ext != "":
                return LinkChecker.get_link_extension(new_link) + ext
            else:
                return ""

另一种右拆分解决方案：

# to get extension only

s = 'test.ext'

if '.' in s: ext = s.rsplit('.', 1)[1]

# or, to get file name and extension

def split_filepath(s):
    """
    get filename and extension from filepath 
    filepath -> (filename, extension)
    """
    if not '.' in s: return (s, '')
    r = s.rsplit('.', 1)
    return (r[0], r[1])

a = ".bashrc"
b = "text.txt"
extension_a = a.split(".")
extension_b = b.split(".")
print(extension_a[-1])  # bashrc
print(extension_b[-1])  # txt

我知道我迟到了

这是我的简单解决方案

file = '/foo/bar/whatever.ext'
extension = file.split('.')[-1]
print(extension)

#output will be ext