我正在寻找相同的，但找不到它，所以我在PHP中做了一个小脚本，你可以在: http://tequilaphp.wordpress.com/2010/07/05/searching-strings-in-a-database-and-files/

好运！ (我删除了一些私人代码，如果我没有在这个过程中破坏它，请告诉我:D)

当我们在Wordpress网站上更改域名时，我自己也在寻找这个。没有编程是做不到的，这就是我所做的。

<?php  
  header("Content-Type: text/plain");

  $host = "localhost";
  $username = "root";
  $password = "";
  $database = "mydatabase";
  $string_to_replace  = 'old.example.com';
  $new_string = 'new.example.com';

  // Connect to database server
  mysql_connect($host, $username, $password);

  // Select database
  mysql_select_db($database);

  // List all tables in database
  $sql = "SHOW TABLES FROM ".$database;
  $tables_result = mysql_query($sql);

  if (!$tables_result) {
    echo "Database error, could not list tables\nMySQL error: " . mysql_error();
    exit;
  }

  echo "In these fields '$string_to_replace' have been replaced with '$new_string'\n\n";
  while ($table = mysql_fetch_row($tables_result)) {
    echo "Table: {$table[0]}\n";
    $fields_result = mysql_query("SHOW COLUMNS FROM ".$table[0]);
    if (!$fields_result) {
      echo 'Could not run query: ' . mysql_error();
      exit;
    }
    if (mysql_num_rows($fields_result) > 0) {
      while ($field = mysql_fetch_assoc($fields_result)) {
        if (stripos($field['Type'], "VARCHAR") !== false || stripos($field['Type'], "TEXT") !== false) {
          echo "  ".$field['Field']."\n";
          $sql = "UPDATE ".$table[0]." SET ".$field['Field']." = replace(".$field['Field'].", '$string_to_replace', '$new_string')";
          mysql_query($sql);
        }
      }
      echo "\n";
    }
  }

  mysql_free_result($tables_result);  
?>

希望它能帮助任何在未来遇到这个问题的人:)

我不记得我在哪里遇到这个脚本，但我一直在使用它与XCloner移动我的WP多站点。

<?php

    // Setup the associative array for replacing the old string with new string
    $replace_array = array( 'FIND' => 'REPLACE', 'FIND' => 'REPLACE');

    $mysql_link = mysql_connect( 'localhost', 'USERNAME', 'PASSWORD' );
    if( ! $mysql_link) {
        die( 'Could not connect: ' . mysql_error() );
    }

    $mysql_db = mysql_select_db( 'DATABASE', $mysql_link );
    if(! $mysql_db ) {
        die( 'Can\'t select database: ' . mysql_error() );
    }

    // Traverse all tables
    $tables_query = 'SHOW TABLES';
    $tables_result = mysql_query( $tables_query );
    while( $tables_rows = mysql_fetch_row( $tables_result ) ) {
        foreach( $tables_rows as $table ) {

            // Traverse all columns
            $columns_query = 'SHOW COLUMNS FROM ' . $table;
            $columns_result = mysql_query( $columns_query );
            while( $columns_row = mysql_fetch_assoc( $columns_result ) ) {

                $column = $columns_row['Field'];
                $type = $columns_row['Type'];

                // Process only text-based columns
                if( strpos( $type, 'char' ) !== false || strpos( $type, 'text' ) !== false ) {
                    // Process all replacements for the specific column                    
                    foreach( $replace_array as $old_string => $new_string ) {
                        $replace_query = 'UPDATE ' . $table . 
                            ' SET ' .  $column . ' = REPLACE(' . $column . 
                            ', \'' . $old_string . '\', \'' . $new_string . '\')';
                        mysql_query( $replace_query );
                    }
                }
            }
        }
    }

    mysql_free_result( $columns_result );
    mysql_free_result( $tables_result );
    mysql_close( $mysql_link );

    echo 'Done!';

?>

我正在寻找相同的，但找不到它，所以我在PHP中做了一个小脚本，你可以在: http://tequilaphp.wordpress.com/2010/07/05/searching-strings-in-a-database-and-files/

好运！ (我删除了一些私人代码，如果我没有在这个过程中破坏它，请告诉我:D)

一个简单的解决方案是这样做的:

mysqldump -u myuser --no-create-info --extended-insert=FALSE databasename | grep -i "<search string>"

MikeW提出了一个有趣的解决方案，但正如评论中提到的，它是一个SQL Server解决方案而不是MySQL解决方案。下面是一个MySQL解决方案:

use information_schema;
set @q = 'Boston';
set @t = 'my_db';

select CONCAT('use \'',@q,'\';') as q UNION
select CONCAT('select \'', tbl.`TABLE_NAME`,'\' as TableName, \'', col.`COLUMN_NAME`,'\' as Col, `',col.`COLUMN_NAME`,'` as value  from `' , tbl.`TABLE_NAME`,'` where `' ,
        col.`COLUMN_NAME` , '` like \'%' ,@q,  '%\' UNION') AS q
from `tables` tbl
inner join `columns` col on tbl.`TABLE_NAME` = col.`TABLE_NAME`and col.DATA_TYPE='varchar'
where tbl.TABLE_SCHEMA  =  @t  ;