我如何检查一个字符串是否有几个特定的字符在它使用Python 2?
例如,给定以下字符串:
罪犯们偷了价值一百万美元的珠宝。
我如何检测它是否有美元符号(“$”),逗号(“,”)和数字?
我如何检查一个字符串是否有几个特定的字符在它使用Python 2?
例如,给定以下字符串:
罪犯们偷了价值一百万美元的珠宝。
我如何检测它是否有美元符号(“$”),逗号(“,”)和数字?
当前回答
s=input("Enter any character:")
if s.isalnum():
print("Alpha Numeric Character")
if s.isalpha():
print("Alphabet character")
if s.islower():
print("Lower case alphabet character")
else:
print("Upper case alphabet character")
else:
print("it is a digit")
elif s.isspace():
print("It is space character")
其他: print(“非空格特殊字符”)
其他回答
另一种可能是python式的方法是:
aString = """The criminals stole $1,000,000 in jewels."""
#
if any(list(map(lambda char: char in aString, '0123456789,$')))
print(True) # Do something.
检查字符串中是否有字符:
parse_string = lambda chars, string: [char in string for char in chars]
例子:
parse_string('$,x', 'The criminals stole $1,000,000 in ....')
or
parse_string(['$', ',', 'x'], '..minals stole $1,000,000 i..')
输出:[True, True, False]
这将测试字符串是否由某些组合或数字、美元符号和逗号组成。这就是你想要的吗?
import re s1 = 'Testing string' s2 = '1234,12345$' regex = re.compile('[0-9,$]+$') if ( regex.match(s1) ): print "s1 matched" else: print "s1 didn't match" if ( regex.match(s2) ): print "s2 matched" else: print "s2 didn't match"
我的简单,简单,简单的方法!= D
Code
string_to_test = "The criminals stole $1,000,000 in jewels."
chars_to_check = ["$", ",", "0", "1", "2", "3", "4", "5", "6", "7", "8", "9"]
for char in chars_to_check:
if char in string_to_test:
print("Char \"" + char + "\" detected!")
输出
Char "$" detected!
Char "," detected!
Char "0" detected!
Char "1" detected!
s=input("Enter any character:")
if s.isalnum():
print("Alpha Numeric Character")
if s.isalpha():
print("Alphabet character")
if s.islower():
print("Lower case alphabet character")
else:
print("Upper case alphabet character")
else:
print("it is a digit")
elif s.isspace():
print("It is space character")
其他: print(“非空格特殊字符”)