我想使用Java中的XPath读取XML数据,因此对于我所收集的信息,我无法根据我的要求解析XML。

这就是我想做的:

从网上通过其URL获取XML文件,然后使用XPath来解析它,我想在其中创建两个方法。一种情况是,我输入一个特定的节点属性id,结果得到所有的子节点,另一种情况是,假设我只想得到一个特定的子节点值

<?xml version="1.0"?>
<howto>
  <topic name="Java">
      <url>http://www.rgagnonjavahowto.htm</url>
  <car>taxi</car>
  </topic>
  <topic name="PowerBuilder">
       <url>http://www.rgagnon/pbhowto.htm</url>
       <url>http://www.rgagnon/pbhowtonew.htm</url>
  </topic>
  <topic name="Javascript">
        <url>http://www.rgagnon/jshowto.htm</url>
  </topic>
 <topic name="VBScript">
       <url>http://www.rgagnon/vbshowto.htm</url>
 </topic>
 </howto>

在上面的例子中,我想读取所有的元素,如果我通过@name搜索,还有一个函数,我只是想从@name 'Javascript'的url只返回一个节点元素。


当前回答

下面是一个用vtd-xml处理xpath的例子…对于繁重的XML处理,它是首屈一指的。这是最近的一篇关于用Java处理XML -性能基准的论文

import com.ximpleware.*;

public class changeAttrVal {
    public  static  void main(String s[]) throws VTDException,java.io.UnsupportedEncodingException,java.io.IOException{
        VTDGen vg = new VTDGen();
        if (!vg.parseFile("input.xml", false))
            return;
        VTDNav vn = vg.getNav();
        AutoPilot ap = new AutoPilot(vn);
        XMLModifier xm = new XMLModifier(vn);
        ap.selectXPath("/*/place[@id=\"p14\" and   @initialMarking=\"2\"]/@initialMarking");
        int i=0;
        while((i=ap.evalXPath())!=-1){
            xm.updateToken(i+1, "499");// change initial marking from 2 to 499
        }
        xm.output("new.xml");
    }

}

其他回答

下面是一个用vtd-xml处理xpath的例子…对于繁重的XML处理,它是首屈一指的。这是最近的一篇关于用Java处理XML -性能基准的论文

import com.ximpleware.*;

public class changeAttrVal {
    public  static  void main(String s[]) throws VTDException,java.io.UnsupportedEncodingException,java.io.IOException{
        VTDGen vg = new VTDGen();
        if (!vg.parseFile("input.xml", false))
            return;
        VTDNav vn = vg.getNav();
        AutoPilot ap = new AutoPilot(vn);
        XMLModifier xm = new XMLModifier(vn);
        ap.selectXPath("/*/place[@id=\"p14\" and   @initialMarking=\"2\"]/@initialMarking");
        int i=0;
        while((i=ap.evalXPath())!=-1){
            xm.updateToken(i+1, "499");// change initial marking from 2 to 499
        }
        xm.output("new.xml");
    }

}

你需要这样的东西:

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse(<uri_as_string>);
XPathFactory xPathfactory = XPathFactory.newInstance();
XPath xpath = xPathfactory.newXPath();
XPathExpression expr = xpath.compile(<xpath_expression>);

然后调用express .evaluate(),传递在该代码中定义的文档和您期望的返回类型,并将结果转换为结果的对象类型。

如果您需要关于特定XPath表达式的帮助,您可能应该将其作为单独的问题提出(除非这是您首先要问的问题—我理解您的问题是如何在Java中使用API)。

编辑:(回复评论):这个XPath表达式将为您提供PowerBuilder下第一个URL元素的文本:

/howto/topic[@name='PowerBuilder']/url/text()

这将得到第二个:

/howto/topic[@name='PowerBuilder']/url[2]/text()

你可以通过下面的代码得到:

expr.evaluate(doc, XPathConstants.STRING);

如果你不知道给定节点中有多少url,那么你应该这样做:

XPathExpression expr = xpath.compile("/howto/topic[@name='PowerBuilder']/url");
NodeList nl = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);

然后循环遍历NodeList。

如果你有一个像下面这样的xml

<e:Envelope
    xmlns:d = "http://www.w3.org/2001/XMLSchema"
    xmlns:e = "http://schemas.xmlsoap.org/soap/envelope/"
    xmlns:wn0 = "http://systinet.com/xsd/SchemaTypes/"
    xmlns:i = "http://www.w3.org/2001/XMLSchema-instance">
    <e:Header>
        <Friends>
            <friend>
                <Name>Testabc</Name>
                <Age>12121</Age>
                <Phone>Testpqr</Phone>
            </friend>
        </Friends>
    </e:Header>
    <e:Body>
        <n0:ForAnsiHeaderOperResponse xmlns:n0 = "http://systinet.com/wsdl/com/magicsoftware/ibolt/localhost/ForAnsiHeader/ForAnsiHeaderImpl#ForAnsiHeaderOper?KExqYXZhL2xhbmcvU3RyaW5nOylMamF2YS9sYW5nL1N0cmluZzs=">
            <response i:type = "d:string">12--abc--pqr</response>
        </n0:ForAnsiHeaderOperResponse>
    </e:Body>
</e:Envelope>

并希望提取下面的XML

<e:Header>
   <Friends>
      <friend>
         <Name>Testabc</Name>
         <Age>12121</Age>
         <Phone>Testpqr</Phone>
      </friend>
   </Friends>
</e:Header>

下面的代码有助于实现同样的目标

public static void main(String[] args) {

    File fXmlFile = new File("C://Users//abhijitb//Desktop//Test.xml");
    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    Document document;
    Node result = null;
    try {
        document = dbf.newDocumentBuilder().parse(fXmlFile);
        XPath xPath = XPathFactory.newInstance().newXPath();
        String xpathStr = "//Envelope//Header";
        result = (Node) xPath.evaluate(xpathStr, document, XPathConstants.NODE);
        System.out.println(nodeToString(result));
    } catch (SAXException | IOException | ParserConfigurationException | XPathExpressionException
            | TransformerException e) {
        e.printStackTrace();
    }
}

private static String nodeToString(Node node) throws TransformerException {
    StringWriter buf = new StringWriter();
    Transformer xform = TransformerFactory.newInstance().newTransformer();
    xform.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
    xform.transform(new DOMSource(node), new StreamResult(buf));
    return (buf.toString());
}

现在,如果您只需要如下所示的xml

<Friends>
   <friend>
      <Name>Testabc</Name>
      <Age>12121</Age>
      <Phone>Testpqr</Phone>
   </friend>
</Friends>

你需要改变

String xpathStr = "//信封//头";to String xpathStr = "//信封//头/*";

在@bluish和@Yishai的精彩回答上展开,下面是如何使nodelist和节点属性支持迭代器,即for(node n: nodelist)接口。

像这样使用它:

NodeList nl = ...
for(Node n : XmlUtil.asList(nl))
{...}

and

Node n = ...
for(Node attr : XmlUtil.asList(n.getAttributes())
{...}

代码:

/**
 * Converts NodeList to an iterable construct.
 * From: https://stackoverflow.com/a/19591302/779521
 */
public final class XmlUtil {
    private XmlUtil() {}

    public static List<Node> asList(NodeList n) {
        return n.getLength() == 0 ? Collections.<Node>emptyList() : new NodeListWrapper(n);
    }

    static final class NodeListWrapper extends AbstractList<Node> implements RandomAccess {
        private final NodeList list;

        NodeListWrapper(NodeList l) {
            this.list = l;
        }

        public Node get(int index) {
            return this.list.item(index);
        }

        public int size() {
            return this.list.getLength();
        }
    }

    public static List<Node> asList(NamedNodeMap n) {
        return n.getLength() == 0 ? Collections.<Node>emptyList() : new NodeMapWrapper(n);
    }

    static final class NodeMapWrapper extends AbstractList<Node> implements RandomAccess {
        private final NamedNodeMap list;

        NodeMapWrapper(NamedNodeMap l) {
            this.list = l;
        }

        public Node get(int index) {
            return this.list.item(index);
        }

        public int size() {
            return this.list.getLength();
        }
    }
}

入门示例:

xml文件:

<inventory>
    <book year="2000">
        <title>Snow Crash</title>
        <author>Neal Stephenson</author>
        <publisher>Spectra</publisher>
        <isbn>0553380958</isbn>
        <price>14.95</price>
    </book>

    <book year="2005">
        <title>Burning Tower</title>
        <author>Larry Niven</author>
        <author>Jerry Pournelle</author>
        <publisher>Pocket</publisher>
        <isbn>0743416910</isbn>
        <price>5.99</price>
    </book>

    <book year="1995">
        <title>Zodiac</title>
        <author>Neal Stephenson</author>
        <publisher>Spectra</publisher>
        <isbn>0553573862</isbn>
        <price>7.50</price>
    </book>

    <!-- more books... -->

</inventory>

Java代码:

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;

import org.testng.annotations.DataProvider;
import org.testng.annotations.Test;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;


try {

    DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();
    DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();
    Document doc = docBuilder.parse (new File("c:\\tmp\\my.xml"));

    // normalize text representation
    doc.getDocumentElement().normalize();
    System.out.println ("Root element of the doc is " + doc.getDocumentElement().getNodeName());

    NodeList listOfBooks = doc.getElementsByTagName("book");
    int totalBooks = listOfBooks.getLength();
    System.out.println("Total no of books : " + totalBooks);

    for(int i=0; i<listOfBooks.getLength() ; i++) {

        Node firstBookNode = listOfBooks.item(i);
        if(firstBookNode.getNodeType() == Node.ELEMENT_NODE) {

            Element firstElement = (Element)firstBookNode;                              
            System.out.println("Year :"+firstElement.getAttribute("year"));

            //-------
            NodeList firstNameList = firstElement.getElementsByTagName("title");
            Element firstNameElement = (Element)firstNameList.item(0);

            NodeList textFNList = firstNameElement.getChildNodes();
            System.out.println("title : " + ((Node)textFNList.item(0)).getNodeValue().trim());
        }
    }//end of for loop with s var
} catch (SAXParseException err) {
    System.out.println ("** Parsing error" + ", line " + err.getLineNumber () + ", uri " + err.getSystemId ());
    System.out.println(" " + err.getMessage ());
} catch (SAXException e) {
    Exception x = e.getException ();
    ((x == null) ? e : x).printStackTrace ();
} catch (Throwable t) {
    t.printStackTrace ();
}